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Eğilme Momenti ) diyagramlarının en temel mantıkla ve çok kolay bir şekilde nasıl çizileceğini ve V M( Kesme...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/1769710/ea62e41599c97c6d205258781be1e2ea/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/BGsLCQEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"14","reqid":"1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=videoid:17044293906359478151","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan mekanik mühendislik dersinin bir bölümüdür. Eğitmen, kesme ve moment diyagramları konusunu detaylı bir şekilde anlatmaktadır.","Videoda, kesme ve moment kavramlarının tanımı yapılarak başlanmakta, ardından sabit izo-statik sistemlerde mesnet reaksiyonlarının hesaplanması, kesme diyagramının çizimi ve eğilme momenti diyagramının oluşturulması adım adım gösterilmektedir. Eğitmen, düzgün yayılı yük ve üçgen yayılı yük içeren kiriş sistemlerinin çözümünü üç denge denklemi kullanarak anlatmakta, her iki diyagram için de eğim hesaplamaları, alan hesaplamaları ve yön değişikliklerinin nasıl belirleneceğini açıklamaktadır.","Video, üçgen yayılı yükün birinci dereceden eğri denkleminin (qx = -17,78x + 80) nasıl bulunacağını göstermekte ve öğrencilerin sık yaptığı hataları vurgulamaktadır. Eğitmen, farklı yük tiplerinde ve soru tiplerinde daha fazla örnek sunulacağını belirterek videoyu sonlandırmaktadır."]},"endTime":1613,"title":"Kesme ve Moment Diyagramları Eğitim Videosu","beginTime":0}],"fullResult":[{"index":0,"title":"Kesme ve Moment Kavramları","list":{"type":"unordered","items":["Kesme kuvveti, bir malzemenin yüzeyine dik ve kesitine paralel olacak şekilde etki eden kuvvettir.","Moment, bir cismi bir noktaya veya eksen etrafında döndürme etkisidir.","Kesme diyagramı, yapı elemanına ne kadar kesme kuvveti gerekir sorusunu cevaplamak için oluşturulurken, moment diyagramı ne kadar çekme donatısı gereklidir sorusuna cevap bulmak için oluşturulur."]},"beginTime":11,"endTime":91,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=11&ask_summarization=1"},{"index":1,"title":"Mesnet Reaksiyonlarının Hesaplanması","list":{"type":"unordered","items":["Kesme ve moment diyagramları oluşturmak için önce mesnet reaksiyonları hesaplanmalıdır.","Mesnet tepkilerini bulmak için üç denge denklemi kullanılır: x ekseninde toplam kuvvetin sıfır olması, y ekseninde toplam kuvvetin sıfır olması ve moment ekseninde toplam momentin sıfır olması.","Sabit mesnet iki reaksiyon kuvveti, hareketli mesnet ise tek reaksiyon kuvveti vardır."]},"beginTime":91,"endTime":314,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=91&ask_summarization=1"},{"index":2,"title":"Kesme Diyagramının Çizimi","list":{"type":"unordered","items":["Kesme diyagramlarında üstü pozitif, altı negatif kabul edilirken, moment diyagramlarında yabancı kaynaklarda üstü pozitif, altı negatif; Türkçe kaynaklarda ise alt tarafı pozitif, üst tarafı negatif kabul edilir.","Kesme diyagramında, yükle aynı yönde hareket eden eğim çizilir; düzgün yayılı yük olduğu için eğim sabittir.","Kesme diyagramında yön değişimi olan noktalar, moment diyagramında da yön değişimi olduğundan kesikli çizgilerle gösterilir."]},"beginTime":314,"endTime":463,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=314&ask_summarization=1"},{"index":3,"title":"Moment Diyagramının Çizimi","list":{"type":"unordered","items":["Moment diyagramında, kesme diyagramındaki değerin mutlak değerinin artması veya azalması, moment diyagramındaki eğimin artması veya azalmasını belirtir.","Kesme diyagramındaki değer azalıyorsa, moment diyagramında eğim azalan bir parabol çizilir; değer artıyorsa eğim artan bir parabol çizilir.","Moment diyagramında, kesme diyagramındaki değer sıfıra yaklaştıkça eğim de sıfıra yaklaşıp yatay olur."]