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kullanarak bu kavramları görselleştiriyor. Ardından oksidasyon-redüksiyon denklemlerinin çözüm süreci üç farklı örnek üzerinden adım adım gösteriliyor. Her örnek için yüklerin belirlenmesi, yükseltgen ve indirgenme durumlarının hesaplanması, elektron sayılarının eşitlenmesi ve elementlerin sayılarının eşitlenmesi adımları detaylı olarak anlatılıyor.","Videoda ayrıca tersten çözüm yapmanın faydaları ve elektron sayısının eşitlenmesinin önemi vurgulanmaktadır. Bu içerik, AYT sınavına hazırlanan öğrenciler için hazırlanmış olup, öğretmen yeni bir kampın Kasım ayında başlayacağını belirtmektedir."]},"endTime":1285,"title":"Kimya Dersi: Yükseltgenme, İndirgenme ve Redoks Tepkimeleri","beginTime":0}],"fullResult":[{"index":0,"title":"Yükseltgenme ve İndirgenme Kavramları","list":{"type":"unordered","items":["Yükseltgenme, bir maddenin elektron vermesi ve yükünün artması durumudur.","İndirgenme, bir maddenin elektron alması ve yükünün azalması durumudur.","Yükseltgenme \"yükseltgenmiş\" veya \"yükseltgenen\", indirgenme ise \"indirgenmiş\" veya \"indirgenen\" olarak ifade edilir."]},"beginTime":0,"endTime":16,"href":"/video/preview/15944675345246217005?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=0&ask_summarization=1"},{"index":1,"title":"Yükseltgenme ve İndirgenme Örnekleri","list":{"type":"unordered","items":["X → X⁺¹ dönüşümü bir yükseltgendir çünkü X bir elektron verir ve yükü artı bire çıkar.","X²⁻ → X⁰ dönüşümü bir yükseltgendir çünkü X iki elektron verir ve yükü sıfıra çıkar.","X⁺¹ → X⁺³ dönüşümü bir yükseltgendir çünkü X bir elektron verir ve yükü artı üçe çıkar.","X → X⁻¹ dönüşümü bir indirgenmedir çünkü X bir elektron alır ve yükü sıfıra çıkar.","X⁺³ → X⁺¹ dönüşümü bir indirgenmedir çünkü X iki elektron alır ve yükü artı üçe çıkar.","X⁻¹ → X⁻⁴ dönüşümü bir indirgenmedir çünkü X üç elektron alır ve yükü eksi dörde çıkar."]},"beginTime":16,"endTime":132,"href":"/video/preview/15944675345246217005?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=16&ask_summarization=1"},{"index":2,"title":"Yükseltgenme ve İndirgenme İlişkisi","list":{"type":"unordered","items":["Bakır(II) ve çinko arasındaki tepkimede, bakır sıfıra inerken çinko artı ikiye yükselir.","Tahterevalli sistemi kullanılarak, bakırın elektron alması ve çinko'nun elektron vermesi gösterilir.","Bakır, çinko'nun yükselmesine sebep olduğu için yükseltgenmiş, çinko ise bakırın indirgenmesine sebep olduğu için indirgenmiş olarak ifade edilir."]},"beginTime":132,"endTime":277,"href":"/video/preview/15944675345246217005?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=132&ask_summarization=1"},{"index":3,"title":"Redoks Tepkimelerinin Denkleştirilmesi","list":{"type":"unordered","items":["Redoks tepkimelerini denkleştirmek için önce maddelerin yüklerini tespit etmek gerekir.","Yükseltgenme basamaklarını belirleyip, hangisinin değeri artmış, hangisinin değeri azalmış olduğunu belirlemek gerekir.","Alınan ve verilen elektron sayısını eşitlemek için, elektron alışverişi yapanların karşı taraftaki sayılarını da eşitlemek gerekir.","Redoks tepkimelerinde oksijen eşit çıkıyorsa doğru denkleştirme yapılmış 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faydalı olduğu belirtiliyor.","Azotun bir tanesi değişiyor, bir tanesi değişmediği için sağdan sola doğru çözüm yapılabilir.","Klor hem sıfırdan eksi bir'e indirgeniyor hem de sıfırdan artı bir'e yükseltgeniyor, bu durumda alınan verilen elektron sayısı eşit."]