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Eğitmen, enerji korunumu prensibi kullanarak bu cisimlerin hızlarını, zamanlarını, ivmelerini ve etki eden net kuvvetlerini karşılaştırmaktadır. Özellikle kaymadan dönerek ilerleyen cisimlerin hareketi, sürtünme kuvveti ve eylemsizlik momenti kavramları üzerinde durulmaktadır. 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Öğretmen önce her aralıktaki hareketi belirleyip, ardından bu hareketlerin ivmelerini hesaplamaktadır. Son olarak, ivme-zaman grafiğini çizerek konuyu pekiştirmektedir. Video, fizik dersinde hareket ve ivme konusunu öğrenmek isteyenler için faydalı bir kaynaktır."]},"endTime":206,"title":"Fizik Dersi: Hareket ve İvme Grafiği","beginTime":0}],"fullResult":[{"index":0,"title":"Hareket Türleri","list":{"type":"unordered","items":["0-2 aralığında artı yönde sabit ivmeli düzgün hızlanan hareket yapılıyor.","2-4 aralığında artı yönde sabit hızlı (düzgün doğrusal) hareket yapılıyor.","4-6 aralığında artı yönde sabit ivmeli düzgün yavaşlayan hareket yapılıyor.","6-8 aralığında eksi yönde sabit ivmeli düzgün hızlanan hareket yapılıyor.","8-10 aralığında eksi yönde sabit ivmeli düzgün yavaşlayan hareket yapılıyor."]},"beginTime":0,"endTime":90,"href":"/video/preview/4623326320595309011?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=0&ask_summarization=1"},{"index":1,"title":"İvme Hesaplamaları","list":{"type":"unordered","items":["İvme, eğim formülüyle bulunur: karşı bölü komşu.","0-2 aralığında 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yayınladığım içeriklerin düzenli PDF dosyasını (Son birkaç içerik eklenmedi) indirmek ve bilgi almak için; • Fizik Kanalımın Etkileşimli PDF Dosyası Videoda teğetsel (çizgisel) ivme...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/3381252/e537c10d3888003d400243aceb7a3413/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/zBYzUAEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"10","reqid":"1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=videoid:12432566180724756398","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan fizik dersi formatındadır. Eğitmen, teğetsel ve merkezcil (radyal/normal) ivmeler konusunu detaylı şekilde anlatmaktadır.","Videoda, teğetsel ivmenin tanımı, hızla aynı veya zıt doğrultuda olabilmesi ve merkezcil ivmenin (radyal/normal ivme) formülü (v²/r) açıklanmaktadır. Eğitmen, sürtünmesiz sistemlerde yatay düzlemdeki cisim ve sarkaç örnekleri üzerinden teğetsel ve merkezcil ivmelerin hesaplanmasını ve hareket üzerindeki etkilerini göstermektedir.","Ayrıca, mg sinüs alfa ve mg kosinüs alfa gibi kuvvet bileşenlerinin kullanımı, eğrilik yarıçapı kavramı ve cismin farklı noktalardaki ivmesinin yönü ve büyüklüğü animasyonlarla görselleştirilmektedir. Video, teorik bilgilerin yanı sıra pratik örneklerle desteklenerek, kuvvetlerin analizi ve cismin hızını etkilemesi konularını kapsamaktadır."]},"endTime":1232,"title":"Teğetsel ve Merkezcil İvme Fizik Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"Teğetsel İvme ve Merkezcil İvme","list":{"type":"unordered","items":["Videoda teğetsel ivme ve merkezcil ivme (radyal ivme veya normal ivme olarak da bilinen) konuları ele alınacaktır.","Teğetsel ivme, cismin hareket doğrultusundaki ivmesidir ve hızıyla aynı yönde veya zıt yönde olabilir.","F=m.a denklemi içindeki ivme aslında teğetsel ivmedir ve 11. sınıfta Newton'un hareket yasaları konusunda işlenir."]