},"beginTime":463,"endTime":642,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=463&ask_summarization=1"},{"index":4,"title":"Kesme ve Moment Diyagramı Çizimi","list":{"type":"unordered","items":["İki konsol ve bir iç kiriş içeren, 5 metrelik kiriş üzerinde 30 kN/m düzgün yayılı yük olan bir yapı inceleniyor.","A sabit mesnet (iki reaksiyon kuvveti) ve B hareketli mesnet (bir reaksiyon kuvveti) olarak hesaplanıyor.","A ve B mesnet reaksiyonları, toplam Fx, toplam Fy ve toplam moment denklemleri kullanılarak hesaplanıyor."]},"beginTime":647,"endTime":721,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=647&ask_summarization=1"},{"index":5,"title":"Kesme Diyagramı Çizimi","list":{"type":"unordered","items":["Kesme diyagramında başlangıçta sıfırdan başlanıyor ve 1,5 metrelik kısım için 30 kN/m yük, kesme diyagramını -45 kN'e getiriyor.","A mesnet reaksiyonu (+120 kN) eksi 45 kN ile toplandığında kesme diyagramı +75 kN'e geliyor.","AB kiriş aralığındaki 30 kN/m düzgün yayılı yük, 5 metrelik mesafe boyunca 150 kN'e ulaşarak kesme diyagramını -75 kN'e getiriyor."]},"beginTime":721,"endTime":829,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=721&ask_summarization=1"},{"index":6,"title":"Moment Diyagramı Çizimi","list":{"type":"unordered","items":["Moment diyagramında başlangıçta sıfırdan başlanıyor ve kesme diyagramındaki değerlerin altında kalan alanlar kullanılarak hesaplanıyor.","Kesme diyagramındaki değerlerin artması veya azalması, moment diyagramındaki eğimin artan veya azalan bir eğri oluşturuyor.","Kesme diyagramındaki yön değişiklikleri, moment diyagramında da yön değişikliği oluşturuyor ve bu noktalar işaretlenmelidir."]},"beginTime":829,"endTime":968,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=829&ask_summarization=1"},{"index":7,"title":"İkinci Örnek Çözümü","list":{"type":"unordered","items":["İkinci örnekte A ve B mesnetli, üçgen yayılı yük içeren bir yapı inceleniyor.","Kesme diyagramında üçgen yayılı yük, kesme diyagramını azalan bir eğri oluşturarak -75 kN'e getiriyor.","Kesme diyagramındaki yön değişikliği, moment diyagramında da yön değişikliği oluşturuyor ve bu noktanın x değeri kesme diyagramının denkleminin kökü olarak bulunmalıdır."]},"beginTime":968,"endTime":1149,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=968&ask_summarization=1"},{"index":8,"title":"Üçgen Yayılı Yükün Denkleminin Bulunması","list":{"type":"unordered","items":["Üçgen yayılı yük birinci dereceden bir eğri olarak tanımlanır ve qx = ax + b formülüyle ifade edilir.","Sınır şartları kullanılarak denklem bulunur: x=0'da yük 80, x=4,5'te yük 10 değerlerini kullanarak a=-17,78 ve b=80 olarak hesaplanır.","Üçgen yayılı yükün denklemi -17,78x + 80 olarak hesaplanır."]},"beginTime":1160,"endTime":1254,"href":"/video/preview/17044293906359478151?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=1160&ask_summarization=1"},{"index":9,"title":"Kesme Kuvvet Denkleminin Çözümü","list":{"type":"unordered","items":["Kesme kuvvet denklemi başlangıç reaksiyonu (105 kN) ve yükün integrali ile yazılır: -17,78x²/2 + 80x + 105.","Denklem 2. dereceden olduğundan iki kökü vardır, ancak sadece 1,15 değeri sınır şartları içinde olduğu için geçerlidir.","Kesme kuvvet diyagramı, kesme değerinin yönü pozitif olduğu için başlangıçta 105 kN'den başlayıp 1,15 m'de sıfıra 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#parabolikyükleme #kesmemomentdiyagramı #ömeryeşiltepe Bu videoda V M( Kesme Kuvveti - Eğilme Momenti ) diyagramlarının en temel mantıkla ve çok kolay bir şekilde nasıl çizileceğini...