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hesaplanıyor."]},"beginTime":387,"endTime":559,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=387&ask_summarization=1"},{"index":3,"title":"Öğrenci Gruplama Problemi","list":{"type":"unordered","items":["Dördüncü soruda, bir kurstaki öğrenciler 4'er, 7'er ve 9'er gruplara ayrıldığında her seferinde 4 öğrenci eksik kalıyor.","Öğrenci sayısı 480'den fazla olduğuna göre, 4, 7 ve 9'un EKOK'u bulunuyor.","Çözüm sonucunda öğrenci sayısı 500 olarak hesaplanıyor."]},"beginTime":559,"endTime":657,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=559&ask_summarization=1"},{"index":4,"title":"EKOK ve EBOB Uygulaması","list":{"type":"unordered","items":["Beşinci soruda, EKOK ve EBOB kavramları kullanılarak bir hesaplama yapılıyor.","EKOK hesaplanırken ortak kuvveti büyük olan çarpanlar, EBOB 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bölü EBOB çarpı EDİ.","156 ve 396 sayılarının EBOB'u 26 olarak hesaplanıyor.","Dikdörtgenin etrafına ve içine eşit aralıklarla ağaç dikme problemi çözülüyor."]},"beginTime":794,"endTime":988,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=794&ask_summarization=1"},{"index":7,"title":"Ağaç Dikme Problemi","list":{"type":"unordered","items":["Dikdörtgen şeklindeki bir tarlanın etrafına ve içine eşit aralıklarla ağaç dikme problemi çözülüyor.","Çevre bölü EBOB formülü kullanılarak ağaç sayısı hesaplanıyor.","İçine ve çevresine dikilen toplam ağaç sayısı 808 olarak bulunuyor."]},"beginTime":988,"endTime":1115,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=988&ask_summarization=1"},{"index":8,"title":"Yasal Çarpanlara Ayırma","list":{"type":"unordered","items":["Yasal çarpanlarına ayırma yaparak en küçük x tam sayısı bulunuyor.","1500-950 ifadesinin çarpanlarına ayrılması yapılıyor.","İlk sayının 55 olması gerektiği belirleniyor."]},"beginTime":1115,"endTime":1225,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1115&ask_summarization=1"},{"index":9,"title":"Kare Parsele Bölme","list":{"type":"unordered","items":["Boyutları 48 metre ve 72 metre olan dikdörtgen şeklindeki bir tarla en az kaç kare parsele bölünüyor.","EBOB formülü kullanılarak en büyük kare parçaları bulunuyor.","Toplam 3 kare parsele bölündüğü belirleniyor."]},"beginTime":1225,"endTime":1368,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1225&ask_summarization=1"},{"index":10,"title":"Rasyonel İfadelerde EKOK","list":{"type":"unordered","items":["Rasyonel ifadelerde EKOK hesaplaması yapılıyor.","15 ve 63 sayılarının EKOK'u 300 olarak bulunuyor.","Saat probleminde 10 saat sonra aynı anda çıkan üç nesnenin 3 sefer hesaplanması yapılıyor."]},"beginTime":1368,"endTime":1478,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1368&ask_summarization=1"},{"index":11,"title":"Dairesel Pist Problemi","list":{"type":"unordered","items":["Çevresi 360 metre olan dairesel bir pistte, A noktasındaki çiçek zambak isimli hamsterlar aynı yönde hareket ediyorlar.","İlk kez aynı anda harekete başlayan hamsterlar ikinci kez yan yana geldiklerinde zambak çiçekten kaç tur fazla atmış.","Zambak 15 tur, çiçek 10 tur, zambak çiçekten 5 tur fazla atmış."]},"beginTime":1504,"endTime":1691,"href":"/video/preview/6932231753687563944?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1504&ask_summarization=1"},{"index":12,"title":"Bölme ve Kalan 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İçerikte değişkenler, eşitsizlikler, sıralama, çift ve tek kuvvet özellikleri, eşitsizliklerin taraf tarafa toplanması, çıkarma işlemleri, tam sayı değerleri, ikili paketleme sistemi, mutlak değer, basit kesirler, devirli ondalık sayılar ve tam kare açılımı gibi konular ele alınmaktadır.","Öğretmen her soruyu adım adım çözerken gerekli özellikleri ve çözüm taktiklerini açıklamakta, öğrencilerin dikkat etmesi gereken noktaları vurgulamaktadır. Video sonunda, bir sonraki derste mutlak değer soru çözümlerinin yapılacağı belirtilmektedir."]