},"beginTime":1,"endTime":38,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1&ask_summarization=1"},{"index":1,"title":"Teğetsel İvme Örnekleri","list":{"type":"unordered","items":["Sürtünmesiz bir sistemde yatay düzlemde ilerleyen bir cisim üzerine hızıyla aynı yönde bir kuvvet uygulandığında hızlandırılır, zıt yönde uygulandığında ise yavaşlatılır.","Hızına dik olan kuvvet, cismin süratini değiştiremez ancak yönünü değiştirebilir.","Teğetsel ivme, net kuvvetin yönünde oluşur ve cismin hızıyla aynı yönde olduğunda hızı artırır, zıt yönde olduğunda ise yavaşlatır."]},"beginTime":38,"endTime":165,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=38&ask_summarization=1"},{"index":2,"title":"Sarkaç Örneği","list":{"type":"unordered","items":["Sürtünmesiz bir sarkaç sisteminde, cismin üzerinde ağırlığı (mg) ve ipin uyguladığı kuvvet (T) bulunur.","Cismin hızına dik olan doğrultuda merkezcil (radyal) ivme oluşur, hızın doğrultusunda ise teğetsel ivme oluşur.","Serbest bırakılan sarkaçta, teğetsel ivme g.sinüsθ olarak hesaplanır ve bu ivme cismin süratinin birim zamandaki değişimini verir."]},"beginTime":165,"endTime":337,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=165&ask_summarization=1"},{"index":3,"title":"Merkezcil İvme","list":{"type":"unordered","items":["Merkezcil ivme, yarıçapı değişmeyen bir yörünge izleyen cisimlerde oluşur ve merkeze doğru olan kuvvet tarafından sağlanır.","Merkezcil ivme formülü v²/r ile verilir ve cismin hızı sıfır olduğunda sıfır olur.","Sarkaç örneğinde, cisim aşağıya doğru indikçe mg.sinüsθ değeri azalır, bu nedenle teğetsel ivme azalır ve cismin hızı artar."]},"beginTime":337,"endTime":510,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=337&ask_summarization=1"},{"index":4,"title":"İvme ve Kuvvet İlişkisi","list":{"type":"unordered","items":["Alfa açısı için MG sinüs alfa ve MG kosinüs alfa değerleri hesaplanabilir.","Teğetsel ivme, sinüs alfanın yönünde olup MG sinüs alfa bölü m formülüyle g sinüs alfa olarak hesaplanır.","Radyal ivme merkeze doğru olup, T eksi MG kosinüs alfa eşittir m v kare bölü r formülüyle hesaplanır."]},"beginTime":512,"endTime":583,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=512&ask_summarization=1"},{"index":5,"title":"Cismin İvmesi ve Kuvvetleri","list":{"type":"unordered","items":["Cismin ivmesi, cisme etki eden net kuvvetin oluşturduğu ivmeyi ifade eder.","Birinci durumda cismin radyal doğrultuda ivmesi yokken, teğetsel ivmesi sıfır olup v kare bölü r büyüklüğünde bir ivmesi vardır.","MG sinüs teta kuvveti teğetsel ivmeyi oluştururken, T ve MG kosinüs teta birlikte radyal (merkezcil) kuvveti oluşturur."]},"beginTime":583,"endTime":700,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=583&ask_summarization=1"},{"index":6,"title":"Kuvvetlerin Etkisi ve Eğrilik Yarıçapı","list":{"type":"unordered","items":["Cisme sadece düşey MG kuvveti etki ederse, cismin ivmesi aşağıya doğru g olur.","MG kuvveti cismin hızına sürekli dik kalmayı başarsa, cismin hızının yönünü değiştirir ama büyüklüğünü değiştirmez.","MG sinüs teta teğetsel kuvvet olurken, MG kosinüs teta radyal doğrultudaki ivmeyi oluşturur ve cismin hızının yön değiştirme hızıdır."]},"beginTime":700,"endTime":819,"href":"/video/preview/12432566180724756398?