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Eğitmen, iki farklı molekül örneği üzerinden kiralite merkezlerinin nasıl belirleneceğini, moleküllerin ayna görüntülerinin nasıl alınacağını ve moleküllerin kiral olup olmadığını nasıl anlayacağımızı detaylı şekilde açıklamaktadır. İlk örnek bir kiral molekül, ikinci örnek ise iki kiralite merkezi bulunan ancak bir bütün olarak kiral olmayan bir moleküldür."]},"endTime":527,"title":"Organik Kimya Dersinde Kiral Moleküllerin Tanımlanması","beginTime":0}],"fullResult":[{"index":0,"title":"Kiralite Merkezlerin Tanımlanması","list":{"type":"unordered","items":["Kiralite merkezi, kiral atom veya asimetrik karbon olarak da adlandırılır ve bir molekülün kiral olup olmadığını belirler.","Kiralite merkezindeki atom dört farklı gruba bağlı olmalıdır, aksi takdirde kiralite merkezi olamaz.","Karbon atomunun bağlı olduğu atomlar değil, bağlı olduğu gruplar önemlidir."]},"beginTime":3,"endTime":56,"href":"/video/preview/13254601842872705851?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=3&ask_summarization=1"},{"index":1,"title":"İlk Molekül Örneği","list":{"type":"unordered","items":["İlk molekülde dördüncü karbon atomu iki metil grubu, bir OH molekülü ve bir hidrojen 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Moleküllerin iki ana kategorisi olan diatomik (iki atomlu) ve poliatomik (iki'den fazla atomlu) moleküller detaylı olarak ele alınmaktadır. Ayrıca hidrojen gazı, su, azot, oksijen, flor, klor, brom, altın ve iyot gibi diatomik moleküller ile hidrojen klorür, karbon monoksit, karbondioksit, ozon ve amonyak gibi poliatomik moleküller örneklerle açıklanmaktadır. Video, moleküllerin periyodik cetvelle ilişkisine de değineceğini belirterek sonlanmaktadır."]},"endTime":399,"title":"Kimya Dersi: Molekül Kavramı","beginTime":0}],"fullResult":[{"index":0,"title":"Molekül Kavramı","list":{"type":"unordered","items":["Bu videoda kimyada önemli bir konu olan molekül kavramı ele alınacaktır.","Molekül, en az iki atomun belli bir düzende kimyasal kuvvetlerle (bağlarla) bir arada tutulduğu atomlar topluluğudur.","Bir molekülde tek bir elementin atomları bulunabileceği gibi, iki veya daha çok sayıda elementin atomları sabit oranlar yasasına uygun bir biçimde birleşmiş olarak bulunabilir."]},"beginTime":1,"endTime":54,"href":"/video/preview/16028999688643741096?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1&ask_summarization=1"},{"index":1,"title":"Molekül ve Bileşik İlişkisi","list":{"type":"unordered","items":["Bileşikler tanımı gereği birden çok element içerdiklerine göre her molekül bileşik olmayabilir.","Hidrojen gazı saf bir element olmasına rağmen iki tane hidrojen atomu içermesinden dolayı moleküllerden oluşur.","Su, hidrojen ve oksijen içeren molekülleri birleştirip bir bileşiktir ve su molekülünde hidrojen atomlarının oksijen atomları oranı ikiye bir katıdır."]},"beginTime":54,"endTime":109,"href":"/video/preview/16028999688643741096?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=54&ask_summarization=1"},{"index":2,"title":"Diatomik Moleküller","list":{"type":"unordered","items":["Hakiki olarak gösterilen hidrojen molekülüne atomik (diatomik) element denilebilir.","Diatomik molekül, kendiliğinden oluştuğu iki atomludur.","Normal olarak iki atomlu moleküller halinde bulunan diğer elementler arasında azot (N₂), oksijen (O₂), flor (F₂), klor (Cl₂), brom (Br₂) ve iyot (I₂) bulunmaktadır."]},"beginTime":109,"endTime":213,"href":"/video/preview/16028999688643741096?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=109&ask_summarization=1"},{"index":3,"title":"Diatomik Bileşikler","list":{"type":"unordered","items":["İki atomlu moleküller farklı elementlerin atomlarından da oluşabilir.","Hidrojen klorür (HCl) ve karbon monoksit (CO) diatomik bileşiklerdir.","Moleküllerin büyük çoğunluğu iki'den çok daha fazla atom içerir."]},"beginTime":213,"endTime":265,"href":"/video/preview/16028999688643741096?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=213&ask_summarization=1"},{"index":4,"title":"Poliatomik Moleküller","list":{"type":"unordered","items":["Moleküllerin büyük çoğunluğu ikiden fazla atom içerdiğine göre bunlara poliatomik (çok atomlu) moleküller de denenebilir.","Ozon (O₃), su (H₂O) ve amonyak (NH₃) poliatomik moleküllerdir.","Amonyak gösteriminde bazı kitaplarda NH₃, bazılarında NH₃ şeklinde gösterilebilir."]