Hızlı yanıt: kod örneği
It is a template specialization. The typical case would be partial specialization:As you can see, the specialization removes one element from the template parameters and explicitly states a type instead of the removed one. That means if there is only one template type, the just become empty:
#include <iostream>template<class T1, class T2>struct foo{ void doStuff() { std::cout << "generic foo "; }};template<class T1>struct foo<T1, int>{ void doStuff() { std::cout << "specific foo with T2=int"; }};<>template<class T1>struct bar{ void doStuff() { std::cout << "generic bar"; }};template<>struct bar<int>{ void doStuff() { std::cout << "specific bar with T1=int"; }};