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Öğretmen, iki gündür rahatsız olduğunu belirterek dersine devam etmektedir.","Videoda parçalı fonksiyonların limitleri konusu detaylı olarak ele alınmaktadır. Öğretmen, kritik noktaların belirlenmesi, sol ve sağ limitlerin hesaplanması ve bunların eşit olması gerektiği konusunu örneklerle açıklamaktadır. Ders boyunca 44. sorudan 48. soruya kadar olan parçalı fonksiyon limit sorularının çözümü yapılmakta, ayrıca f(x) ve g(x) fonksiyonlarının limitleri, bileşke fonksiyonların limitleri ve mutlak değer fonksiyonlarının limitleri grafik üzerinden gösterilmektedir.","Öğretmen, limit hesaplamalarında dikkat edilmesi gereken noktaları ve hızlı çözüm yöntemlerini paylaşırken, öğrencilerin kendi başlarına çözmesi için alıştırmalar da sunmaktadır. Video, öğrencilere ilk beş testi başarıyla çözmeleri için motivasyon vererek sonlanmaktadır."]},"endTime":1366,"title":"Matematik Dersi: Parçalı Fonksiyonların Limitleri","beginTime":0}],"fullResult":[{"index":0,"title":"Giriş ve Geometri Kampı Duyurusu","list":{"type":"unordered","items":["Eğitmen, iki gündür rahatsız olduğunu ve geometri kitabını yetiştirmek için sabahlara kadar çalıştığını belirtiyor.","Yılbaşı itibariyle geometri kampına başlanacağı ve bunun için sabahlara kadar çalışıldığını açıklıyor."]},"beginTime":0,"endTime":47,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=0&ask_summarization=1"},{"index":1,"title":"Parçalı Fonksiyonların Limiti","list":{"type":"unordered","items":["Parçalı fonksiyonların limiti sınavda karşımıza gelebilecek, kolay ve zor olmayan bir konu olarak tanımlanıyor.","Parçalı fonksiyonların limiti için sağdan limit ve soldan limitin incelenip eşit olup olmadığı kontrol ediliyor.","Parçalı fonksiyonların limiti, süreklilik ve parçalı fonksiyonların türevi için önemli bir kısım olarak vurgulanıyor."]},"beginTime":47,"endTime":110,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=47&ask_summarization=1"},{"index":2,"title":"Parçalı Fonksiyonların Limit Hesaplama Yöntemi","list":{"type":"unordered","items":["Parçalı fonksiyonlar birden fazla parça ve aralıklara ayrılmış fonksiyonlardır.","Limit sorulduğunda, kritik noktada (parçalanış noktası) sağdan ve soldan limit hesaplanır.","Kritik noktada sağdan limit ve soldan limit eşitse limit vardır, eşit değilse limit yoktur."]},"beginTime":110,"endTime":342,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=110&ask_summarization=1"},{"index":3,"title":"Örnek 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belirtiliyor."]},"beginTime":429,"endTime":491,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=429&ask_summarization=1"},{"index":5,"title":"Örnek Problemin Çözümü","list":{"type":"unordered","items":["f(x) fonksiyonunun kritik noktası x=3 olarak belirleniyor.","f(3) değeri hesaplanırken, eşitlikte olduğu için uygun ifade kullanılarak 8 bulunuyor.","x=3 noktasında limiti inceleyince sağdan ve soldan limit de 8 olduğu için limit vardır ve değeri 8'dir."]},"beginTime":491,"endTime":609,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=491&ask_summarization=1"},{"index":6,"title":"Parçalı Fonksiyonların Limiti","list":{"type":"unordered","items":["Bir fonksiyonun kritik noktasında limitinin olması için sol limit ile sağ limitin birbirine eşit olması gerekir.","Parçalı fonksiyonlarda limit hesaplaması yapılırken, kritik noktada fonksiyonun değeri (f(x)) önemli değildir, sadece sol ve sağ limitler karşılaştırılır.","Limit sorularında, kritik noktada fonksiyonun değeri sadece süreklilik için kullanılır, limit hesaplamasında ilgilenecek değiliz."]