},"beginTime":265,"endTime":396,"href":"/video/preview/16028999688643741096?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=265&ask_summarization=1"}],"linkTemplate":"/video/preview/16028999688643741096?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Molekül Nedir? 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videoyu izleyerek molekül çeşitlerini ve molekül yapımını öğrenmiş olacaksınız. Video konu anlatımı pdf indirme linki -- https://bit.ly/3hKXuLo Video sizin için faydalı olduysa desteğinizi...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/1655134/4049b20bbad638a09f4b35e25b74e3bd/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/BMOWWwEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"6","reqid":"1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL","summary":{"fullTextUrl":"/int_search_summary?data=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3Db5vVV2GnckE","linkTemplate":"/video/preview/16736560591663993303?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Moleküller konu anlatımı 7.sınıf","related_orig_text":"Molegul","related_porno":false,"related_less_3m_off":true,"client":"d2d","no_cnt":1,"related_src":"serp","related":"{\"porno\":false,\"vfp\":1,\"orig_text\":\"Molegul\",\"url\":\"http:\\/\\/www.youtube.com\\/watch?v=b5vVV2GnckE\",\"src\":\"serp\",\"rvb\":\"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_E-sGggQkAYAEKyqLARABGniB_v33_f8CAPz1CAD7Bf4C-ggSBPn-_QD7BQEICAT-APXwCfz-AAAA7fn7AgAAAAAO-_4L9_8AABcAA_4FAAAADPH9__oAAAD_CPH9_wEAAP8F-_8D_wAAEAP48v8AAAD-DQUKAQAAAAwI-fwBAAAABOUB_wEAAAAgAC0Kb9k7OBNACUhOUAIqhAIQABrwAX30NP7RENYA0xXXACwDxQG3Pg8AVwzYAJPrQAKx7QUA7Am8_9rk8QAmzS7_2hD8_03zvv_b_OoAEhEN_zcGNAEbS-gAFNhLAlfwBgDuJRL-4Uv6_-4CEAP5Aer9CQ_q_iohJgAdIt_9HO_sA8PjKQNXGAUDR78b_7869QbNCRcEwtTA-kz8-gMHGQsGtRL8A_vd4QEBCf0K_hbnAPu09wQM4v4HJ_r6C0IL7_oY6BX4-gER8t_48f4l-CsH-BXrBTUBEvgF0-335ykMBH_fB__yAOYDMR0CDBQLCv0y_hjt2RsAAwISAPfb8fwQEfPjAiAALW289Do4E0AJSGFQAipzEAAaYBoBACfrF_4P-DX6BPhXEvu-8fILwhb_AP4A-gnqtiv4_u4uGQA-FzziqgAAAE3f7O8LAAJutvv7Ke36_7O6-_8GfxY7ZvnaMQwZ7TTq-SZPDAnmAADxGqbYS96lDkf0ESAALc_LHjs4E0AJSG9QAiqvBhAMGqAGAADAQQAAuEEAAKjBAADgwAAAlsIAAAzCAABAQQAAEEEAAMBAAACwQQAAVMIAAHDBAAAUwgAABMIAAIBAAACwwQAAyEEAAIDCAABwQgAAwEAAAIC_AACIwQAAskIAABBBAAAgwQAAoEEAAL7CAABgQQAA0EEAAFDBAAAAwgAAUEIAAKjBAACQQQAAWMIAAKhBAADIQQAAsEIAAKjBAADAQAAAFMIAABTCAAAwQgAAQEEAAKjBAAAAwAAAsEEAACBBAADYwQAAJEIAAHDBAAAAQQAAgL8AAABCAAA4QgAAoEAAAMzCAACAwAAA4EAAAIBBAAAUQgAAlMIAAKxCAAAwQQAAAMIAAMhBAAC0wgAAwMAAANhBAACowQAAqEEAAGBBAACgwgAAAEAAAIC_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_AAAwvQAATL4AAOC8AAAQPQAAiD0AAKI-AABEvgAADD4AAFw-AACgvAAAlj4AAHw-AAAcvgAAsr4AAFA9AADgPAAAiL0AADk_AADCPgAAfz8AAEC8AABEPgAABD4AANi9AAC4vQAA4LwAAGw-AADgvAAA4DwAADC9AACovQAAgj4AAGQ-AABEvgAARL4AAGQ-AAC2vgAAAb8AAAy-AACePgAAJD4AAEw-AAAQvQAAsj4AADy-AADIvQAAuL0AAMg9AAAkvgAA-D0AAAw-AABcPgAAEL0AAPg9AAD4PQAAuj4AANg9AAAQPQAAFD4AAAG_AAAwPQAAhr4AAHy-IAA4E0AJSHxQASqPAhABGoACAAAUvgAAcD0AABS-AABRvwAAoLwAAI4-AADmPgAAoLwAABC9AADYPQAAqD0AAOC8AABEvgAATL4AACQ-AACAOwAADL4AAPI-AADSvgAAoj4AABS-AAAwPQAAJL4AANi9AACAOwAAZL4AACS-AADgvAAA-L0AAHy-AAAQPQAAyD0AADy-AACmvgAAHD4AAEC8AADYPQAAXD4AALa-AABwvQAA6L0AABS-AACgvAAAQLwAABA9AAAcvgAAf78AAEQ-AABEPgAAoDwAANg9AACAuwAADD4AAOC8AABwPQAAUD0AAIC7AACgvAAADD4AABC9AABQPQAAgDsAAIo-AABkPiAAOBNACUh8UAEwCTgBSgBgAGgA\"}","related_url":"http://www.youtube.com/watch?v=b5vVV2GnckE","parent-reqid":"1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL","related_vfp":1,"relatedVideo":"yes"},"cwidth":1920,"cheight":932,"cratio":2.06008,"dups":["16736560591663993303"],"episode":0,"season":0,"isEmbedOnly":false,"greenHost":"YouTube","hasTranslation":true,"contentTypeId":null,"censored":false,"videoContentId":"2007599576"},"8751624753760455914":{"videoId":"8751624753760455914","docid":"34-1-8-ZE7597413D91978DE","description":"Her gün en yeni eğitim videolarını ilk izleyen olmak için kanalımıza abone olun. Daha fazlası ve ders videolarını sıralı izlemek için: https://www.khanacademy.org.tr Matematikten sanat tarihine...