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merhabalar, bu videomda sizlere zayıf asit ve bazlar için iyonlaşma sabitlerinin yazılmasını gösterdim. Videolarimi Beğenmeyi,Yorum Yazmayi VE Paylaşmayi Unutmayin.","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/3046333/6a216d6f90fb00b4a496e0e1f2808c5b/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/NiLcZwAAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"3","reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=videoid:6408038447166097143","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitim dersi formatında olup, bir öğretmen tarafından zayıf asit ve bazların iyonlaşma sabiti konusu anlatılmaktadır.","Videoda zayıf asitlerin (Ka) ve bazların (Kb) iyonlaşma sabitlerinin nasıl hesaplanacağı, denge ifadelerinin nasıl yazılacağı açıklanmaktadır. Öğretmen, asetik asit ve amonyak gibi zayıf asitlerin ve bazların reaksiyonlarını örnek olarak vererek Ka ve Kb değerlerini hesaplamayı göstermektedir. Ayrıca konjuge asit-baz çiftleri için Ka × Kb = Ks (suyun iyonlaşma sabiti) formülünün nasıl elde edildiği ve bu formülün soru çözümlerinde nasıl kullanılabileceği anlatılmaktadır."]},"endTime":418,"title":"Zayıf Asit ve Bazların İyonlaşma Sabiti Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"Zayıf Asit ve Bazların İyonlaşma Sabitleri","list":{"type":"unordered","items":["Zayıf asitler ve bazlar kısmen iyonlaştıkları için iyonlaşma sabitleri (Ka ve Kb) kullanılır.","Asetik asit suyla reaksiyona girdiğinde asetat ve hidronyum iyonu oluşur ve bu tepkime bir denge tepkimesi olur.","Suyu iyonlaşma sabiti (Ka) ifadesinde ihmal edilir çünkü suyun iyonlaşma derişimi (5,5 M) tepkime süresince sabit kalır."]},"beginTime":15,"endTime":89,"href":"/video/preview/6408038447166097143?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=15&ask_summarization=1"},{"index":1,"title":"İyonlaşma Sabitlerinin Hesaplanması","list":{"type":"unordered","items":["Amonyak zayıf bir bazdır ve suyla reaksiyona girdiğinde amonyum hidroksit oluşur.","Kuvvetli asit ve bazlar (örneğin hidroklorik asit) suda yüzde yüz iyonlaşabildiği için iyonlaşma sabitleri kullanılmaz.","Zayıf asit ve bazlarda iyonlaşma sabitlerini ve denge ifadelerini yazmak gerekir."]},"beginTime":89,"endTime":147,"href":"/video/preview/6408038447166097143?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=89&ask_summarization=1"},{"index":2,"title":"Konjuge Asit-Baz Çiftleri İçin İyonlaşma Sabitleri","list":{"type":"unordered","items":["Konjuge asit-baz çifti için iyonlaşma sabitleri, bir asitin konjuge bazıyla reaksiyonu sırasında oluşur.","Formik asit suyla reaksiyona girdiğinde format iyonu ve hidronyum iyonu oluşur.","Ka ve Kb değerleri çarpıldığında, formik asit ve format iyonu derişimleri birbirini götürür ve geriye hidronyum iyonu derişimi ve hidroksit iyonu derişimi kalır."]},"beginTime":147,"endTime":230,"href":"/video/preview/6408038447166097143?