},"beginTime":610,"endTime":705,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=610&ask_summarization=1"},{"index":7,"title":"Parçalı Fonksiyonlarda Limit Örnekleri","list":{"type":"unordered","items":["Bir fonksiyonun her yerde limitinin olması için, kritik noktaların sol ve sağ limitlerinin birbirine eşit olması gerekir.","Polinom fonksiyonlar her yerde limiti olan fonksiyonlardır, bu nedenle sadece kritik noktalara bakmak yeterlidir.","Bir fonksiyonda birden fazla kritik noktası varsa, her kritik noktada sol ve sağ limitlerin eşit olması gerekir."]},"beginTime":705,"endTime":952,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=705&ask_summarization=1"},{"index":8,"title":"Fonksiyon Değerleri ve Limitler","list":{"type":"unordered","items":["Fonksiyonların limitlerini hesaplamak için, kritik noktaların sol ve sağ limitlerini bulmak gerekir.","Fonksiyonların limitlerini hesaplamak için, x'in önündeki işareti inceleyerek hangi parçanın kullanılacağını belirleyebiliriz.","Kritik nokta olmayan noktalarda, hangi aralıkta olduğuna göre fonksiyonun ilgili parçasını kullanarak limit değeri bulunabilir."]},"beginTime":952,"endTime":1107,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=952&ask_summarization=1"},{"index":9,"title":"Grafikli Parçalı Fonksiyonlar","list":{"type":"unordered","items":["Grafikli parçalı fonksiyonlarda limit hesaplaması yapılırken, kritik noktaların sol ve sağ limitleri karşılaştırılır.","İki fonksiyonun toplamının limiti, her iki fonksiyonun kritik noktalarındaki limitlerinin toplamına eşittir."]},"beginTime":1107,"endTime":1158,"href":"/video/preview/1389943109375860163?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1107&ask_summarization=1"},{"index":10,"title":"Fonksiyonların Limitleri","list":{"type":"unordered","items":["f fonksiyonunun x=3 noktasındaki sağdan limiti 0 olarak bulunuyor.","g fonksiyonunun x=3 noktasındaki sağdan limiti 3 olarak bulunuyor ve bu değerle f fonksiyonunun limiti 6 oluyor.","f(x)+2g(x) fonksiyonunun x=3 noktasındaki sol limiti 4, sağ limiti 6 olarak bulunuyor, bu yüzden x=3 noktasında limiti 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Öğretmen, tahtada veya whiteboard üzerinde grafikler çizerek konuyu anlatmaktadır.","Videoda, mutlak değer fonksiyonlarının grafiklerinin nasıl çizileceği iki farklı yöntemle açıklanmaktadır: kısa yol olarak mutlak değer içeren fonksiyonların önce mutlak değer yok gibi çizilip, x ekseninin altında kalan kısımların katlanması yöntemi ve uzun yol olarak kritik noktaların bulunması ve parçalı fonksiyona dönüştürülmesi yöntemi. Öğretmen, bu yöntemleri çeşitli örneklerle pekiştirmekte ve AYT sınavında karşılaşılabilecek soru tiplerini ele almaktadır.","Video boyunca öğretmen, şıkları kullanarak soruların nasıl çözüleceğini göstermekte, kritik noktaları belirleme, parçalı fonksiyonlara dönüştürme ve grafik çizme adımlarını adım adım anlatmaktadır. 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Eğitmen, öğrencilere çeşitli matematik problemlerini adım adım çözerek anlatmaktadır.","Videoda toplam on iki farklı matematik problemi ele alınmaktadır. Problemler magnetler arasındaki uzaklık hesaplaması, kahve-süt karışımı oranları, katlı gökdelerdeki daire hesaplamaları, fonksiyonlar, basamak sayıları, bölünebilme kuralları, açıklık toplamı, öğrenci numaraları, binalardaki odalar, yayınevinin kitapları, hız-yol ilişkisi, yaş ortalamaları, \"bom oyunu\" ve rehberlik hizmeti gibi çeşitli konuları kapsamaktadır. Her problem için eğitmen detaylı çözüm adımları ve matematiksel hesaplamalar göstermektedir.","Video, ÖSYM sınavlarında çıkabilecek türdeki problemleri içermekte ve sınav hazırlığı yapan öğrenciler için faydalı problem çözme stratejileri sunmaktadır. Çözümlerde denklemler kurma, oran-orantı yöntemleri, kombinasyon ve olasılık kavramları gibi farklı matematiksel yaklaşımlar kullanılmaktadır."]