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/3142607/f593d56b5980997427a030f717365dfd/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/k9ZAjgAAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"7","reqid":"1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=videoid:8751624753760455914","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitimci tarafından sunulan kimya dersi formatında hazırlanmış bilgilendirici bir içeriktir.","Video iki ana bölümden oluşmaktadır. İlk bölümde molekülleri ifade etmek için kullanılan üç temel formül türü (molekül formülü, ampirik formül ve yapı formülü) detaylı şekilde açıklanmakta ve periyodik tablo kullanılarak molekül kütlesinin nasıl hesaplanacağı gösterilmektedir. İkinci bölümde ise periyodik tabloda \"geçiş metalleri\" olarak adlandırılan grupların aslında \"zayıf metaller\" olarak da adlandırıldığı ve bu metallerin özellikleri anlatılmaktadır.","Videoda benzin, su, kükürt ve glikoz gibi çeşitli moleküller üzerinden formül hesaplamaları ve kütle bileşimleri örneklerle açıklanırken, zayıf metallerin daha yumuşak, daha düşük erime noktasına sahip, elektron verme özelliğinin daha az olduğu ve elektronegatiflik değerlerinin daha yüksek olduğu vurgulanmaktadır."]},"endTime":775,"title":"Kimya Eğitim Videosu: Molekül Formülleri ve Zayıf Metaller","beginTime":0}],"fullResult":[{"index":0,"title":"Molekülleri İfade Etme Yöntemleri","list":{"type":"unordered","items":["Molekülleri ifade etmek için üç temel yöntem vardır: molekül formülü, ampirik formül ve yapı formülü.","Ampirik formül, gözlemlerle veya deneylerle elde edilen sonuçları gösterir ve molekülün içindeki atomların oranını belirtir.","Molekül formülü ise molekülün içindeki atom sayısına bağlıdır ve molekülün içindeki atomların sayısını gösterir."]},"beginTime":4,"endTime":148,"href":"/video/preview/8751624753760455914?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=4&ask_summarization=1"},{"index":1,"title":"Ampirik Formül ve Molekül Formülü Arasındaki İlişki","list":{"type":"unordered","items":["Molekül formülünden ampirik formüle ulaşmak kolaydır; molekülün içindeki atom sayısının EBOB'unu bulup, molekül formülünü bu sayıya bölerek basit formülü elde edebiliriz.","Tam tersi işlem (molekül formülünden ampirik formüle geçiş) çok zordur ve bazı bilgileri kaybetmeyi gerektirir.","Yapı formülü, molekül formülündeki atomların nasıl yerleştiğini gösterir ve molekül hakkında en çok bilgiyi verir."]},"beginTime":148,"endTime":250,"href":"/video/preview/8751624753760455914?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=148&ask_summarization=1"},{"index":2,"title":"Formül Örnekleri","list":{"type":"unordered","items":["Su molekülünün molekül formülü H₂O'dur ve ampirik formülü de H₂O'dur çünkü her bir oksijen için iki tane hidrojen vardır.","Kükürt molekülünün molekül formülü S₈'dir ve ampirik formülü S'dir çünkü tek bir atomdan oluşur.","Glukoza molekülünün molekül formülü C₆H₁₂O₆'dır ve ampirik formülü C₂H₅O'dur çünkü her altı karbon için oniki hidrojen ve altı oksijen vardır."]},"beginTime":250,"endTime":357,"href":"/video/preview/8751624753760455914?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=250&ask_summarization=1"},{"index":3,"title":"Molekül Kütlesi ve Kütle Bileşimi","list":{"type":"unordered","items":["Molekül kütlesi, bir molekül içinde bulunan bütün atomların kütlelerinin toplamıdır.","Karbonun atom kütlesi yaklaşık 12 atomik kütle birimidir ve hidrojen atom kütlesi 1 atomik kütle birimidir.","Benzinin molekül kütlesi 78 atomik kütle birimidir ve içindeki karbon yüzdesi yaklaşık %92,30'dur.","Suyun molekül kütlesi 18 atomik kütle birimidir ve içindeki oksijen yüzdesi yaklaşık %88,90'dur."]},"beginTime":357,"endTime":660,"href":"/video/preview/8751624753760455914?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=357&ask_summarization=1"},{"index":4,"title":"Metallerin Özellikleri ve Periyodik Tabloda Gruplandırma","list":{"type":"unordered","items":["Bazı metallerin daha iyi iletken olduklarını anlamak için araştırma yapılıyor.","Periyodik tabloda d orbitallerini kısmen dolduran geçiş metalleri bulunuyor.","Araştırmada kullanılan kitapta bu gruba \"metaller\" denirken, diğer gruba \"geçiş metalleri\" denmesi garip 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fazlası için: http://www.khanacademy.org.tr Matematikten sanat tarihine, ekonomiden fen bilimlerine, basit toplamadan diferansiyel denklemlere, ilkokul seviyesinden üniversite seviyesine...