},"endTime":1714,"title":"Matematik Dersi: Eşitsizlikler ve Değişkenler","beginTime":0}],"fullResult":[{"index":0,"title":"Giriş ve Çift Kuvvet Özelliği","list":{"type":"unordered","items":["Videoda değişkenler hakkında sorular çözülecek ve bazı özel soru tipleri ele alınacak.","Reel sayı, değer ve gerçek aynı şeydir.","Çift kuvvet özelliği, aralıkta sıfır değeri varsa eşitsizlik küçük eşit x kare şeklinde çözülür ve en büyük değer dahil edilir."]},"beginTime":0,"endTime":138,"href":"/video/preview/2383657551075776376?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=0&ask_summarization=1"},{"index":1,"title":"Eşitsizlik Çözümü","list":{"type":"unordered","items":["Eşitsizliklerde eksikler taraf tarafa toplanabilir, asla çıkarılamaz.","Küpte herhangi bir problem yoktur, normal şekilde işlem yapılır.","Eşitsizliklerin işaretleri dahil olduğu için kapalı aralık kullanılır."]},"beginTime":138,"endTime":209,"href":"/video/preview/2383657551075776376?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=138&ask_summarization=1"},{"index":2,"title":"Sıralama Problemi","list":{"type":"unordered","items":["Gerçek sayılarla ilgili sıralama problemlerinde, değişkenlerin değerleri karşılaştırılarak sıralama yapılır.","Paketleme sistemi kullanılarak eşitsizlikler çözülür.","Sıralama sonucunda y, z, x şeklinde bir sıralama elde edilir."]},"beginTime":209,"endTime":283,"href":"/video/preview/2383657551075776376?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=209&ask_summarization=1"},{"index":3,"title":"Özel Soru Çözümü","list":{"type":"unordered","items":["Özel sorularda, ortadaki değer baz alınarak diğer değerler hesaplanır.","Oran orantı konusunda da benzer sorular çıkabilir.","En küçük tam sayı değeri için, verilen 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en büyük ve en küçük tam sayı değerleri toplanarak sonuç bulunur."]},"beginTime":435,"endTime":538,"href":"/video/preview/2383657551075776376?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=435&ask_summarization=1"},{"index":6,"title":"Eşitsizlik Problemleri Çözümü","list":{"type":"unordered","items":["Eşitsizlik problemlerinde, verilen aralıklara göre en uygun değerler bulunarak hesaplamalar yapılır.","Tam sayı ve reel sayı arasındaki fark, tam sayılı ifadelerde en büyük tam sayı değeri aranırken, reel sayılarda ise genel kurallar uygulanır.","Eşitsizliklerde aynı yönde olan terimler taraf tarafa toplanabilir ve toplama kuralları vardır: dahil olanlar dahil, dahil olmayanlar dahil değildir."]},"beginTime":553,"endTime":744,"href":"/video/preview/2383657551075776376?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=553&ask_summarization=1"},{"index":7,"title":"Eşitsizlik Çözüm Teknikleri","list":{"type":"unordered","items":["Eşitsizliklerde kare alma işlemi yapılırken, eşitsizlik içinde sıfır varsa klasik davranılır, yoksa karesi alınır.","Paydada bilinmeyen varsa, payda ile çarpma işlemi yaparak paydadan kurtulmak tavsiye edilir.","Çarpma işlemine göre ters dönen terimlerde işaret yönü değişir."]},"beginTime":744,"endTime":913,"href":"/video/preview/2383657551075776376?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=744&ask_summarization=1"},{"index":8,"title":"Eşitsizlik Problemlerinin Çözümü","list":{"type":"unordered","items":["Eşitsizlik problemlerinde aralık verilip diğer terim sorulduğunda, sızma yöntemi kullanılır.","Eşitsizliklerde terimler yer değiştirilerek ve paydalar eşitlenerek çözüm yapılır.","Sıralama sorularında paydalar eşitlenerek ve terimler karşılaştırılarak sıralama 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KPSS undergraduate associate degree Turkey-wide practice exam KPSS associate degree...