},"endTime":3581,"title":"Matematik Problemleri Çözüm Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"Kırmızı ve Mavi Magnetler Problemi","list":{"type":"unordered","items":["Kırmızı magnetler üç'er birim aralıklarla konulmuş ve magnetlerin boyu önemsiz kabul edilmiş.","Kırmızı magnetlerin toplam uzaklığı 31 birim olarak verilmiş ve hesaplamalar sonucunda a=7 bulunmuştur.","Mavi magnetlerin arası 4 birim olarak verilmiş ve hesaplamalar sonucunda x=5 bulunmuştur."]},"beginTime":1,"endTime":97,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1&ask_summarization=1"},{"index":1,"title":"Kahve ve Süt Problemi","list":{"type":"unordered","items":["Mavi kesir 1/3, yeşil kesir 1/6, gri kesir 1/12 olarak verilmiş.","Üç fincan kahve bir kupada karıştırıldığında, süt miktarı tüm kahve hacminin 7/36'ı olmuştur."]},"beginTime":97,"endTime":160,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=97&ask_summarization=1"},{"index":2,"title":"Gökdelen Problemi","list":{"type":"unordered","items":["Katlı bir gökdelende her katında 8 daire, her dairede 7 oda ve her odanın alanı 12 metrekare olarak verilmiş.","20 katlı gökdelenin toplam alanı hesaplanmıştır.","Metrekare başına 132 lira ödenildiğine göre toplam maliyet hesaplanmıştır."]},"beginTime":160,"endTime":194,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=160&ask_summarization=1"},{"index":3,"title":"Faktöriyel Problemi","list":{"type":"unordered","items":["132×11×2×7×8 faktöriyel sorusu çözülmüştür.","Çözümde faktöriyel ifadesi sadeleştirilerek 2×3×4×5×6×7×8×9×10×11×12×13×14×15×16×17×18×19×20×21×22×23×24×25×26×27×28×29×30×31×32×33×34×35×36×37×38×39×40×41×42×43×44×45×46×47×48×49×50×51×52×53×54×55×56×57×58×59×60×61×62×63×64×65×66×67×68×69×70×71×72×73×74×75×76×77×78×79×80×81×82×83×84×85×86×87×88×89×90×91×92×93×94×95×96×97×98×99×100×101×102×103×104×105×106×107×108×109×110×111×112×113×114×115×116×117×118×119×120×121×122×123×124×125×126×127×128×129×130×131×132×133×134×135×136×137×138×139×140×141×142×143×144×145×146×147×148×149×150×151×152×153×154×155×156×157×158×159×160×161×162×163×164×165×166×167×168×169×170×171×172×173×174×175×176×177×178×179×180×181×182×183×184×185×186×187×188×189×190×191×192×193×194×195×196×197×198×199×200×201×202×203×204×205×206×207×208×209×210×211×212×213×214×215×216×217×218×219×220×221×222×223×224×225×226×227×228×229×230×231×232×233×234×235×236×237×238×239×240×241×242×243×244×245×246×247×248×249×250×251×252×253×254×255×256×257×258×259×260×261×262×263×264×265×266×267×268×269×270×271×272×273×274×275×276×277×278×279×280×281×282×283×284×285×286×287×288×289×290×291×292×293×294×295×296×297×298×299×300×301×302×303×304×305×306×307×308×309×310×311×312×313×314×315×316×317×318×319×320×321×322×323×324×325×326×327×328×329×330×331×332×333×334×335×336×337×338×339×340×341×342×343×344×345×346×347×348×349×350×351×352×353×354×355×356×357×358×359×360×361×362×363×364×365×366×367×368×369×370×371×372×373×374×375×376×377×378×379×380×381×382×383×384×385×386×387×388×389×390×391×392×393×394×395×396×397×398×399×400×401×402×403×404×405×406×407×408×409×410×411×412×413×414×415×416×417×418×419×420×421×422×423×424×425×426×427×428×429×430×431×432×433×434×435×436×4"]},"beginTime":194,"endTime":488,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=194&ask_summarization=1"},{"index":4,"title":"Sayı Doğrusu Problemi","list":{"type":"unordered","items":["x negatif, y pozitif ve z pozitif olduğunda, x artı z pozitif olur çünkü sayı doğrusunda z, x'ten sağda yer alır.","y artı z negatif olma durumu örnekle çürütmüştür, bu nedenle bu ifade doğrulanamaz.","z eksi x negatif olma durumu da örnekle çürütmüştür, bu nedenle doğru cevap sadece birinci ifadedir."]