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/1023253/9cfb3a2110fa8be4b26bb8d333ba7a0a/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/PgzcawAAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"8","reqid":"1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=videoid:14915340172798119288","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitimci tarafından sunulan kimya dersi formatındadır. Eğitimci, molekül kütlesi kavramını açıklamaktadır.","Video, su molekülünün (H₂O) molekül kütlesini hesaplama örneği üzerinden molekül kütlesi kavramını anlatmaktadır. Önce hidrojen ve oksijen atomlarının kütlesinin periyodik tablodan nasıl bulunacağı, ardından bu atomların izotopları ve ortalama atom kütlesinin nasıl hesaplanacağı açıklanmaktadır. Son olarak, tek bir su molekülünün kütlesinin ve bir bardak su içindeki moleküllerin ortalama kütlesinin nasıl hesaplanacağı gösterilmektedir. Video, molekül ağırlığı kavramının fizikteki ağırlık kavramından farklı olduğunu da vurgulamaktadır."]},"endTime":457,"title":"Molekül Kütlesi Kavramı Eğitim Videosu","beginTime":0}],"fullResult":[{"index":0,"title":"Molekül Kütlesi Kavramı","list":{"type":"unordered","items":["Bu videoda molekül kütlesi kavramıyla yakından ilgilenilecek.","Vücudumuzun büyük bir kısmı su molekülünden oluşur ve su molekülünün formülü H₂O'dur.","Her su molekülü iki tane hidrojen atomu ve bir tane oksijen atomu içerir."]},"beginTime":0,"endTime":44,"href":"/video/preview/14915340172798119288?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=0&ask_summarization=1"},{"index":1,"title":"Atomların Kütlesi","list":{"type":"unordered","items":["Hidrojenin atom numarası bir olup, proton sayısı bir ve ortalama atom kütlesi 1,7'dir.","Bir atomik kütle birimi, bir tane nötronun ve bir tane protonun kütlelerinin toplamını yaklaşık olarak ifade eder.","Hidrojenin 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İçerik, molekül gösterim şekilleri (açık formül, yarı açık formül, çizgi iskelet modeli, uzay top modeli), kütlece yüzde birleşim hesaplamaları, yanma tepkimeleri ve gazların özkütlesi kullanılarak molekül formülünün bulunması gibi konuları kapsamaktadır.","Öğretmen, her konuyu adım adım açıklayarak, farklı soru tiplerini çözerek pratik çözümler sunmakta ve öğrencilerin bu konuyu daha iyi anlamaları için çeşitli örnekler vermektedir. Video boyunca C₃H₈O₂ gibi organik bileşiklerin yanma denklemleri üzerinden formül bulma yöntemleri detaylı olarak gösterilmektedir."]},"endTime":1776,"title":"Karbon Kimyasında Basit ve Molekül Formülleri Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"Basit ve Molekül Formülleri","list":{"type":"unordered","items":["Karbon kimyasına giriş ünitesinde basit ve molekül formlarının nasıl bulunacağı incelenecek.","Gerçek formül, organik bileşikteki elementlerin gerçek atom sayılarını gösterirken, basit formül (kaba formül) elementlerin türünü ve atom sayılarının oranını verir.","Basit formül, molekül formülüne en uygun sayıda çarpılarak veya basit formülün kütlesi biliniyorsa, gerçek formülün kütlesi bulunabilir."]},"beginTime":11,"endTime":120,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=11&ask_summarization=1"},{"index":1,"title":"Yapı Formülleri","list":{"type":"unordered","items":["Açık formül (yapı formülü), moleküldeki atomların gerçek sayıları ve bağlanma şekillerini gösterir.","Çizgi iskelet gösterimde hidrojenler yazılmaz ve her bir karbon atomu dört bağ yapabilitesi vardır.","Uzay top modeli de molekülün yapısını göstermek için kullanılan bir gösterim şeklidir."]},"beginTime":120,"endTime":206,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=120&ask_summarization=1"},{"index":2,"title":"Örnekler ve Hesaplamalar","list":{"type":"unordered","items":["Molekül formülleri verilen maddelerin basit formülleri, formüldeki sayıları en uygun şekilde sadeleştirerek bulunabilir.","Basit formülü ve mol kütlesi bilinen bir bileşikte, basit formülün kütlesi hesaplanıp gerçek formülün kütlesine bölünerek gerçek formül bulunabilir.","Kütle yüzde birleşimi, bileşikteki elementin sahip olduğu kütleyi toplam kütle oranı ile yüzde çarpılarak hesaplanabilir."]},"beginTime":206,"endTime":460,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=206&ask_summarization=1"},{"index":3,"title":"Organik Bileşiklerin Formülleri","list":{"type":"unordered","items":["Gerçek formülün basit formülünü hesaplamak için molekülün modellerini bulup, karbon ve hidrojen altına yazmak gerekir.","Örneğin, karbon 36, hidrojen 12'den 3 mol hidrojen ise, 6 mol hidrojen bulunur ve molekül formülü C₃H₆ şeklinde yazılır.","Basit formül, molekül formülünün 360'a bölünmesiyle bulunur, örneğin C₃H₆'ın basit formülü CH₂'dir."]