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/2750382/36a261e78ffcbaac3f1ccd554e837154/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/TtALCQEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"16","reqid":"1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=videoid:9656515622990765222","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan mühendislik dersinin bir bölümüdür. Eğitmen, kesme moment diyagramları konusunda detaylı soru çözümleri ve çizim tekniklerini anlatmaktadır.","Videoda, parabolik yük altında kesme moment diyagramı çizimi adım adım gösterilmektedir. İlk olarak mesnet reaksiyonları hesaplanarak parabolik yükün denklemi bulunur, ardından kesme moment diyagramı ve eğilme momenti diyagramı çizilir. Eğitmen, farklı yük türleri (parabolik üçgen üyelik, düzgün yayılı yükler) için kesme moment diyagramı çizimini, integral alma yöntemlerini ve alan hesaplama tekniklerini detaylı olarak açıklamaktadır.","Video ayrıca kesme diyagramından moment diyagramına geçiş sürecini, üçgen ve trapez alanlarını hesaplama tekniklerini ve denklemleri kullanarak moment değerlerini bulma yöntemlerini içermektedir. Kesme ve moment diyagramlarının etr hesaplamaları ve çekme donatılarının hesaplarında nasıl kullanıldığı da vurgulanmaktadır."]},"endTime":1370,"title":"Kesme ve Moment Diyagramları Eğitim Videosu","beginTime":0}],"fullResult":[{"index":0,"title":"Kesme Moment Diyagramları Soru Çözümü","list":{"type":"unordered","items":["Bu videoda kesme moment diyagramları ile ilgili soru çözümlerine devam edilecek.","Önceki videoda kesme moment diyagramlarının temel giriş konuları ve neden çizildiği anlatılmıştır.","Örnek sistemde tek açıklıklı basit bir kiriş ve üzerine ikinci dereceden parabolik yük bulunmaktadır."]},"beginTime":11,"endTime":56,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=11&ask_summarization=1"},{"index":1,"title":"Parabolik Yükün Denkleminin Bulunması","list":{"type":"unordered","items":["İlk adım mesnet reaksiyonlarını (A ve B) hesaplamaktır.","Parabolik yükün altında kalan alanı hesaplamak için iki yöntem vardır: denklem yazmak veya eğriyi dikdörtgene tamamlayıp alan hesaplamak (sadece ikinci dereceden eğriler için).","Parabolik yükün denklemi ax² + bx + c şeklinde tanımlanır ve üç sınır şartı kullanılarak bulunur."]},"beginTime":56,"endTime":128,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=56&ask_summarization=1"},{"index":2,"title":"Parabolik Yükün Denkleminin Çözümü","list":{"type":"unordered","items":["İlk sınır şartı x=0'da yükün sıfır olması, bu c=0 değerini verir.","İkinci sınır şartı x=5'te maksimum değer olan 100 KN'a tekabül etmesi, 25a+5=100 denklemini verir.","Üçüncü sınır şartı tepe noktasındaki eğim, denklemin türevi alınarak bulunur ve a=-4, b=40 değerleri elde edilir."]},"beginTime":128,"endTime":217,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=128&ask_summarization=1"},{"index":3,"title":"Mesnet Reaksiyonlarının Hesaplanması","list":{"type":"unordered","items":["Mesnet reaksiyonlarını bulmak için önce PH değeri (eğrinin altında kalan alan) ve ağırlık merkezi (x') hesaplanmalıdır.","PH değeri integral ile hesaplanır: ∫₀⁵ q(x)dx = 333.333 olarak bulunur.","Ağırlık merkezi formülü x' = (∫₀⁵ xq(x)dx) / PH = 3.125 metre olarak hesaplanır."]},"beginTime":217,"endTime":345,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=217&ask_summarization=1"},{"index":4,"title":"Kesme Moment Diyagramının Çizimi","list":{"type":"unordered","items":["Kesme moment diyagramında A noktasındaki reaksiyon +125 olarak yukarıya doğru çizilir.","Parabolik yükün altında kalan alan -333.333 olduğundan, kesme momenti -208.333 değerine düşer.","Parabolik yükün eğimi arttığı için kesme momenti de 208.333 değerine doğru artar ve B noktasında sıfıra gelir."]