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=700&ask_summarization=1"},{"index":7,"title":"Eğrilik Yarıçapı Kavramı","list":{"type":"unordered","items":["Eğrilik yarıçapı, MG kuvveti cismin hızına 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Derslerimizi İzlemek İsterseniz : bit.ly/3eNmhli 🚀 Kimya Kitap + Video Paketler ve Fizik Adına Tüm Yayınlarımız İçin : https://bit.ly/3bfYfKw 🔥 AYT Fizik Kampı Serisini Sipariş Etmek...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/2744263/b912b76c3f698998fd9ce67bdcc6b3c4/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/gTTBHAIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"12","reqid":"1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=videoid:11155284555526752496","teaser":[{"list":{"type":"unordered","items":["Bu video, bir öğretmenin öğrencilere fizik dersinde sabit ivmeli hareket konusunu anlattığı eğitim içeriğidir. Öğretmen, konuyu adım adım açıklamakta ve öğrencilere sorular sorarak pekiştirmektedir.","Video, sabit ivmeli hareket kavramını temelinden başlayarak, ivmenin tanımı ve birimi, hız-zaman ve ivme-zaman grafiklerinin çizimi, alınan yol hesaplamaları ve formüllerin uygulamalarını kapsamaktadır. Öğretmen, sabit ivmeli harekette ivmenin yönünü, hız değişimini ve alınan yolu hesaplama yöntemlerini çeşitli örnekler üzerinden göstermektedir.","Videoda ayrıca sürtünme kuvvetinin ivmenin yönünü belirlediği, net kuvvetin ivmenin yönüyle aynı yönde olduğu ve değişken ivmeli hareket ile sabit ivmeli hareket arasındaki farklar da açıklanmaktadır. Dersin sonunda, bir sonraki derste konum-zaman grafikleri, hareket ve nehir problemleri ile test sorularının ele alınacağı belirtilmektedir."]},"endTime":2222,"title":"Fizik Dersi: Bir Boyutta Sabit İvmeli Hareket","beginTime":0}],"fullResult":[{"index":0,"title":"Dersin Tanıtımı","list":{"type":"unordered","items":["Ders, bir boyutta sabit ivmeli hareket konusunu ele alacak ve dokuzuncu sınıf konularına dayanacak.","Dersin kazanımları arasında hareket, Newton hareket yasaları, bağıl hareket ve enerji konuları yer alıyor.","Dersin sonunda grafik çizimleri yaparak soruları hızlıca çözebileceksiniz."]},"beginTime":1,"endTime":131,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1&ask_summarization=1"},{"index":1,"title":"Hareket ve İvme Kavramları","list":{"type":"unordered","items":["Bir cismin referans noktasına göre zamanla konum değiştirmesi hareket olarak tanımlanır.","İvme, birim zamandaki hız değişimidir ve vektörel bir büyüklüktür, birimi metre bölü saniye karedir.","İvme değeri, cismin eşit zaman aralıklarındaki hız değişimini belirler."]},"beginTime":131,"endTime":183,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=131&ask_summarization=1"},{"index":2,"title":"İvmenin Anlamı","list":{"type":"unordered","items":["Bir cismin ivmesi 5 m/s² olduğunda, duruştan harekete başladığında her saniye 5 metre/saniye hız kazanır.","İvme değeri 10 m/s² olsaydı, her saniye 10 metre/saniye hız kazanarak hızlanırdı.","Yavaşlayan bir cismin ivmesi eksi değer alır, örneğin -15 m/s² ivmesi olan bir cisim her saniye 15 metre/saniye hız kaybeder."]},"beginTime":183,"endTime":311,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=183&ask_summarization=1"},{"index":3,"title":"Sabit İvme ile Hareket Problemleri","list":{"type":"unordered","items":["Sabit ivme ile hareket eden araçların ivmelerini, yönlerini ve verilen hareket süresinde aldıkları yolları hesaplamak için örnekler çözülecek.","Hız zaman grafiğinin altında kalan alan, araçın aldığı yolu verir.","İvmenin yönü, hızın yönüyle aynı yönlüyse araç hızlanır, ters yönlüyse araç yavaşlar."]