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4439030/059105a5987bed9c3de6f0bb01e325c0/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/P-4sDAIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"9","reqid":"1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=videoid:4739328768963189191","teaser":[{"list":{"type":"unordered","items":["Bu video, Ömer Hoca tarafından sunulan bir matematik eğitim içeriğidir. Öğretmen, öğrencilere çeşitli matematik sorularını adım adım çözerek anlatmaktadır.","Videoda toplam 30 sorudan oluşan bir matematik sınavının çözümleri sunulmaktadır. İçerik, tam sayılar, üslü sayılar, mutlak değer, fonksiyonlar, kombinasyon problemleri, oran-orantı, yaş problemleri, geometri ve koordinat düzlemi gibi farklı matematik konularını kapsamaktadır. Her soru için çözüm yöntemleri, dikkat edilmesi gereken noktalar ve özel çözüm teknikleri detaylı olarak açıklanmaktadır.","Video özellikle DGS sınavına hazırlanan öğrenciler için faydalı olabilecek problem çözme teknikleri içermektedir. Eğitmen, öğrencilere ağır usul ve yavaş anlatım ile konuları aktarmakta, formülleri uygulamalı olarak göstermekte ve öğrencilerin sık yaptığı hataları vurgulamaktadır. Video sonunda gelecek videolarda denemeler ve problemlere devam edileceği belirtilmektedir."]},"endTime":3358,"title":"Türkiye Geneli Matematik Deneme Sınavı Çözüm Videosu","beginTime":0}],"fullResult":[{"index":0,"title":"Türkiye Geneli Deneme Sınavı Tanıtımı","list":{"type":"unordered","items":["Ömer Hoca, Türkiye geneli bir deneme sınavı yapacağını ve 30 sorudan oluşan matematik testi sunacağını belirtiyor.","Kanalın abone olunması ve videoların beğenilmesi isteniyor.","Destek olunması durumunda problem videoları, kamp videoları ve lisans denemeleri devam edecek."]},"beginTime":0,"endTime":34,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=0&ask_summarization=1"},{"index":1,"title":"İlk Soruların Çözümü","list":{"type":"unordered","items":["İlk soruda sayısal hesaplama yapılıyor ve cevap 12 olarak bulunuyor.","İkinci soruda \"5x+7 ifadesi çift ise\" koşulu verilmiş ve hangi ifadenin kesinlikle çift sayı olduğunu bulmak gerekiyor.","Üçüncü soruda üslü sayılarla ilgili bir problem çözülüyor ve cevap 36 olarak bulunuyor."]},"beginTime":34,"endTime":263,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=34&ask_summarization=1"},{"index":2,"title":"Köklü Sayılar ve Bölenler Soruları","list":{"type":"unordered","items":["Dördüncü soruda köklü sayılarla ilgili bir düzenleme yapılıyor ve a×b=16 olduğu bulunuyor.","Beşinci soruda 140'ın bölenleri hesaplanıyor ve toplam 24 bölen olduğu belirleniyor.","Altıncı soruda EBOB ve EKOK kavramları kullanılarak bir problem çözülüyor ve cevap 40 olarak bulunuyor."]},"beginTime":263,"endTime":631,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=263&ask_summarization=1"},{"index":3,"title":"Mutlak Değer Sorusu","list":{"type":"unordered","items":["Yedinci soruda mutlak değer sorusu çözülüyor.","Mutlak değer sorularında kural olarak, mutlak değer içi pozitifse çözüm kümesi elemanları aralıklara sığarsa alınır, sığmazsa alınmaz."]},"beginTime":631,"endTime":657,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=631&ask_summarization=1"},{"index":4,"title":"Mutlak Değer Problemi Çözümü","list":{"type":"unordered","items":["Mutlak değer probleminde, içindeki ifade negatif tespit edildiğinde eksi ile çarpılır.","Çözüm kümesinde a değerleri -7 ve 7 olarak bulunmuş, toplamları sıfırdır.","Mutlak değer problemlerinde, verilen aralıkla ilgili terimleri tek terim haline getirmek için tam kare yapma sistemi kullanılır."]},"beginTime":659,"endTime":842,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=659&ask_summarization=1"},{"index":5,"title":"Çift Kuvvet Özellikli Soru","list":{"type":"unordered","items":["Çift kuvvet özelliği kullanılarak, verilen aralıkta en küçük ve en büyük değerler bulunur.","Minimum değer sıfır olduğunda dahil olur, maksimum değer ise dahil olmayabilir.","En büyük ve en küçük değerlerin toplamı 22 olarak hesaplanmıştır."]