},"beginTime":345,"endTime":422,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=345&ask_summarization=1"},{"index":5,"title":"Kesme Moment Diyagramının Devamı","list":{"type":"unordered","items":["Kesme moment diyagramında yön değişikliği olduğu mesafe, kesme moment denkleminin sıfır yapan kök değeridir.","Kesme moment denklemi 4x³/3 - 20x² + 125 olarak bulunur ve kökleri x₁=14.58, x₂=2.769, x₃=-2.769'dur.","Sıfır ile beş aralığı için mantıklı kök 2.769 metredir ve bu noktada kesme momenti sıfıra döner."]},"beginTime":422,"endTime":548,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=422&ask_summarization=1"},{"index":6,"title":"Eğilme Moment Diyagramının Hesaplanması","list":{"type":"unordered","items":["Eğilme moment diyagramı için kesme moment denkleminin integrali alınır.","Başlangıçta moment değeri olmadığı için, moment denklemi x⁴/3 - 20x³/360 + 125x olarak bulunur.","Kesme momentinin sıfır olduğu yerde moment maksimum olur."]},"beginTime":548,"endTime":615,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=548&ask_summarization=1"},{"index":7,"title":"Parabolik Yükün Kesme Moment Diyagramı","list":{"type":"unordered","items":["Değer azaldığında eğim azalır, değer sıfır olduğunda eğim sıfır olur.","Moment denkleminde x yerine 5 koyulduğunda, değer arttığı için mutlak değer olarak düşünülür ve eğim artar.","Parabolik yükün kesme moment diyagramı çizilmiştir."]},"beginTime":619,"endTime":693,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=619&ask_summarization=1"},{"index":8,"title":"İki Yönde Parabolik Üçgen Yük ve Düzgün Yayılı Yükler","list":{"type":"unordered","items":["Sistemde iki yönde parabolik üçgen yük ve iki düzgün yayılı yük bulunmaktadır.","Kesme moment diyagramlarını çizmenin ilk adımı mesnet reaksiyonlarını tespit etmektir.","Eğrilerin denklemleri ikinci dereceden olup, tepe noktasındaki değerler ve eğimler kullanılarak bulunmuştur."]},"beginTime":693,"endTime":826,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=693&ask_summarization=1"},{"index":9,"title":"Mesnet Reaksiyonlarının Hesaplanması","list":{"type":"unordered","items":["Üçgen yayılı yük için P1=26,67, düzgün yayılı yükler için P2=100 ve P3=40 değerleri hesaplanmıştır.","Üç denge denklemi (toplam Fx=0, toplam Fy=0, toplam moment=0) kullanılarak mesnet reaksiyonları bulunmuştur.","Ay=132,594 ve By=174,72 değerleri tespit edilmiştir."]},"beginTime":826,"endTime":924,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=826&ask_summarization=1"},{"index":10,"title":"Kesme Moment Diyagramının Çizimi","list":{"type":"unordered","items":["Kesme moment diyagramında üçgen yayın altında kalan alan 90, düzgün yayılı yüklerin altında kalan alanlar hesaplanmıştır.","Değer azaldığı için eğim azalır, değer arttığı için eğim artar.","Üçgen yayın altında kalan alan için benzerlik kullanılarak x değeri 0,32 olarak bulunmuştur."]},"beginTime":924,"endTime":1057,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=924&ask_summarization=1"},{"index":11,"title":"Moment Diyagramının Hesaplanması","list":{"type":"unordered","items":["Moment diyagramında, bölgenin altında kalan alan hesaplanmak için önce kesme kuvveti denklemi yazılır.","Kesme kuvveti denklemi -40x² + 40 olarak bulunmuş ve integrali alınarak moment denklemi 40x⁴/12 - 40x²/2 elde edilmiştir.","Moment denkleminde x yerine 1 konulduğunda -16,67 değerine ulaşılır ve bu değer moment diyagramında eğimli bir şekilde artar."]