},"beginTime":314,"endTime":326,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=314&ask_summarization=1"},{"index":4,"title":"İvme Hesaplama Örnekleri","list":{"type":"unordered","items":["Bir araç 30 m/s hızla hareket edip 3 saniye sonra durduğunda, ivmesinin büyüklüğü (30-0)/3 = 10 m/s² olur ve yön sola doğrudur.","Bir araç 20 m/s hızla hareket edip 4 saniye sonra durduğunda, ivmesinin büyüklüğü (20-0)/4 = 5 m/s² olur ve yön sola doğrudur.","İvmede eksi işareti sadece yön ifade eder, yavaşlama veya hızlanma için her zaman eksi işareti olmadığından dikkat edilmelidir."]},"beginTime":326,"endTime":486,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=326&ask_summarization=1"},{"index":5,"title":"Hızlanma Örneği","list":{"type":"unordered","items":["Bir araç 20 m/s hızla hareket edip 3 saniye boyunca 5 m/s² ivmeyle hızlanırsa, son hızı 35 m/s olur.","Hız zaman grafiğinde, eğim ivmeyi, ve grafiğin altında kalan alan alınan yolu verir.","Alınan yol hesaplanırken, (ilk hız + son hız) × hareket süresi ÷ 2 formülü kullanılır."]},"beginTime":486,"endTime":704,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=486&ask_summarization=1"},{"index":6,"title":"Diğer Örnekler","list":{"type":"unordered","items":["Bir araç 40 m/s hızla hareket edip 3 saniye boyunca 10 m/s² ivmeyle hızlanırsa, son hızı 70 m/s ve alınan yol 165 metre olur.","Yavaşlarken de bir yol alınır, bu nedenle takip mesafesi önemlidir."]},"beginTime":704,"endTime":794,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=704&ask_summarization=1"},{"index":7,"title":"İvme ve Hız Hesaplamaları","list":{"type":"unordered","items":["Bir araç 50 m/s hızla hareket ederek 15 m/s² ivmeyle 3 saniye yavaşladığında son hızı 5 m/s olur.","Yavaşlama sırasında alınan yol, (ilk hız + son hız) × hareket süresi / 2 formülüyle hesaplanır ve bu örnekte 82,5 metre olarak bulunur.","Takip mesafesi önemli bir konudur, çünkü 50 m/s hızla giden bir araç 3 saniyede durmak için 82,5 metre yol alır, bu nedenle takip eden araçlar bu mesafeyi korumalıdır."]},"beginTime":798,"endTime":857,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=798&ask_summarization=1"},{"index":8,"title":"Hız-Zaman Grafikleri","list":{"type":"unordered","items":["Hız-zaman grafiklerinde, alan hesaplaması alınan yolu gösterir; üçgenin alanı (taban × yükseklik) / 2 formülüyle hesaplanır.","Sabit ivmeli harekette, hız-zaman grafiği bir doğru çizgisidir ve eğim sabittir.","Değişken ivmeli harekette, ivme zamanla değişir ve gaza basma miktarı ivmeyi artırır."]},"beginTime":857,"endTime":944,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=857&ask_summarization=1"},{"index":9,"title":"İvme ve Hız Problemleri","list":{"type":"unordered","items":["Bir araç 20 m/s'den 0'a 5 saniyede düşerse, ortalama ivmesi -4 m/s² olur (eksi işaretine dikkat).","Hız-zaman grafiğinde, alan hesaplaması alınan yolu gösterir; üçgenin alanı (taban × yükseklik) / 2 formülüyle hesaplanır.","Bir araç 30 m/s hızla hareket ederek 0'a 6 saniyede düşerse, ortalama ivmesi -5 m/s² olur."]},"beginTime":944,"endTime":1115,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=944&ask_summarization=1"},{"index":10,"title":"Hız ve İvme Bağıntıları","list":{"type":"unordered","items":["Bir araç 2 m/s² ivmeyle 5 saniye hızlanıyorsa, her saniye 2 m/s hız kazanır.","Hızlanma durumunda, son hız = ilk hız + (ivme × hareket süresi) formülü kullanılır.","Hız ve ivme problemlerinde, alınan yol, hareket süresi ve ivme bilgileri kullanılarak diğer değerler hesaplanabilir."]