},"beginTime":842,"endTime":965,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=842&ask_summarization=1"},{"index":6,"title":"Fonksiyon Sorusu","list":{"type":"unordered","items":["Özel tanımlı bir fonksiyon sorusunda, verilen değerler için fonksiyonun hangi parçasının kullanılacağı belirlenir.","f(29,10) değeri için fonksiyonun farklı parçaları kullanılarak sonuç 14 olarak bulunmuştur."]},"beginTime":965,"endTime":1047,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=965&ask_summarization=1"},{"index":7,"title":"Çarpanlara Ayırma Problemi","list":{"type":"unordered","items":["Terim benzeterek çarpanlara ayırma yöntemi kullanılarak, verilen ifade çarpanlarına ayrılır.","İkinci dereceden denkleme benzetme yöntemiyle çarpanlar bulunur.","35 sayısı çarpanlarından biri değildir."]},"beginTime":1047,"endTime":1195,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1047&ask_summarization=1"},{"index":8,"title":"Aritmetik Ortalama Problemi","list":{"type":"unordered","items":["1'den 40'a kadar sayıların toplamı formülü kullanılarak 812 olarak hesaplanır.","Dört sayının aritmetik ortalaması 2,5 olduğundan toplamları 10'dur.","Seçilmeyen sayıların toplamı 802 olarak bulunur."]},"beginTime":1195,"endTime":1274,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1195&ask_summarization=1"},{"index":9,"title":"Küme Sorusu","list":{"type":"unordered","items":["Bir kümenin alt kümelerinin sayısı 2 üzeri eleman sayısına eşittir.","Eleman sayısının 5'in tam katı olan sayılar çıkarılır.","İki farklı yöntemle çözüm sunulmuştur."]},"beginTime":1274,"endTime":1322,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1274&ask_summarization=1"},{"index":10,"title":"Kombinasyon Problemleri Çözümü","list":{"type":"unordered","items":["Beş ve on sayılarının çarpımlarının beşin katı olma durumları inceleniyor.","Ömer Hoca ile Fatma'nın yan yana olmaması durumunda, tüm durumdan yan yana geldiğini çıkarmak gerekiyor.","Özdeş boncuklar arasından en az bir boncuk seçme probleminde, durumlar düşünülerek çözüm bulunuyor."]},"beginTime":1328,"endTime":1488,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1328&ask_summarization=1"},{"index":11,"title":"Özdeş Boncuk Seçme Problemi","list":{"type":"unordered","items":["Özdeş boncuklar arasından seçim yaparken, toplam olarak kaç boncuk seçildiği düşünülerek durumlar belirleniyor.","Dört mavi ve üç beyaz boncuk arasından en az bir boncuk seçme probleminde, farklı durumlar incelenerek toplam 19 farklı seçim bulunuyor.","Özdeş boncuklar problemleri çözümünde dikkatli olunması gerekiyor çünkü bu tür sorular karmaşık olabilir."]},"beginTime":1488,"endTime":1680,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1488&ask_summarization=1"},{"index":12,"title":"Matematiksel İfadelerin Eşitliği","list":{"type":"unordered","items":["Verilen matematiksel ifadelerin eşitliği inceleniyor ve sadeleştirme işlemleri yapılıyor.","Eşitlikte k değerinin en büyük değerini alması durumunda, k değeri 50 olarak bulunuyor.","Karışım problemlerinin çözümünde tek bir yol var ve bu konu oynatma listesinde başlık olarak bırakılmış."]},"beginTime":1680,"endTime":1783,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1680&ask_summarization=1"},{"index":13,"title":"Karışım Problemi","list":{"type":"unordered","items":["Alkol oranı %k olan 100 gram karışım ile alkol oranı %3k olan 100 gram karışım birleştirildiğinde yeni karışımın alkol oranı hesaplanıyor.","Yeni oluşan karışımın alkol oranı %2k olarak bulunuyor.","Yeni oluşan karışımın alkol miktarı 250k olarak hesaplanıyor."]},"beginTime":1783,"endTime":1932,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1783&ask_summarization=1"},{"index":14,"title":"Hareket Problemi","list":{"type":"unordered","items":["Dakikada 64 metre hızla yürüyen Saffet, 969-976 metrelik asfalt yolu ve 25 metrelik kayalıkları geçiyor.","Saffet'in asfalt yolu üzerinde 15,25 dakika harcadığı hesaplanıyor.","Saffet'in toplam 16 dakikada B noktasına varması durumunda, kayalıklarda kalan 75 dakika saniyeye çevrilmeye başlanıyor."]