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=147&ask_summarization=1"},{"index":3,"title":"Ksuyun İlişkisi","list":{"type":"unordered","items":["Hidronyum iyonu derişimi ve hidroksit iyonu derişiminin çarpımı Ksuya eşittir.","Tüm konjuge asit-baz çiftleri için Ka × Kb = Ksuya formülü geçerlidir.","Ksuya değeri 1 × 10^-14'tür ve sorularda genellikle Ka veya Kb değerleri verilir."]},"beginTime":230,"endTime":353,"href":"/video/preview/6408038447166097143?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=230&ask_summarization=1"},{"index":4,"title":"Sonuç","list":{"type":"unordered","items":["Zayıf asitlerde ve bazlarda iyonlaşma sabitleri denge ifadeleriyle yazılır.","Ksuya = Ka × Kb formülü, soruların çözümünde kolaylık sağlar.","Diğer videolarda örnek soru çözümleri yapılacaktır."]},"beginTime":353,"endTime":399,"href":"/video/preview/6408038447166097143?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=353&ask_summarization=1"}],"linkTemplate":"/video/preview/6408038447166097143?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Ka ve kb nasıl bulunur ? 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fazlası için: http://www.khanacademy.org.tr Matematikten sanat tarihine, ekonomiden fen bilimlerine, basit toplamadan diferansiyel denklemlere, ilkokul seviyesinden üniversite seviyesine...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4448258/23d4c084528b2777ac5be465a5237553/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/G9BAZAAAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"5","reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=videoid:1012279319550039620","teaser":[{"list":{"type":"unordered","items":["Bu video, kimya dersi formatında bir eğitim içeriğidir. Bir öğretmen, eşlenik asit-baz çiftleri ve denge sabitleri konusunu anlatmaktadır.","Video, NH₄⁺ ve NH₃ arasındaki eşlenik asit-baz çiftini inceleyerek başlıyor ve suyun iyonlaşma tepkimesi üzerinden Kₐ ve Kb arasındaki ilişkiyi açıklıyor. Ardından kuvvetli asitlerin eşlenik bazlarının zayıf olması gibi temel kavramları matematiksel olarak gösteriyor. Son bölümde ise metilamin örneği üzerinden Kₐ, Kb, pKa ve pKb arasındaki ilişkileri hesaplamalar yaparak pekiştiriyor. Video, kimya dersinde denge sabitleri konusunu anlamak isteyenler için faydalı bir kaynak niteliğindedir."]},"endTime":609,"title":"Kimya Dersi: Eşlenik Asit-Baz Çiftleri ve Denge Sabitleri","beginTime":0}],"fullResult":[{"index":0,"title":"NH4+ ve NH3 Eşlenik Aşit-Baz Çifti","list":{"type":"unordered","items":["NH4+ ve NH3 bir eşlenik aşit-baz çiftidir.","NH4+ bir proton kaybettiğinde NH3'ü oluşturur ve bu tepkimenin Ka değeri 5,60 × 10^-10'dur.","NH3 suyun bir protonunu alarak NH4+ oluşturur ve bu tepkimenin Kb değeri 1,80 × 10^-5'tir."]},"beginTime":4,"endTime":54,"href":"/video/preview/1012279319550039620?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=4&ask_summarization=1"},{"index":1,"title":"Su İyonlaşma Tepkimesi","list":{"type":"unordered","items":["İki tepkimeyi birleştirince suyun iyonlaşma tepkimesi elde edilir: 2H2O → H3O+ + OH-.","Suyun iyonlaşma sabiti Kw 1 × 10^-14'e eşittir.","Eşlenik aşit-baz çifti için Ka × Kb = Kw bağıntısı geçerlidir."]},"beginTime":54,"endTime":211,"href":"/video/preview/1012279319550039620?