},"beginTime":1070,"endTime":1136,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=1070&ask_summarization=1"},{"index":12,"title":"İkinci Bölgenin Hesaplanması","list":{"type":"unordered","items":["İkinci bölgede, tepe noktadaki değer 60 ve eğimi 20 olarak hesaplanmıştır.","Kesme kuvveti denklemi 20x²/2 olarak bulunmuş ve integrali alınarak moment denklemi 105,97 olarak elde edilmiştir.","Moment denkleminde x yerine 3 konulduğunda 211,14 değerine ulaşılır ve bu değer moment diyagramında eğimli bir şekilde artar."]},"beginTime":1136,"endTime":1206,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=1136&ask_summarization=1"},{"index":13,"title":"Üçüncü Bölgenin Hesaplanması","list":{"type":"unordered","items":["Üçüncü bölgede, üçgen şeklindeki bölgenin alanı 15,97×2/2 = 31,45 olarak hesaplanmıştır.","Moment diyagramında yön değiştirerek eksiye doğru gider ve 211,14 değerine eklenir.","Daha sonra 84,74×1,68/2 = 213,64 değerine ulaşılır ve bu değer moment diyagramında eksiye doğru gider."]},"beginTime":1206,"endTime":1249,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=1206&ask_summarization=1"},{"index":14,"title":"Dördüncü Bölgenin Hesaplanması","list":{"type":"unordered","items":["Trapez şeklindeki bölgenin altında kalan alan 84,4 + 144,73/2×1,5 = 142,90 olarak hesaplanmıştır.","Bu değer 213,64'ten çıkarıldığında 28,19 değerine ulaşılır ve bu değer moment diyagramında eğimli bir şekilde artar.","Son bölgede, üçüncü dereceden denklem kullanılarak moment diyagramı tamamlanır ve değer azaldığı için eğim azalır."]},"beginTime":1249,"endTime":1338,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=1249&ask_summarization=1"},{"index":15,"title":"Kesme ve Moment Diyagramlarının Önemi","list":{"type":"unordered","items":["Kesme diyagramı, kirişteki çekme donatıların hesaplarında kullanılır.","Moment diyagramı, mesnetlerde ve açıklık bölgesindeki moment hesaplamalarında kullanılır.","Kesme ve moment diyagramları, kirişin yapısal analizinde önemli bir rol oynar."]},"beginTime":1338,"endTime":1368,"href":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=1338&ask_summarization=1"}],"linkTemplate":"/video/preview/9656515622990765222?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Yapı Statiği 1 (V-M Diyagramlari PART 2 Parabolik 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#çerçevesistem #kesmemomentdiyagramı #ömeryeşiltepe Bu videoda çerçeve sistemlerin V M diyagramlarının çizilmesinin ne kadar basit olduğunu göreceksiniz. Yapı Statiği, Statik...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/901260/660c6ef1e106816f49eb70695dc9366b/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/1erdDwEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"17","reqid":"1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=videoid:3571732825404709246","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan mühendislik dersidir ve çerçeve sistemlerde kesme ve moment diyagramlarının hesaplanması konusunu ele almaktadır.","Video, izostatik bir çerçeve sisteminde düzgün yayılı yük ve tekil yük etkisi altında mesnet reaksiyonlarının hesaplanmasıyla başlayıp, normal kuvvet diyagramı, kesme diyagramı ve moment diyagramının çizimine geçiş yapmaktadır. Eğitmen, her bir diyagramın nasıl çizileceğini adım adım göstermekte, pozitif ve negatif yön kabulünü açıklamakta ve diyagramların eğimlerini hesaplamaktadır.","Videoda ayrıca kesme diyagramından moment diyagramına geçişte, diyagramın altında kalan alanların nasıl hesaplanacağı detaylı olarak anlatılmakta ve birimlerin önemi vurgulanmaktadır (normal kuvvet ve kesme kuvvetinde kilo, newton; moment, newton metre)."]},"endTime":1198,"title":"Çerçeve Sistemlerde Kesme ve Moment Diyagramları Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"Çerçeve Sistemlerinde Kesme ve Moment Diyagramları","list":{"type":"unordered","items":["Video, çerçeve sistemlerinde kesme ve moment diyagramlarının dördüncü videosu olup, ilk videoda basit bir çerçeve sistemi incelenecektir.","Örnek sistemde düzgün yayılı yük, tekil yük, kiriş genişliği, kolon yüksekliği ve açıklık değerleri verilmiştir.","Bu tür sorularda işi kolaylaştıracak ilk adım serbest cisim diyagramını çizmektir."]