},"beginTime":1932,"endTime":2038,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=1932&ask_summarization=1"},{"index":15,"title":"Matematik Problemleri Çözümü","list":{"type":"unordered","items":["Bir problemde 75 dakikada 45 saniyede harcanan süre hesaplanıyor ve 1 metre inme süresi 1,80 saniye olarak bulunuyor.","2,10 metre uzunluğundaki bir telin parçaları ardışık olarak 1 santim daha kısa olacak şekilde parçalanıyor ve en uzun parça 20 santim olarak hesaplanıyor.","Arda ve Ferda'nın iş bitirme hızları karşılaştırılıyor, Arda 4 saatte, Ferda 5 saatte bir işi bitiriyor ve birlikte çalıştıklarında 12,6 saatte işi bitirebilecekleri hesaplanıyor."]},"beginTime":2047,"endTime":2266,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=2047&ask_summarization=1"},{"index":16,"title":"Yaş Problemi ve Grafik Soruları","list":{"type":"unordered","items":["Esin ve Esen'in yaşları 9 ve 7 ile orantılıdır, 24 yıl sonra yaşları 15 ve 13 olacak şekilde hesaplanıyor ve Esen'in Esin'den 8 yaş küçük olduğu bulunuyor.","2014-2017 yılları arasındaki otomobil ve ikinci el otomobil satış sayıları inceleniyor, 2017'de otomobil satışları 10.000 adet olarak hesaplanıyor.","2015 yılında satılan sıfır otomobil sayısı 2014 yılına göre %20 arttığı bulunuyor."]},"beginTime":2266,"endTime":2548,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=2266&ask_summarization=1"},{"index":17,"title":"Restoran Masası Problemi","list":{"type":"unordered","items":["Bir restoranda 5 ve 7 kişilik masaların kapasitesi 83 kişi olacak şekilde en az 14 masanın olması gerektiği hesaplanıyor.","Eğer 5 kişilik masalarda 4 kişi otursa ve 7 kişilik masalarda 7 kişi otursa, en çok 17 masanın kullanılacağı bulunuyor."]},"beginTime":2548,"endTime":2709,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=2548&ask_summarization=1"},{"index":18,"title":"Matematik Problemleri Çözümü","list":{"type":"unordered","items":["Ardışık sayılardan oluşan bir soruda, toplam 326 top ve boş kalan sepet numarası 23 olarak bulunmuştur.","Sayısal mantık sorusunda, 1'den 9'a yazılan rakamların toplamı 45 olacak şekilde yerleştirilmesi istenmiştir.","Bir çemberde üçgen problemi çözülerek LKM açısı 75 derece olarak hesaplanmıştır."]},"beginTime":2718,"endTime":3098,"href":"/video/preview/4739328768963189191?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=2718&ask_summarization=1"},{"index":19,"title":"Geometri Problemleri","list":{"type":"unordered","items":["Yamuk probleminde, paralel kenarlar arasındaki oran hesaplanarak 16/5 cevabı bulunmuştur.","Koordinat düzleminde K ve L noktaları arasındaki uzaklık 3/10 birim olarak hesaplanmıştır.","Video boyunca 30 soru incelenmiş ve ağır usul, yavaş anlatım yöntemiyle çözümleri 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Eğitmen, cebirsel kısımdan 12 soruluk bir deneme sınavını adım adım çözmektedir.","Videoda rasyonel sayılar, ondalık sayılar, üslü sayılar, köklü sayılar, çarpanlara ayırma, tam sayı çeşitleri, doğal sayılar, EBOB, mutlak değer ve oran orantı gibi cebirsel konulardaki sorular ele alınmaktadır. Eğitmen her soruyu detaylı şekilde açıklamakta ve çözüm yöntemlerini göstermektedir.","Video sonunda eğitmen, KPSS'de cebirsel konuların 13-15 soru arasında çıkabileceğini ve bu bölümün detaylı çözümlerle yüksek net elde edilebileceğini belirtmektedir. Ayrıca soruların PDF'sinin videonun açıklama kısmında, topluluk bölümünde ve Instagram hesabında paylaşıldığı bilgisi verilmektedir."]},"endTime":1065,"title":"KPSS Matematik: Cebirsel Kısım Deneme Sınavı Çözümü","beginTime":0}],"fullResult":[{"index":0,"title":"Cebirsel Deneme Sınavı Tanıtımı","list":{"type":"unordered","items":["Ömer Hoca, cebirsel kısımdan on iki soruluk bir deneme sınavı yapacağını belirtiyor.","Soruların PDF'si videonun açıklama kısmında ve kanalın topluluk bölümünde paylaşılacak.","Sorular Instagram adresinde \"mat zamanı\" isimli hesapta da paylaşılmış durumda."]