},"beginTime":465,"endTime":496,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=465&ask_summarization=1"},{"index":4,"title":"Organik Bileşiklerin Molekül Formülü Bulma","list":{"type":"unordered","items":["Organik bileşiğin tam verimli yakılmasına ait mor sayısı zaman değişim grafiği kullanılarak molekül formülü bulunabilir.","Yakma tepkimesinde oksijen, karbondioksit ve su miktarları ölçülerek katsayılar belirlenir.","Örnekte, 2 mol oksijen, 6 mol karbondioksit ve 8 mol su oluştuğunda, molekül formülü C₃H₈O₂ olarak bulunur."]},"beginTime":496,"endTime":581,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=496&ask_summarization=1"},{"index":5,"title":"Nicel Analizle Molekül Formülü Hesaplama","list":{"type":"unordered","items":["Karbon, hidrojen ve oksijenden oluşan bir organik bileşiğin nicel analizinde kütlece %40'ı karbon, %6,66'ı hidrojen bulunmuştur.","Bileşiğin molekül ağırlığı 180 gram/mol olduğuna göre, karbonun miktarı 72 gram olarak hesaplanır.","Karbonun mol sayısı 6 olarak bulunur ve molekül formülü CH₆ olarak belirlenir."]},"beginTime":581,"endTime":631,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=581&ask_summarization=1"},{"index":6,"title":"Hidrojen Oranı Hesaplama","list":{"type":"unordered","items":["180'in %6,66'sı hidrojen olduğundan, 180×6,66=11,98 gibi bir değer elde edilir ve bu değer 12'ye çok yakın olduğu için doğrudur.","Karbon, hidrojen ve oksijen içeren bir organik bileşiğin 12,40 gramı yakıldığında 4 mol karbondioksit ve 6 mol su oluşmaktadır.","Bu soruda farklı yöntemlerle çözüm yapılabilir, ancak temel prensip kütlenin korunumu kanunudır."]},"beginTime":633,"endTime":747,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=633&ask_summarization=1"},{"index":7,"title":"Karbondioksit ve Su Analizi","list":{"type":"unordered","items":["Yakılan bileşikte kaç gram karbon varsa, karbondioksitte de o kadar karbon vardır; kaç tane hidrojen varsa, hidrojende de o kadar hidrojen vardır.","4 mol karbondioksit 4,80 gram karbon, 6 mol su 1,20 gram hidrojen içerir.","Toplam kütleden karbon ve hidrojen kütlesi çıkarıldığında oksijen kütlesi bulunur ve bu değerle birlikte karbon, hidrojen ve oksijen oranları hesaplanır."]},"beginTime":747,"endTime":820,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=747&ask_summarization=1"},{"index":8,"title":"Basit Formül Hesaplama","list":{"type":"unordered","items":["Bulunan oranlar (karbon: 0,40, hidrojen: 1,20, oksijen: 0,40) uygun sayılarla sadeleştirilerek basit formül bulunur.","Molekül formülü bulmak için molekül formülünün kütlesini vermek gerekir.","Karbon ve hidrojen içeren bileşiklerde oksijen yoksa, basit formül doğrudan molekül formülüdür."]},"beginTime":820,"endTime":908,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=820&ask_summarization=1"},{"index":9,"title":"Hidrokarbon Örneği","list":{"type":"unordered","items":["Mol kütlesi 30 gram olan bir bileşiğin 0,10 mol oksijen gazı ile yakıldığında 4,48 litre karbondioksit ve 5,40 gram su oluşmaktadır.","Hidrokarbon, yapısına sadece karbon ve hidrojen içeren organik bileşiklerdir.","4,48 litre karbondioksit 0,20 mol, 5,40 gram su 0,30 mol olduğundan, bileşik C₂H₆ molekül formülüne sahiptir."]},"beginTime":908,"endTime":1012,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=908&ask_summarization=1"},{"index":10,"title":"Oksijen İçeren Bileşik Örneği","list":{"type":"unordered","items":["Bir organik bileşenin 30,40 gramının yanmasıyla 1,20 mol karbondioksit ve 1,60 mol su oluşmaktadır.","1,20 mol karbondioksit 14,40 gram karbon, 1,60 mol su 3,20 gram hidrojen içerir.","Toplam kütleden karbon ve hidrojen kütlesi çıkarıldığında 18,80 gram oksijen bulunur ve bileşik C₃H₈₂ basit formülüne sahiptir."]},"beginTime":1012,"endTime":1195,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1012&ask_summarization=1"},{"index":11,"title":"Organik Bileşiklerin Basit ve Molekül Formülü Hesaplamaları","list":{"type":"unordered","items":["Bir hidrokarbonun basit formülü hesaplanırken, karbon ve hidrojen atomlarının emaları bulunup uygun sayılarla çarpılarak tam sayılı hale getirilir.","Organik bileşiğin yakılması sonucunda oluşan karbondioksit ve su mol sayıları eşit olup olmadığı, bileşik formülüne göre belirlenir.","Bir hidrokarbonun basit formülü, bileşikteki elementlerin kütlece birleşme oranlarını gösterir ve bu formülden atomların türü ve kütlece birleşme oranları tespit edilebilir."]},"beginTime":1203,"endTime":1448,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1203&ask_summarization=1"},{"index":12,"title":"Gaz Fazındaki Hidrokarbonların Molekül Formülü","list":{"type":"unordered","items":["Gaz fazındaki bir hidrokarbonun molekül formülü hesaplanırken, özkütlesi ve basit formülü kullanılarak mol kütlesi bulunur.","Normal koşullarda (0°C ve 1 atm) gazların formülü P = nRT'dir ve bu formül kullanılarak mol kütlesi hesaplanabilir.","Molekül formülü, basit formülün uygun sayılarla çarpılarak elde edilir."]},"beginTime":1448,"endTime":1515,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1448&ask_summarization=1"},{"index":13,"title":"Organik Bileşiklerin Yakılması ve Formül Hesaplamaları","list":{"type":"unordered","items":["Karbon, hidrojen ve oksijenden oluşan bir organik bileşiğin yakılması sonucunda oluşan karbondioksit ve su kütleleri arasındaki ilişki, bileşik formülünü belirlemek için kullanılır.","Kütlenin korunumu kanunu, organik bileşiğin toplam kütlesini hesaplamak için kullanılır.","Basit formül, bileşikteki elementlerin atom kütleleri ve kütlece birleşme oranları kullanılarak bulunabilir."]},"beginTime":1515,"endTime":1633,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1515&ask_summarization=1"},{"index":14,"title":"Glikoz Örneği ve Bileşik Formülleri","list":{"type":"unordered","items":["Glikozun molekül formülü C₆H₁₂O₆, basit formülü ise CH₂O şeklindedir.","Basit formül ve elementlerin atom kütleleri bilindiğinde, elementlerin kütlece birleşme oranları tespit edilebilir.","Basit formül ve molekül formülü aynı olan bileşikler olabilir, ancak basit formülü aynı molekül formülü farklı olan bileşikler de olabilir."]},"beginTime":1633,"endTime":1767,"href":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1633&ask_summarization=1"}],"linkTemplate":"/video/preview/11752266584857542881?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Basit Formül ve Molekül Formülü Bulma | Organik-2 | AYT Kimya 2021 | 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fazlası için: http://www.khanacademy.org.tr Matematikten sanat tarihine, ekonomiden fen bilimlerine, basit toplamadan diferansiyel denklemlere, ilkokul seviyesinden üniversite seviyesine...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/471039/ac60acdd6806f65b0db91369377c4e25/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/FGPk2wAAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"16","reqid":"1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=videoid:18075769101215289027","teaser":[{"list":{"type":"unordered","items":["Bu video, kimya dersi formatında bir eğitim içeriğidir. Anlatıcı, benzin molekülünün kütlece yüzde kaçının karbon, yüzde kaçının hidrojen olduğunu hesaplamayı adım adım göstermektedir.","Video, benzin molekülünün altı karbon ve altı hidrojen atomundan oluştuğunu açıklayarak başlıyor. Anlatıcı önce periyodik tablodan elementlerin atom ağırlıklarını bulup, benzin molekülünün toplam kütlesini hesaplıyor. Ardından karbonun ve hidrojenin kütlesini hesaplayarak, molekülün kütlesinin yaklaşık %92'sinin karbondan geldiğini gösteriyor. Video boyunca hesaplamalar detaylı olarak anlatılıyor ve anlamlı rakam kavramı vurgulanıyor."]},"endTime":333,"title":"Benzin Molekülünün Karbon ve Hidrojen Yüzdesi Hesaplama","beginTime":0}],"fullResult":[{"index":0,"title":"Benzen Molekülünün Kütle Hesaplaması","list":{"type":"unordered","items":["Benzen molekülü altı karbon ve altı hidrojen atomundan oluşmaktadır.","Atomların gerçek ağırlıklarıyla hesaplama yapılacaktır.","Periyodik tablodan elementlerin atom ağırlıklarına bakarak benzenin molekül kütlesi hesaplanacaktır."]},"beginTime":0,"endTime":50,"href":"/video/preview/18075769101215289027?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=0&ask_summarization=1"},{"index":1,"title":"Karbon ve Hidrojenin Atom Ağırlıkları","list":{"type":"unordered","items":["Karbonun atom ağırlığı 12,1 atomik kütle birimidir.","Hidrojenin atom ağırlığı 1,79 atomik kütle birimidir.","Bu değerler doğada bulunan tüm izotopları kullanılarak belirlenen ortalama ağırlık değerleridir."]},"beginTime":50,"endTime":112,"href":"/video/preview/18075769101215289027?