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=54&ask_summarization=1"},{"index":2,"title":"Denge Sabitleri ve İlişkileri","list":{"type":"unordered","items":["Ka = [H3O+][NH3]/[NH4+] formülüyle hesaplanır.","Kb = [NH4+][OH-]/[NH3] formülüyle hesaplanır.","Ka ve Kb değerlerini kullanarak Kw değeri hesaplanabilir."]},"beginTime":211,"endTime":295,"href":"/video/preview/1012279319550039620?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=211&ask_summarization=1"},{"index":3,"title":"Kuvvetli ve Zayıf Aşitler","list":{"type":"unordered","items":["HCl kuvvetli bir aşit olduğunda, eşlenik bazı (Cl-) oldukça zayıftır.","Kuvvetli bir aşit olduğunda Ka değeri çok yüksek, eşlenik bazın Kb değeri çok düşük olur.","Aşit ne kadar kuvvetli olursa, eşlenik bazı o kadar zayıftır."]},"beginTime":295,"endTime":376,"href":"/video/preview/1012279319550039620?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=295&ask_summarization=1"},{"index":4,"title":"Problem Çözümü ve pKa-pKb İlişkisi","list":{"type":"unordered","items":["Metilaminin Kb değeri 3,70 × 10^-4 olduğunda, metilamonyum iyonunun Ka değeri 2,70 × 10^-11 olarak hesaplanır.","pKa + pKb = 14 bağıntısı geçerlidir.","pKa = -log(Ka) ve pKb = -log(Kb) formülleriyle pKa ve pKb değerleri 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Merhabalar. Sizlere BU Videomda Zayif ASİT VE BAZ İyonlaşma Saibtlerini Anlattim. pKa pKb nasıl bulunuru anlattım. Sinavlara Hazirlanan Herkese Başarilar Dilerim.","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4000334/63891ac892360cb8d2dbcc6e04a4ec7a/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/BtOUDQEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"7","reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","summary":{"fullTextUrl":"/int_search_summary?data=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DJvrbV2tqvEs","linkTemplate":"/video/preview/1790724283001857459?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Ka, Kb, pKa, pKb İlişkisi Nedir ?","related_orig_text":"KB SOLUTION","related_porno":false,"related_less_3m_off":true,"client":"d2d","no_cnt":1,"related_src":"serp","related":"{\"porno\":false,\"vfp\":1,\"orig_text\":\"KB SOLUTION\",\"url\":\"http:\\/\\/www.youtube.com\\/watch?v=JvrbV2tqvEs\",\"src\":\"serp\",\"rvb\":\"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--gj8BAD89__5_QIAAf0I-P34_v0A-QUL-gMD_wDtBAjzAAAAAPb2AAYGAAAA9gf4EP7_AAAPCgwA9QAAAADyAAH5AAAA8QoFAf8BAAD9EfIAAv8AAAf8-woAAAAAAAn6CAAAAAAJ-_D2AQAAAPLrAwEAAAAAIAAtdR3gOzgTQAlITlACKoQCEAAa8AFkAur_4PfqAeQVvwHZERUBxzAMAAv72ACxEhMBgQvJ_u4X4AD477P_DOAX_-MaG_8S27kC3cYNACr88f8M-yD_8gMWACi-9QE6AP0A8fPs_tYWAf709QsA9d24AAgL0_4d8RL8AP_sAAAG4gMJ1zsDHu0kAgwDFQHk3hL91hQCAc_ezvv_IBP69coDAeL2LQf13RX_6_4I-c8GBP379eb9BvL8-QMMAvf15fD-7OQG_A327ffw9en4BAcq_9ACCPzz9yQC7uPy-fQD-f5E8v78zv76_hPh-glDGgT8BOj3-v8H9vDW9QgI3fgA_u_4_A0gAC27Nx07OBNACUhhUAIqcxAAGmAb-AAUDBcP2NwJ9zEoMhjopsMB-7wX_-v0__s2x_QOE9a9-Tr_WPcV96EAAAA__NRLFQAaf8Ue3uvS6xrW8dgGLnveFzK2oB3x2s0GBPT1MgsKLWcA5t-YDz_hwxxOKgcgAC3d1xM7OBNACUhvUAIqrwYQDBqgBgAAKEIAAPDBAADQQQAAQEEAAEDCAABgQQAAQEAAAFDBAABgwgAAwEAAAKjBAABwwQAA-MEAADjCAAD4QQAAIMEAAMBBAACIwgAAQEEAAKDBAADQwQAA4MAAAGBBAACAvwAAyMEAAJJCAABswgAAMEIAAIZCAACIQQAAEMEAAIDAAACMwgAAJMIAAKDBAAAwQgAAIEIAAOpCAAAwwgAAwEEAAFBBAADAQQAAVEIAAIC_AAAgwQAAXEIAAABBAAA0QgAAAMAAAJhBAAA8wgAAIEEAAADCAAAAQAAAQMAAAJBBAABwwQAAoEAAALhBAABEQgAACMIAAJDCAACowQAAtsIAAJrCAAAgQQAA-EEAAJhBAABIwgAAQEAAAEhCAAB0QgAABMIAABxCAABgQQAAfMIAADDCAACowQAAjEIAADBBAADgwQAAkEEAAPDBAAAQQQAAQMEAAIjBAADgQQAAYMEAALjBAAAIwgAAeMIAAGRCAAAgwgAAxMIAAABAAAAAwQAARMIAAOhBAABYQgAAuMEAAEzCAACAvwAAOEIAAGDCAAAYwgAAqEEAAETCAACCQgAAgD8AAOjBAAC4QQAAqEEAAJhBAACgwQAAQEAAANDBAADgwAAAlMIAABBCAACIwQAAgMIAALjBAAD4QQAAwMEAAMBAAABAwAAAuMEAAEzCAADowQAAgsIAAKBBAAAgQgAAEEEAAJxCAADwQQAAGEIAAIA_AACwwQAAgEEAAKjCAAAAwgAAlkIAAMDBAAAAAAAAwMAAAKBBAAAkwgAAgkIAAMDBAACAPwAAAEAAAIBBAAA0QgAAEMEAAKBAAAAgQgAAgEAAAMTCAABwwQAA-EEAAEDAAABQwQAARMIAAIBBAAD4wQAAEEIAAIhBAACAvwAAAMEAAHBBAABIwgAAwMEAAJBBAACYwQAAwMAAANBBAACEwgAAHMIAAAhCAACYQgAA-MIAAKjBAAAMQgAAUMIAAKpCAABYwgAAmsIAAExCAAAAwAAABEIAADhCAAC4wQAA2EEAAODAAAAgwgAAykIAACTCAADwQQAAUMIAABTCIAA4E0AJSHVQASqPAhAAGoACAAD-vgAABL4AADC9AADgvAAAQDwAAAQ-AADoPQAA-r4AACQ-AACYPQAAHD4AAIA7AADgPAAAcD0AAMi9AADoPQAAgDsAADC9AACCPgAALD4AAH8_AABEvgAAmL0AAFA9AAAwvQAAHL4AAJa-AAAMPgAAdL4AACw-AACYPQAAHD4AAAy-AAAMvgAAZL4AAAy-AACYPQAArr4AANK-AAB0PgAAJD4AAFS-AAAwPQAA2D0AAIY-AACSvgAAgLsAAKi9AABkvgAAxr4AAIg9AACAOwAAyj4AADC9AAAEvgAA-D0AAAk_AACCPgAAuD0AAEw-AADgvAAA2L0AAIK-AAAwvSAAOBNACUh8UAEqjwIQARqAAgAAoDwAAHA9AADovQAAf78AAJi9AAAMPgAAhj4AAHA9AADIPQAAXL4AALi9AABMvgAAFL4AABe_AAAQvQAA6D0AABA9AADGPgAAXL4AADy-AABUvgAARD4AAPg9AACaPgAAyr4AAOI-AADyvgAAiD0AAKC8AADmvgAALD4AAMg9AADgvAAAcL0AAK6-AAB0PgAAET8AANi9AACSvgAArr4AAIC7AACKPgAAgr4AAII-AAAwPQAA2D0AAHW_AACoPQAAVD4AAJ4-AAA0PgAAuL0AAM4-AAB8PgAAJL4AAPg9AACgvAAAJL4AAEC8AAC6vgAA6D0AAJg9AABMvgAA2D0gADgTQAlIfFABMAk4AUoAYABoAA,,\"}","related_url":"http://www.youtube.com/watch?v=JvrbV2tqvEs","parent-reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","related_vfp":1,"relatedVideo":"yes"},"cwidth":1280,"cheight":720,"cratio":1.77777,"dups":["1790724283001857459"],"episode":0,"season":0,"isEmbedOnly":false,"greenHost":"YouTube","hasTranslation":true,"contentTypeId":null,"censored":false},"5392467934409177715":{"videoId":"5392467934409177715","docid":"34-4-3-ZD5C21696ADA03226","description":"pH of weak acids and bases 1. Calculate the pH of a 0.020 M carbonic acid solution, H2co3(aq), that has the stepwise dissociation constants Ka1 = 4.3e-7 and Ka2 = 5.6e-11 2. Calculate the pH of...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4114567/8dcd5f79fe61f6e1b712a0d46d88f1fa/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/XYcRaAEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"8","reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","summary":{"fullTextUrl":"/int_search_summary?data=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DdrrcszcFsko","linkTemplate":"/video/preview/5392467934409177715?parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=KB+SOLUTION&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"How to find the pH of weak acids and bases using Ka and Kb.","related_orig_text":"KB