},"beginTime":1115,"endTime":1139,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1115&ask_summarization=1"},{"index":11,"title":"Hız-Zaman Grafiği ve Yer Değiştirme Hesaplama","list":{"type":"unordered","items":["Hız-Zaman grafiğinde, ilk hız 25 m/s, son hız 35 m/s ve hareket süresi 5 saniye olarak verilmiştir.","Hız-Zaman grafiğinin altındaki alan, doğrusal bir yolda yer değiştirmeyi verir ve bu örnekte (35+25)/2 × 5 = 150 m olarak hesaplanmıştır.","Sabit ivmeli harekette, Hız-Zaman grafiğinin eğimi sabit olmalıdır çünkü eğim ivmeyi verir."]},"beginTime":1144,"endTime":1272,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1144&ask_summarization=1"},{"index":12,"title":"Net Kuvvet ve İvme İlişkisi","list":{"type":"unordered","items":["Net kuvvet, cisme ivme kazandıran kuvvettir ve Fnet = ma formülüyle ifade edilir.","Arabanın ivmesini sağlayan net kuvvet, tekerleklerine etki eden bileşke sürtünme kuvvetidir.","İvmenin yönüyle net kuvvetin yönü her zaman aynıdır; ivme sola ise net kuvvet de sola, ivme sağa ise net kuvvet de sağa doğrudur."]},"beginTime":1272,"endTime":1470,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1272&ask_summarization=1"},{"index":13,"title":"Hız-Zaman ve İvme-Zaman Grafikleri","list":{"type":"unordered","items":["Hız-zaman ve ivme-zaman grafikleri çizilirken, sağa doğru hız artı, sola doğru ivme eksi olarak alınır.","Hız-zaman grafiğinin altındaki alan, cismin aldığı yolu verir.","İvme-zaman grafiğinin altındaki alan, hız değişimini verir."]},"beginTime":1476,"endTime":1581,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1476&ask_summarization=1"},{"index":14,"title":"Örnek Hareketler ve Grafikler","list":{"type":"unordered","items":["Hareket yönü ve ivme yönü aynı yönde olabilir, bu durumda her iki değer de eksi olabilir.","Hız değişimi, ilk hız ile son hız arasındaki farktır.","Hızlanma durumunda ivme artı, yavaşlama durumunda ivme eksi olarak alınır."]},"beginTime":1581,"endTime":1832,"href":"/video/preview/11155284555526752496?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1581&ask_summarization=1"},{"index":15,"title":"Farklı Hareket Durumları","list":{"type":"unordered","items":["Hız 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Eğitmen, ilkokul seviyesinde bile anlaşılır şekilde fizik kavramlarını açıklamaktadır.","Videoda, önceki videolarda anlatılan konum-zaman ve hız-zaman grafiklerinin devamı olarak ivme kavramı işlenmektedir. Eğitmen, ivme-zaman grafiğinden hız-zaman grafiğine geçiş yöntemini anlatmakta ve telefonlardaki ivme sensörlerinin çalışma prensibini, günlük hayattaki uygulamalarını (asansörler, uçaklar) ve okuma hatalarını açıklamaktadır.","Ayrıca augmented reality teknolojisinin kamera sensörlerini kullanarak konum bilgisini nasıl artırdığı gösterilmekte ve basit fizik kavramlarının bilim kurgu gibi görünen uygulamalara nasıl dönüştüğü vurgulanmaktadır."]