},"beginTime":7,"endTime":64,"href":"/video/preview/3571732825404709246?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=7&ask_summarization=1"},{"index":1,"title":"Serbest Cisim Diyagramı ve Reaksiyon Hesaplamaları","list":{"type":"unordered","items":["Düzgün yayılı yük, etki ettiği noktayı ve kuvveti tekil bir kuvvet cinsinden (8 kN/m) yazarak serbest cisim diyagramına geçirilir.","Düzgün yayılı yükün ağırlık merkezi, yükün tam ortasında (6 metre genişliğinde 6 metre uzunluğunda) yer alır.","Üç denge denklemi (Fx, Fy ve moment denklemi) kullanılarak mesnet reaksiyonları hesaplanır: Ay = 40 kN ve Ey = 80 kN."]},"beginTime":64,"endTime":304,"href":"/video/preview/3571732825404709246?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=64&ask_summarization=1"},{"index":2,"title":"İç Kuvvetlerin Hesaplanması","list":{"type":"unordered","items":["Kesme ve moment diyagramlarını çizmek için çerçeve sistemlerinde iç kuvvetlerin hesaplanması gerekir.","Rijit birleşim noktalarından sistem ayrıldığında, x ve y yönündeki normal kuvvetler ile moment kuvveti olmak üzere üç iç kuvvet yazılır.","İç kuvvetlerin yönü, çubuk elemanın sol tarafına yazıldığında pozitif yön kabulüne göre belirlenir ve sonuç negatifse okun yönü değiştirilir."]},"beginTime":304,"endTime":456,"href":"/video/preview/3571732825404709246?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=304&ask_summarization=1"},{"index":3,"title":"İlk Parçanın İç Kuvvetlerinin Hesaplanması","list":{"type":"unordered","items":["İlk parçada Fx denklemi kullanılarak Bx = 48 kN bulunur.","Fy denklemi kullanılarak By = 40 kN bulunur.","B noktasına göre moment denklemi kullanılarak, düzgün yayılı yükün momenti 48 x 3 = 144 kN·m olarak hesaplanır."]},"beginTime":456,"endTime":547,"href":"/video/preview/3571732825404709246?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=456&ask_summarization=1"},{"index":4,"title":"İç Kuvvetlerin Hesaplanması","list":{"type":"unordered","items":["İkinci sistemde toplam Fx hesaplanırken, Bx 48 bulunmuş ve dx de 48 olarak hesaplanmıştır.","By 40 kN ton yukarı yönde, aşağı yönde 120 kN ton olduğu için, 80 kN ton aşağı yönde bulunarak Dy 80 kN ton olarak hesaplanmıştır.","D noktasındaki moment değeri B noktasına göre alınarak 144 kNtometre olarak tespit edilmiştir."]},"beginTime":549,"endTime":609,"href":"/video/preview/3571732825404709246?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=549&ask_summarization=1"},{"index":5,"title":"Dengenin Sağlanması","list":{"type":"unordered","items":["D noktasındaki 80 kN ton meslek reaksiyonu düşeyde dengeyi sağlamıştır.","Yatayda dx 48 kNtometre bulunmuş ve dengeyi sağlamıştır.","E noktasına göre moment alındığında, 48 kNtometre 3 metre mesafede 144 kNtometre moment etkisi yaratmıştır."]},"beginTime":609,"endTime":654,"href":"/video/preview/3571732825404709246?parent-reqid=1769505158214805-6443933833597412648-balancer-l7leveler-kubr-yp-vla-64-BAL&text=P.M.V&t=609&ask_summarization=1"},{"index":6,"title":"Normal Kuvvet Diyagramı","list":{"type":"unordered","items":["Normal kuvvet diyagramında, birinci çubuğun iki tarafında 40 kN ton basınç olduğu için negatif işaretli olarak çizilmiştir.","İkinci parçada Bx 48 kNtometre ve dx 48 kNtometre basınç olduğu için negatif işaretli olarak çizilmiştir.","Üçüncü parçada Dy 80 kN ton ve mesnet reaksiyonu 80 kN ton basınç olduğu için negatif işaretli olarak 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