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=50&ask_summarization=1"},{"index":2,"title":"Benzen Molekülünün Kütlesi","list":{"type":"unordered","items":["Benzen molekülünün kütlesi, karbon ve hidrojenin atom ağırlıklarının toplamına eşittir.","Karbonun toplam kütlesi 6×12,1 = 72,66 atomik kütle birimidir.","Hidrojenin toplam kütlesi 6×1,79 = 6,474 atomik kütle birimidir.","Benzen molekülünün kütlesi 72,66+6,474 = 78,113 atomik kütle birimidir."]},"beginTime":112,"endTime":198,"href":"/video/preview/18075769101215289027?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=112&ask_summarization=1"},{"index":3,"title":"Karbon ve Hidrojenin Yüzdesi","list":{"type":"unordered","items":["Karbonun yüzdesi: 72,66/78,113 ≈ 0,92259 (yaklaşık %92,259)","Hidrojenin yüzdesi: 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sevgili 9.sınıf öğrencileri 2024-2025 eğitim öğretim yılı yeni müfredata uygun kimya derslerine devam ediyoruz. Bu Dersimizde yeni müfredata göre; 2.TEMA - 1.Konu \"Etkileşimler\"...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/2732945/ce3609d261234dc89ad3e59d5ce198f5/564x318_1"},"target":"_self","position":"17","reqid":"1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=videoid:16249928152493662216","teaser":[{"list":{"type":"unordered","items":["Bu video, bir kimya öğretmeninin 9. sınıf öğrencileri için hazırladığı eğitim içeriğidir. Öğretmen, yeni müfredata uygun olarak kimya konularını anlatmaktadır.","Video, \"Çeşitlilik\" temasındaki \"Etkileşim\" ünitesinden \"Molekül Polarlığı ve Apolarlığı\" konusunu ele almaktadır. İçerikte polar ve apolar moleküllerin temel özellikleri, Lewis nokta yapısı çizme yöntemi ve moleküllerin polar veya apolar olup olmadığını belirleme teknikleri detaylı olarak açıklanmaktadır. Ayrıca, molekül içi bağların polarlığı ile molekülün polarlığı arasındaki ilişki çeşitli molekül örnekleri üzerinden gösterilmektedir.","Videoda HF, H₂O, NH₃, HCl, CH₄, PCl₃, CO₂ gibi çeşitli moleküllerin Lewis yapıları çizilerek, elektron yük dağılımları analiz edilmekte ve dipol momentleri hesaplanmaktadır. Video, bir sonraki derste iyonik bağlı bileşiklerin adlandırması ve kovalent bağlı bileşiklerin adlandırması konularının işleneceği bilgisiyle sonlanmaktadır."]},"endTime":1867,"title":"9. Sınıf Kimya Dersi: Molekül Polarlığı ve Apolarlığı","beginTime":0}],"fullResult":[{"index":0,"title":"Molekül Polarlığı ve Apolarlığı Konusuna Giriş","list":{"type":"unordered","items":["Dokuzuncu sınıf kimya derslerinde yeni müfredata uygun ikinci dönem konuları inceleniyor.","Bu derste \"Çeşitlilik\" temasında \"Etkileşim\" ünitesinden \"Molekül Polarlığı ve Apolarlığı\" konusu ele alınacak.","Daha önce metalik bağ, iyonik bağ, kovalent bağ ve Lewis nokta yapısı öğrenilmiş, bu derste molekülün tamamının polar mı yoksa apolar mı olduğunu belirleyeceğiz."]},"beginTime":0,"endTime":53,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=0&ask_summarization=1"},{"index":1,"title":"Molekül Polarlığı ve Apolarlığı Arasındaki Fark","list":{"type":"unordered","items":["Kovalent bağ dersinde molekül içindeki ametal atomları arasındaki bağların polar mı yoksa apolar mı olduğunu belirlemiştik.","Bu derste ise molekülün tamamının polar mı yoksa apolar mı olduğunu belirleyeceğiz.","Molekül içi bağ ile molekülün polarlı apolarlığı aynı olmak zorunda değildir, aynı da olabilir, farklı da olabilir."]},"beginTime":53,"endTime":119,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=53&ask_summarization=1"},{"index":2,"title":"Molekül ve Polarlık Kavramları","list":{"type":"unordered","items":["Molekül, ametal atomları arasında elektronların ortaklaşa kullanılmasıyla oluşan yapılardır.","Polar demek Türkçe'de kutuplu demektir, eksi artı kutuplardan bahsedilmektedir.","Polar moleküllerde elektron yük dağılımı dengeli değildir, elektronlar bir atomun etrafında daha yoğun bir şekilde bulunur."]},"beginTime":119,"endTime":196,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=119&ask_summarization=1"},{"index":3,"title":"Polar Molekül Örnekleri","list":{"type":"unordered","items":["HF molekülünde elektronlar flor tarafında daha çok yoğunlaşmıştır, bu nedenle molekül polar bir yapıdır.","H₂O molekülünde oksijen elektronegatifliği daha yüksek olduğu için elektronları kendisine daha çok çeker, bu nedenle molekül polar bir yapıdır.","NH₃ ve HCl moleküllerinde de elektronlar azot ve klor tarafında daha çok yoğunlaşmıştır, bu nedenle moleküller polar yapıdadır."]