},"endTime":2062,"title":"Fizik Dersi: İvme-Zaman ve Hız-Zaman Grafikleri","beginTime":0}],"fullResult":[{"index":0,"title":"Giriş ve Ders Hedefleri","list":{"type":"unordered","items":["Bu video, konum-zaman, hız-zaman ve ivme-zaman grafiği konularını ele alıyor.","Önceki videolarda temel seviyede konum-zaman ve hız-zaman grafiği oluşturulması, bir grafiğin diğerine nasıl geçilmesi anlatılmıştır.","Bu video, daha temel seviyede hedefleniyor ve bilinmeyenler için 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video, bir fizik öğretmeninin 11. sınıf öğrencilerine Newton hareket yasaları, sürtünme kuvveti ve dengede kuvvetler konularını anlattığı kapsamlı bir eğitim içeriğidir.","Video, sürtünme kuvvetinin kaynağı ve büyüklüğü ile başlayıp, dengede kuvvetlerin nasıl dengelenmesi gerektiği konularını ele almaktadır. Daha sonra kuvvet bileşenleri, üst üste cisimler, birlik beraberlik ilkesi, sürtünme kuvveti hesaplamaları ve dinamik sistemler konuları örnek sorular üzerinden açıklanmaktadır. Son bölümde ise ağırlık ve kütle kavramları, yerçekimi kuvveti ve farklı gezegenlerdeki yerçekimi ivmesi farkları anlatılmaktadır.","Videoda TYT, MS ve AYT sınavlarına hazırlanan öğrenciler için önemli soru tipleri ve çözüm teknikleri sunulmaktadır. Öğretmen, konuları günlük hayattan örneklerle somutlaştırmakta ve sınavlarda karşılaşılabilecek zor noktaları vurgulamaktadır. Video, kampın 18. gününde Newton hareket yasaları konusunun bitirileceği ve yarın test sorularının yapılacağı bilgisiyle sonlanmaktadır."]},"endTime":2908,"title":"11. Sınıf Fizik Dersi: Newton Hareket Yasaları ve Sürtünme Kuvveti","beginTime":0}],"fullResult":[{"index":0,"title":"Newton Hareket Yasaları Kampı 18. Gün","list":{"type":"unordered","items":["Kampın 18. gününde Newton hareket yasaları konusu tamamlanacak ve 11. sınıf kitabında soru çözüm odaklı ilerlenecek.","Test sorularında ve okullardaki yazılı sınavlarında zorlayıcı olabilecek bir konu ele alınacak.","Bu konuyu anlamak için kuvvet göstermeyi iyi bilmek gerekiyor ve dikkatli dinlemek yeterli olacak."]},"beginTime":0,"endTime":61,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=0&ask_summarization=1"},{"index":1,"title":"Sürtünme Kuvveti Örneği","list":{"type":"unordered","items":["Kağıt olası yatay F kuvvetinin etkisiyle düşey duvarda hareketsiz durmaktadır, bu durumda net kuvvet sıfırdır.","Cismin ağırlığı 30 Newton olduğunda, sürtünme kuvveti de 30 Newton olmak zorundadır çünkü dengede durmaktadır.","F kuvveti arttırıldığında sürtünme kuvveti artmaz, duvarın tuğlaya uyguladığı tepki kuvveti ve basınç artar."]},"beginTime":61,"endTime":324,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=61&ask_summarization=1"},{"index":2,"title":"Sürtünme Kuvveti Hesaplama","list":{"type":"unordered","items":["Kütlesi m olan bir cisim sürtünmeli düşey duvarda F kuvveti etkisiyle durmaktadır.","Cisme etki eden sürtünme kuvvetinin büyüklüğünü bulabilmek için cismin kütlesini ve yerçekimi ivmesini bilmek gerekir.","F kuvveti azaltıldığında sürtünme kuvveti de azalır ve cisim hafif hafif kaymaya başlar, tamamen kaldırıldığında serbest düşüşe geçer."]},"beginTime":324,"endTime":477,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=324&ask_summarization=1"},{"index":3,"title":"Sürtünme Kuvveti Sınır Değeri","list":{"type":"unordered","items":["Bir kilogram kütleli cismi düşey doğrultuda duvara doğru yatay F kuvveti ile itilerek hareketsiz bir şekilde tutuluyor.","Cisim ile duvar arasındaki statik sürtünme katsayısı 4 ise, cismi hareketsiz tutmak için F kuvvetinin büyüklüğü en az 25 Newton olmalıdır.","F kuvveti arttırıldığında sürtünme kuvveti değişmez, sadece düşey duvarın cisme uyguladığı normal kuvvet artar."]