},"beginTime":495,"endTime":656,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=495&ask_summarization=1"},{"index":5,"title":"Üslü Sayı Problemi","list":{"type":"unordered","items":["6 üzeri a çarpı 3 üzeri b ifadesi tek sayı olduğunda, a'nın çift sayı olması gerekir çünkü 3'ün pozitif üstlerinde daima tek sayı gelir.","b'nin çift mi tek mi olduğu belirsizdir, çünkü 5 üzeri 0 (1) ve 5 üzeri 2 (25) de tek sayıdır.","a çarpı b çarpımı kesinlikle çift sayıdır çünkü a çift sayıdır ve herhangi bir tam sayının çarpımı çift sayıdır."]},"beginTime":656,"endTime":745,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=656&ask_summarization=1"},{"index":6,"title":"Mutlak Değer Problemi","list":{"type":"unordered","items":["|x+y| = x+y olduğunda, x sıfırdan büyük olmalıdır çünkü mutlak değer içinden çıkarken işaret değişmemiştir.","|y-z| = y-z olduğunda, y-z pozitif olmalıdır çünkü mutlak değer içinden çıkarken işaret değişmemiştir.","|y+z| = y+z olduğunda, y+z pozitif olmalıdır çünkü mutlak değer içinden çıkarken işaret değişmemiştir."]},"beginTime":745,"endTime":814,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=745&ask_summarization=1"},{"index":7,"title":"Tuş Problemi","list":{"type":"unordered","items":["Beş kişi (Ali, Berke, Cihan, Diyâr, Ezgi) tuşlara dokunarak kapalıyken açıyor, açıkken kapatıyor.","Ali ve Berke aynı tuşlara (1 ve 2) dokunuyor, diğerleri farklı tuşlara dokunuyor.","Her tuşa tek sayıda dokunulduğunda açılır, çift sayıda dokunulduğunda kapanır.","Sonuçta 5 tuş açık kalmıştır çünkü sadece 5 farklı tuşa bir kez dokunulmuştur."]},"beginTime":814,"endTime":961,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=814&ask_summarization=1"},{"index":8,"title":"Dişli Problemi","list":{"type":"unordered","items":["X dişli saat yönünde dönerse, diğer dişliler zıt yönde döner.","X dişli saat yönünün tersine dönerse, diğer dişliler aynı yönde döner.","P ise R önermesi doğru çünkü X dişli saat yönünde dönerse Z dişli de saat yönünde döner."]},"beginTime":961,"endTime":1107,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=961&ask_summarization=1"},{"index":9,"title":"Fonksiyon Problemi Çözümü","list":{"type":"unordered","items":["f(x) = 3x - 2 fonksiyonunda f(1) = 5 sabit bir sayıdır, f(1), f(2) gibi ifadeler bilinmeyen sabit sayılar olarak düşünülmelidir.","f(x) = mx + n ve g(x) = ax + b şeklindeki fonksiyonlarda, g(1) = n + b ve b = 0 olduğu tespit edilmiştir.","f(2) = 2b + n - 2 = 2 olduğundan, n = 2 ve f(x) sabit fonksiyon olduğu bulunmuştur."]},"beginTime":1112,"endTime":1246,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1112&ask_summarization=1"},{"index":10,"title":"Bileşke Fonksiyon Hesaplama","list":{"type":"unordered","items":["f(g(x)) = f(2) / g(4) = 2 / 8 = 1/2 olarak hesaplanmıştır.","f(1/4) = 2 ve g(1/4) = 1/2 olduğundan, f(1/4) × g(1/4) = 1 olarak bulunmuştur.","Grafikte g fonksiyonunun üç noktada eşit değer aldığı ve bu noktaların f fonksiyonunda farklı değerler verdiği görülmüştür."]},"beginTime":1246,"endTime":1377,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1246&ask_summarization=1"},{"index":11,"title":"Bölme Problemi Çözümü","list":{"type":"unordered","items":["Bir dizinin yarısı bitmiş, toplam bölüm sayısı 6a olarak hesaplanmıştır.","10b + 2a + 10 = 6a denkleminden 10b + 10 = 4a bulunmuştur.","a = 8 ve b = 2 olarak tespit edilmiştir."]},"beginTime":1377,"endTime":1476,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1377&ask_summarization=1"},{"index":12,"title":"Bölme Bölünebilme Problemi","list":{"type":"unordered","items":["Bir dizide 1'den başlayıp her beşinci terim seçildiğinde, beş ile bölümünden kalan 1 olan sayılar elde edilir.","Dizideki terimler beş ile bölümünden kalan 1, 2, 3, 4 ve tam bölünen sayılar olarak gruplandırılmıştır.","Yeşil renk beş ile bölümünden kalan 3 olan sayıları, siyah renk beş ile bölümünden kalan 4 olan sayıları temsil etmektedir.","Farkın mutlak değeri kırmızı renkte olacaktır çünkü 3 + 4 = 7 ve 7 beş ile bölümünden kalan 2'dir."]