},"beginTime":196,"endTime":466,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=196&ask_summarization=1"},{"index":4,"title":"Dipol Moment Kavramı","list":{"type":"unordered","items":["Dipol moment kavramı, bir molekülün polar mı apolar mı olduğunu belirlemek için kullanılan bir başka kavramdır.","Dipol moment, molekülün polarlığını ifade eden vektörel bir büyüklüktür.","Eğer bir moleküldeki kuvvetlerin toplamı sıfırdan farklıysa ve sıfırdan büyükse, o molekül polardır."]},"beginTime":466,"endTime":581,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=466&ask_summarization=1"},{"index":5,"title":"Apolar Moleküller","list":{"type":"unordered","items":["Apolar, kutuplu olmayan veya kutupsuz anlamına gelir.","H₂ molekülünde elektronlar iki hidrojen tarafından aynı güçte çekildiği için elektronegatiflikleri aynıdır ve molekül kutupsuzdur.","Apolar moleküllerde elektron yük dağılımı dengelidir, elektronlar bir tarafa doğru kaymaz ve kalıcı negatif veya pozitif kutuplar oluşmaz."]},"beginTime":583,"endTime":643,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=583&ask_summarization=1"},{"index":6,"title":"Apolar Molekül Örnekleri","list":{"type":"unordered","items":["Oksijen molekülünde elektronlar iki oksijen atomu tarafından eşit güçte çekildiği için molekül apolar ve dipol moment sıfırdır.","Karbondioksit molekülünde oksijenin elektronegatifliği karbondan yüksek olsa da, elektronlar iki oksijen tarafından eşit güçte çekildiği için molekül apolar ve dipol moment sıfırdır.","CH₄ molekülünde karbon ve hidrojen arasındaki bağlar polar olsa da, molekülün simetrik yapısı nedeniyle elektron yük dağılımı dengeli ve dipol moment sıfırdır."]},"beginTime":643,"endTime":795,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=643&ask_summarization=1"},{"index":7,"title":"Molekülün Polar veya Apolar Olup Olmadığını Belirleme","list":{"type":"unordered","items":["Bir molekülün polar veya apolar olup olmadığını belirlemek için Lewis yapısını çizmek gerekir.","Merkez atom üzerinde ortaklanmamış elektron çifti varsa molekül polardır, yoksa apolar olur.","Merkez atom bağ yapmayan elektron çifti içeriyorsa yük dağılımı dengeli değildir ve dipol moment sıfırdan farklıdır, dolayısıyla molekül polardır."]},"beginTime":795,"endTime":974,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=795&ask_summarization=1"},{"index":8,"title":"Lewis Yapısı Örneği","list":{"type":"unordered","items":["Molekülün Lewis yapısını çizmek için önce atomların elektron dizilimini yazıp valance elektron sayısını bulmak gerekir.","Flor atomunda 7 valance elektron vardır ve tekli elektron sayısı kadar bağ yapar.","Flor molekülünde iki flor atomu arasında bir bağ oluşur ve elektron yük dağılımı dengeli olduğu için molekül apolar ve dipol moment sıfırdır."]},"beginTime":974,"endTime":1042,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=974&ask_summarization=1"},{"index":9,"title":"Lewis Yapısı ve Moleküler Özellikler","list":{"type":"unordered","items":["Azot atomu 5 valance elektronu olduğundan 3 bağ yapar ve iki azot atomu arasında 3 bağ oluşur.","Azot atomlarının bağ yapmayan elektronları vardır ve molekül simetrik yapıya sahip olduğundan apolar ve dipol momenti sıfıra eşittir.","Kükürt atomu 6 valance elektronu olduğundan 2 bağ yapar ve H2S molekülünde merkez atomda bağ yapmayan elektron çifti vardır, bu nedenle molekül polar ve dipol momenti sıfırdan farklıdır."]},"beginTime":1044,"endTime":1165,"href":"/video/preview/16249928152493662216?parent-reqid=1769609934927147-7344329956881423630-balancer-l7leveler-kubr-yp-sas-8-BAL&text=Molegul&t=1044&ask_summarization=1"},{"index":10,"title":"Diğer Moleküler Yapılar","list":{"type":"unordered","items":["NCl3 molekülünde azot 3 bağ yapar, klor 1 bağ yapar ve azotun elektronegatifliği daha yüksek olduğu için elektronlar azot tarafına yönelir, bu nedenle molekül polar ve dipol momenti sıfırdan farklıdır.","BH3 molekülünde bor 3 bağ yapar, hidrojen 1 bağ yapar ve merkez atomda ortaklanmamış elektron çifti olmadığı için molekül apolar ve dipol momenti sıfıra eşittir.","CH4 molekülünde karbon 4 bağ yapar, hidrojen 4 bağ yapar ve elektron yük dağılımı dengeli olduğu için molekül apolar ve dipol momenti 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