},"beginTime":477,"endTime":619,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=477&ask_summarization=1"},{"index":4,"title":"Kuvvet Bileşenleri ve Sürtünme Kuvveti Problemi","list":{"type":"unordered","items":["Kütlesi 3 kilogram olan bir meclis, yatayda 53 derece açı yapacak biçimde uygulanan ev kuvveti ile hareketsiz tutuluyor.","Duvar ile cisim arasındaki statik sürtünme katsayısı 1/3 olduğuna göre, cismin düşmemesi için uygulanması gereken kuvvetin büyüklüğü en az kaç Newton olmalıdır?","Çapraz uygulanan kuvvet, açının değdiği yere göre kosinüs, değmediği yere göre sinüs alınarak iki bileşene ayrılır."]},"beginTime":623,"endTime":795,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=623&ask_summarization=1"},{"index":5,"title":"Kuvvetlerin Analizi","list":{"type":"unordered","items":["Cismin ağırlığı 30 Newton, yukarı doğru olan kuvvetler (sürtünme kuvveti ve ev kuvveti) toplamı 8 Newton'dur.","Sürtünme kuvveti, sürtünme katsayısı (1/3) ile ev kuvvetinin (6F) çarpımı olan 2F'dir.","Cismin ağırlığı (30 Newton) yukarı doğru olan kuvvetlerin toplamına (8+2=10 Newton) eşit olduğundan, sorunun cevabı 30 Newton'dur."]},"beginTime":795,"endTime":979,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=795&ask_summarization=1"},{"index":6,"title":"Üst Üste Cisimlerin Hareketi","list":{"type":"unordered","items":["Üst üste cisimlerin hareketi konusu TYT, MS ve AYT sınavlarında yorum olarak sorulabilir.","Üst üste cisimlerde birlik beraberlik ilkesi varsa, cisimlerin ivmeleri birbirine eşit olmak zorundadır.","Cisimlerin birlikte hareket etmesi için aralarındaki bağ kopmamalıdır, aksi takdirde cisimler birbirinden ayrılacaktır."]},"beginTime":987,"endTime":1159,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=987&ask_summarization=1"},{"index":7,"title":"Sürtünme Kuvveti ve Maksimum Kuvvet","list":{"type":"unordered","items":["Üst üste cisimlerde, bir cismin diğerini hareket ettiren kuvvet, bir cismin diğerine uyguladığı sürtünme kuvvetidir.","Sürtünme kuvvetinin değerini bulurken her zaman üstteki cismin kütlesi alınmalıdır.","Maksimum kuvvet, cisimlerin birlikte hareket etmesi için gereken en küçük kuvvettir; bu kuvvetten daha büyük bir kuvvet uygulandığında cisimler birbirinden ayrılacaktır."]},"beginTime":1159,"endTime":1415,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1159&ask_summarization=1"},{"index":8,"title":"Üst Üste Cisimlerin Hareketi Örnekleri","list":{"type":"unordered","items":["Üst üste cisimlerde, bir cismin diğerini hareket ettiren kuvvet, bir cismin diğerine uyguladığı sürtünme kuvvetidir.","Üst üste cisimlerde, bir cismin diğerini hareket ettiren kuvvet, bir cismin diğerine uyguladığı sürtünme kuvvetidir.","Üst üste cisimlerde, bir cismin diğerini hareket ettiren kuvvet, bir cismin diğerine uyguladığı sürtünme kuvvetidir."]},"beginTime":1415,"endTime":1557,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1415&ask_summarization=1"},{"index":9,"title":"Sürtünme Kuvveti Problemi","list":{"type":"unordered","items":["İki cisim arasında sürtünme kuvveti var ve bu kuvvetler eşit büyüklükte (6 Newton) olup, cisimlerin ivmeleri de eşittir.","A'nın üzerindeki kuvvetler: 6 Newton sürtünme kuvveti ve 2 kg kütlesi ile 3 m/s² ivmesi, toplam 18 Newton kuvvet etki etmektedir.","Eğer uygulanan kuvvet 18 Newton'dan fazla olursa, B hızlanacaktır ancak A'nın ivmesine ayak uyduramayıp düşecektir."]