},"beginTime":1476,"endTime":1604,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1476&ask_summarization=1"},{"index":13,"title":"Ortanca Açıklık Toplamı Problemi","list":{"type":"unordered","items":["Ortanca açıklık toplamı, veri grubundaki sayıların en büyük verinin diğer verilerle farkının mutlak değerinin toplamıdır.","Veri grubu 10, 10, 14, 18, 18, A şeklindedir ve ortanca değeri 16'dır.","Açıklık toplamının yarısı medyana eşit olduğundan, 5A-70=16 denklemi çözülerek A=24,4 bulunur."]},"beginTime":1611,"endTime":1690,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1611&ask_summarization=1"},{"index":14,"title":"Öğrenci Numarası Problemi","list":{"type":"unordered","items":["Tekle başlayan 18 öğrenci, çiftle biten 18 öğrenci ve başladığı sayı çeşidinin aynısı ile biten 6 öğrenci vardır.","Tablo yöntemi kullanılarak problem çözülmüş ve tek sayı ile başlayıp çift sayı ile biten 15 numara olduğu bulunmuştur."]},"beginTime":1690,"endTime":1831,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=1690&ask_summarization=1"},{"index":15,"title":"Depo Doldurma Problemi","list":{"type":"unordered","items":["Hızlı mod %40'a kadar, normal mod %40-80 arası, 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eşittir."]},"beginTime":2001,"endTime":2090,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=2001&ask_summarization=1"},{"index":17,"title":"Oda Sayısı Problemi","list":{"type":"unordered","items":["Soruda boş oda sayısı, beşer odası dolu olan binalardaki toplam oda sayısına eşit olarak belirtilmiştir.","İki oda dolu binada 3x boş oda, üç oda dolu binada 2x boş oda bulunmaktadır.","Toplam 15x dolu oda sayısı, binadaki toplam boş oda sayısına eşittir ve sonuç olarak 150 odaya yerleşmiştir."]},"beginTime":2093,"endTime":2202,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=2093&ask_summarization=1"},{"index":18,"title":"Kitap Paketleme Problemi","list":{"type":"unordered","items":["Bir yayınevinin kitapları beş'er, sekiz'er ve on ikişer olarak paketlenmiştir.","Sekiz ve on iki kitap bulunan paketlerin sayısı tüm paketlerin %60'ıdır, beş ve sekiz kitap bulunan paketlerin sayısı tüm paketlerin %80'indedir.","On iki'li paketlerin sayısı 600 olduğuna göre, sekiz'li paketlerdeki kitap sayısı 1920'dir."]},"beginTime":2202,"endTime":2331,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=2202&ask_summarization=1"},{"index":19,"title":"Mesafe Problemi","list":{"type":"unordered","items":["Bir noktadan 140 santim ileride durulduğunda, B noktasına olan mesafe A noktasına olan mesafenin dört katı olmaktadır.","Aynı noktadan 80 santim geride durulduğunda, B noktasına olan mesafe A noktasına olan mesafenin beş katı olmaktadır.","A noktasına olan mesafe 1180 santimetre olarak bulunmuştur."]},"beginTime":2331,"endTime":2458,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=2331&ask_summarization=1"},{"index":20,"title":"Matematik Problemleri Çözümü","list":{"type":"unordered","items":["Bir matematik problemi çözülürken, sayılarla işlemler yapılıyor: 4720 + 700 = 5420, 5420 + 1180 = 6600.","Bir diğer problemde, farklı renkli araçların hızları ve yolları verilmiş, oranlar kullanılarak çözüm bulunuyor.","Yeşil yolu kullanan araç ile siyah yolu kullanan aracın zaman farkı 64 dakika olarak hesaplanıyor."]},"beginTime":2462,"endTime":2588,"href":"/video/preview/15117385926618034991?parent-reqid=1769485664591459-3905276406807023275-balancer-l7leveler-kubr-yp-vla-220-BAL&text=Hill+Math+-+Topics&t=2462&ask_summarization=1"},{"index":21,"title":"Sınıf Öğrencileri Problemi","list":{"type":"unordered","items":["Dokuzuncu ve onuncu sınıfların öğrencilerinin oranı 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