SOLUTION","related_porno":false,"related_less_3m_off":true,"client":"d2d","no_cnt":1,"related_src":"serp","related":"{\"porno\":false,\"vfp\":1,\"orig_text\":\"KB SOLUTION\",\"url\":\"http:\\/\\/www.youtube.com\\/watch?v=drrcszcFsko\",\"src\":\"serp\",\"rvb\":\"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_E9gIggQkAYAEKyqLARABGniBAf36BQAAAPMEBQH5BP8BEAgDC_YBAQAFA_oEBwT-AP8CBvn_AQAA7-73BQMAAAD3-PcEAv8AAAwN-wIFAAAAEwAFBPwAAAAL__v4_wEAAAkRAv4D_wAADv7--P8AAAAEE_QI_gAAAAwI-PwBAAAA_-4D-AAAAAAgAC0sYNU7OBNACUhOUAIqcxAAGmD1IAAbESLizQAY3ALo5f38_OAIwdQQABTjAP324uvoItGuCAT_D-QS8r0AAAAICN0aNADqUxHUvNr7FOjt_t33AX8EC9rr4AnW9xgR9isLAez2O_QA5-gZFwrR_jEULg0gAC2tlE87OBNACUhvUAIqjwIQABqAAgAA2L0AAPg9AAC6PgAA2L0AAAw-AAA0PgAA-L0AAAW_AAAsvgAA4DwAAKi9AADovQAA4LwAAIg9AAA8vgAAoDwAAHA9AABQPQAAmD0AACQ-AAB_PwAA4LwAAIA7AADYPQAA-L0AAJi9AABAPAAAoDwAAHA9AAAkPgAAED0AAKi9AAAwvQAAyL0AAFA9AABAPAAA2D0AAJa-AABcvgAANL4AAHC9AADgPAAAgLsAAKC8AACIvQAA2L0AAHA9AACAuwAAyL0AADS-AADYPQAAUD0AACw-AABkPgAA2L0AAOC8AACyPgAAND4AAHC9AAAEPgAAQLwAAJg9AAD4PQAAUL0gADgTQAlIfFABKo8CEAEagAIAACS-AAD4vQAAyD0AADW_AAA8vgAA4DwAAJg9AADWPgAAMD0AALg9AACKvgAA4LwAAMg9AAA8vgAAiD0AAOC8AABAPAAAAT8AAIi9AACaPgAAor4AAJg9AAAUvgAAqD0AABA9AABwPQAAPD4AAFA9AADovQAAgDsAAFC9AAAEPgAA-L0AAHA9AABwPQAAmL0AABE_AAAcPgAAir4AAGQ-AABsvgAAyL0AAJ6-AACaPgAAUD0AAAG_AAB_vwAAJD4AAPq-AAB8PgAA-L0AAKg9AACKPgAALD4AABC9AACoPQAA4LwAADA9AAAQvQAAJL4AAIY-AACePgAAQDwAABS-IAA4E0AJSHxQATAJOAFKAGAAaAA,\"}","related_url":"http://www.youtube.com/watch?v=drrcszcFsko","parent-reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","related_vfp":1,"relatedVideo":"yes"},"cwidth":640,"cheight":360,"cratio":1.77777,"dups":["5392467934409177715"],"episode":0,"season":0,"isEmbedOnly":false,"greenHost":"YouTube","hasTranslation":true,"contentTypeId":null,"censored":false,"videoContentId":"2025525460"},"4302885981323250754":{"videoId":"4302885981323250754","docid":"34-9-16-Z497C7EC676B03351","description":"Kobb kb100 modeli 12 v 100 psi 7 bar lastik kompresör cihazı kutu açılımı ve kolay kullanım kılavuzu araç üzerinde test edilmesi.","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4119710/08c55504c67667fbeefb5f2c25b7f94b/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/_gXxRQIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"9","reqid":"1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769618062668330-13909078358963297318-balancer-l7leveler-kubr-yp-sas-232-BAL&text=videoid:4302885981323250754","teaser":[{"list":{"type":"unordered","items":["Bu video, bir kişinin 100 PC 7 bar kompresör lastik hava basma aletinin kutu açılımını ve kullanımını gösterdiği bir ürün inceleme içeriğidir.","Videoda önce aletin kutu açılımı yapılarak içinden çıkan parçalar (3 metrelik kablo, şişirme ucu, yastık, top şişirme ucu) tanıtılmaktadır. Ardından aletin araçlarda nasıl kullanılacağı adım adım gösterilmekte, çakmaklık yerine nasıl takılacağı ve lastiklere nasıl hava basılacağı anlatılmaktadır. Aletin 12 volt 70 watt çekim gücüne sahip olduğu, normal araç lastikleri için 2,20-2,50 bar (30-35 PC) basınçta çalıştığı ve 5 dakika çalıştırıp 5 dakika dinlendirilmesi gerektiği belirtilmektedir. 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