},"beginTime":1559,"endTime":1676,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1559&ask_summarization=1"},{"index":10,"title":"Kamyonet ve Kutu Problemi","list":{"type":"unordered","items":["Yatay bir yolda durmakta olan sürtünmeli kamyonet kasasında bir kutu dengededir ve kamyonet sağa doğru ivmelenmeye başladığında, kutu ile kamyonetin arka ucu arasındaki mesafe azalmaktadır.","Kutuya sola doğru bir kuvvet etki etmemektedir, çünkü kutu geri gitmemektedir; aksine ileri gitmektedir.","Kamyonetin ivmesi (6 m/s²) kutunun ivmesinden (2 m/s²) daha büyüktür, bu nedenle kutu kamyonete göre geri kalır."]},"beginTime":1676,"endTime":1940,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1676&ask_summarization=1"},{"index":11,"title":"Sürtünme Kuvveti ve İvme İlişkisi","list":{"type":"unordered","items":["Kutuya ve kamyonete etki eden kuvvetler sürtünme kuvvetidir; kamyonete tekerleklerden, kutuya ise kamyonetle kutu arasındaki zeminden gelmektedir.","Kutunun ivmesi ile kamyonetin ivmesi aynı yöndedir (sağa doğru) ancak birbirine eşit değildir.","Sabit hızla giden bir kamyon ve kutu durumunda net kuvvet sıfırdır, bu nedenle kutuya hareket yönünde bir kuvvet uygulanmaz."]},"beginTime":1940,"endTime":2136,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=1940&ask_summarization=1"},{"index":12,"title":"Dinamik Sistem Sorusu Çözümü","list":{"type":"unordered","items":["Çekirdek sistemde 2 kg'lık K ve 5 kg'lık L kütleleri arasında sürtünme var ve kinetik sürtünme katsayısı 4'tür.","L kütlesi 37 Newton olan F kuvvetiyle çekildiğinde L'nin ivmesi sorulmaktadır.","L sola doğru hareket ederken, K sağa doğru hareket eder ve bir yerden sonra K cismi düşecektir."]},"beginTime":2142,"endTime":2192,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=2142&ask_summarization=1"},{"index":13,"title":"Kuvvetlerin Analizi","list":{"type":"unordered","items":["İp her iki kütleyi de aynı gerilme ile çekmektedir.","K kütlesine etki eden sürtünme kuvveti, hareket yönünde değil, hareket etmemeye yönelik olarak gösterilmelidir.","Sürtünme kuvveti 20 kg × 4 = 8 Newton olarak hesaplanmıştır."]},"beginTime":2192,"endTime":2278,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=2192&ask_summarization=1"},{"index":14,"title":"Ortak İvme ve Net Kuvvet","list":{"type":"unordered","items":["İki kütle aynı iple bağlandığı için ortak ivmeli hareket etmektedir.","K için net kuvvet denklemi: T - 8 = 5 × a şeklinde yazılabilir.","L için net kuvvet denklemi: 37 - 16 = 5 × a şeklinde yazılabilir."]},"beginTime":2278,"endTime":2365,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=2278&ask_summarization=1"},{"index":15,"title":"Sonuç ve Özet","list":{"type":"unordered","items":["İki denklem çözülerek L'nin ivmesi 3 m/s² olarak bulunmuştur.","Sürtünme kuvvetlerinin yönü, ip gerilmelerinin yönü ve net kuvvetin yazımı çözümde önemlidir.","Dinamik sistemler konusu bu şekilde tamamlanmış olup, son kısımda ağırlık ve yerçekimi ivmesi konusu ele alınacaktır."]},"beginTime":2365,"endTime":2470,"href":"/video/preview/17407223574564385703?parent-reqid=1769333645940567-6303239149655041599-balancer-l7leveler-kubr-yp-klg-25-BAL&text=Knowledge+Gift4u&t=2365&ask_summarization=1"},{"index":16,"title":"Ağırlık ve Kütle Kavramları","list":{"type":"unordered","items":["Ağırlık, bir gezegenin üzerinde bulunan cismin kütlesine uyguladığı kütle çekim kuvvetidir ve bir kuvvettir.","Ağırlık dinamometre ile ölçülür, vektörel bir büyüklüktür ve birimi newton'dur.","Kütle, değişmeyen madde miktarıdır ve fizikte cisimlerin ivmelenmeye karşı gösterdiği direnç olarak da 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