},"beginTime":8,"endTime":42,"href":"/video/preview/16115713778663372496?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=8&ask_summarization=1"},{"index":1,"title":"Deneme Sınavının Amacı","list":{"type":"unordered","items":["Deneme sınavının amacı öğrencilerin kendilerini sınayıp eksiklerini belirlemeleri ve önlem alabilmeleri.","Sorular rasyonel 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Öğretmen, öğrencilere çeşitli matematik sorularını adım adım çözerek anlatmaktadır.","Videoda cebirsel konular, köklü sayılar, mutlak değer, çarpanlara ayırma, fonksiyonlar, olasılık, oran-orantı ve top problemleri gibi farklı matematik konularındaki sorular ele alınmaktadır. Öğretmen her soru için çözüm yöntemlerini detaylı olarak göstermekte ve ÖSYM'nin sevdiği kurallar hakkında bilgiler vermektedir.","Özellikle faktöriyel ve tam sayı çeşitleri konularının önlisans ve lisans sınavlarında sıkça çıktığı belirtilmektedir. Video sonunda öğretmen, çözümlü denemenin PDF'sini eklemeyi unuttuğunu ve izleyicilerin yorum bölümünde belirtmesi durumunda bunu paylaşabileceğini söylemektedir."]},"endTime":1671,"title":"KPSS Matematik Soru Çözüm Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"KPSS 2022 Cebirsel Kısım Soru Çözümü","list":{"type":"unordered","items":["Ömer Hoca, KPSS 2022 cebirsel kısmından deneme altı soru çözümüne devam ediyor.","Videoda düşürücü sorular üstüne basa basa anlatılacak ve çıkmış olan tarzlara da değinilecek."]},"beginTime":12,"endTime":48,"href":"/video/preview/9166955812849433606?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=12&ask_summarization=1"},{"index":1,"title":"İşlem Öncelikleri ve Üslü Sayılar","list":{"type":"unordered","items":["İlk soruda işlem önceliklerine dikkat edilerek paydalar eşitlenerek ve ters çevirip çarpma işlemi yapılarak çözüm bulunuyor.","Üslü sayılarla ilgili sorularda bir sayının sıfırıncı 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Öğretmen, öğrencilere hitap ederek köklü sayılar ve denklemler konusunu adım adım anlatmaktadır.","Video, köklü sayılar konusunun temel özellikleri ile başlayıp, derece eşitleme, paydayı rasyonelleştirme ve kök içindeki gizli tam kare bulma gibi temel kuralları açıklamaktadır. 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Ömer Hoca, öğrencilere matematik konularını anlatmaktadır.","Videoda iki temel matematik kuralı ele alınmaktadır: \"İki Kural\" ve \"Eşlilik Bilgisi\". Ömer Hoca önce \"İki Kural\"ı açıklamakta, bu kuralın tam kare ifadelerin pratik uygulaması olduğunu ve beş farklı soru tipinde kullanıldığını belirtmektedir. Ardından \"Eşlilik Bilgisi\"ni anlatmakta, bu bilginin paydasını rasyonelleştirmek için kullanıldığını ve tek terim veya iki terimden oluşabileceğini açıklamaktadır. Video, bu kuralların bir soru üzerinden uygulamalı olarak gösterilmesiyle devam etmektedir."]},"endTime":335,"title":"Matematik Dersinde İki Kural ve Eşlilik Bilgisi","beginTime":0}],"fullResult":[{"index":0,"title":"İki Kuralı ve Eşlilik Bilgisi","list":{"type":"unordered","items":["Videoda iki kural ve beş farklı soru tipi ele alınacak.","İki kuralı, köprü sayılarda iki sayının çarpımı ve toplamının belirli bir ifadeyi vermesi prensibine dayanır.","Eşlilik bilgisi, köprü sayının paydasını rasyonelleştirmek için kullanılır ve tek terimden veya iki terimden oluşabilir."]},"beginTime":0,"endTime":35,"href":"/video/preview/12221685402657842714?parent-reqid=1769396486804204-1314229950358037476-balancer-l7leveler-kubr-yp-vla-178-BAL&text=Mat+Time&t=0&ask_summarization=1"},{"index":1,"title":"İki Kuralı Uygulaması","list":{"type":"unordered","items":["Köprü sayılarda iki kuralı, iki sayının çarpımı ve toplamının belirli bir ifadeyi vermesi prensibine dayanır.","İki kuralı, tam karenin 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