},"beginTime":914,"endTime":1065,"href":"/video/preview/15944675345246217005?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=914&ask_summarization=1"},{"index":12,"title":"Birden Fazla Değişenli Denklemler","list":{"type":"unordered","items":["Birden fazla değişenli bileşiklerde önce yükleri bulup, sonra tek tek değişenleri incelemek gerekiyor.","Arsenik artı üç'ten artı beşe, kükürt eksi iki'den artı dört'e yükseltiyor.","Azot artı beş'ten artı iki'ye indirgeniyor, bu durumda alınan verilen elektron sayısını eşitlemek için katsayılar 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Video sonunda öğretmen, bir sonraki videoda aktiflik konusuyla ilgili test sorularını çözeceğini belirtmektedir."]},"endTime":2292,"title":"AYT Kimya Dersi: Yükseltgenme ve İndirgenme Tepkimeleri","beginTime":0}],"fullResult":[{"index":0,"title":"Giriş ve Konu Tanıtımı","list":{"type":"unordered","items":["Günaydın Yayınları'nın AYT Kimya Soru Bankası'ndan yükseltgenme ve indirgenme tepkimeleri konusu ele alınacak.","Anyon ve katyon tablolarının bilmek gerektiği, bu konuyu yapabilmek için bu tablolardaki bilgilere ihtiyaç duyulacağı hatırlatılıyor."]},"beginTime":6,"endTime":34,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=6&ask_summarization=1"},{"index":1,"title":"Hidrojen Peroksit Örneği","list":{"type":"unordered","items":["H₂O₂ bileşiğinin adının hidrojen peroksit olduğu doğrulanıyor, çünkü oksijen peroksit (O₂²⁻) olarak bağlı.","Hidrojen peroksit bileşiği hem indirgen hem de yükseltgen çünkü oksijen hem indirgenmeye hem de yükseltgenmeye uğramış.","Oksijen eksi bir yüklüden sıfıra yükseltgenme, eksi bir yüklüden eksi iki yüklüye indirgenme geçişleri yapmış."]},"beginTime":34,"endTime":220,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=34&ask_summarization=1"},{"index":2,"title":"Redoks Tepkimelerinin Tanımlanması","list":{"type":"unordered","items":["Redoks tepkimesi olup olmadığını belirlemek için elementlerin bileşiklerdeki yüklerinden farklı olması yeterli.","Yanma tepkimelerinin genellikle redoks tepkimeleri olduğu bilgisi veriliyor.","Redoks tepkimelerinde bir element yükseltgenme basamaklarında bir değişim gösteriyorsa, mutlaka diğer bir element indirgenme basamaklarında değişim gösterir."]},"beginTime":220,"endTime":339,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=220&ask_summarization=1"},{"index":3,"title":"Redoks Tepkimeleri Örnekleri","list":{"type":"unordered","items":["Kurşun ve iyot bileşiklerinde yükler değişmediği için redoks tepkimesi olmadığı belirleniyor.","Lityum ve çinko tepkimelerinde yükler değiştiği için redoks tepkimeleri olduğu tespit ediliyor.","Karbonun yanması (C + O₂ → CO₂) örneği verilerek sorunun devamı bekleniyor."]},"beginTime":339,"endTime":458,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=339&ask_summarization=1"},{"index":4,"title":"Redoks Tepkimeleri ve Yükseltgenme Basamakları","list":{"type":"unordered","items":["Elementel halde bir madde görüldüğünde tepkime redoks tepkimesi olarak tanımlanabilir.","Karbon atomunun yükseltgenmesi, oksijenin indirgenmesi anlamına gelir.","Çinko metalinin hidrojen klorür ile tepkimesinde, hidrojen gazı çıkması ve hidrojenin yükseltgenme basamaklarının değişmesi redoks tepkimesini gösterir."]},"beginTime":461,"endTime":514,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=461&ask_summarization=1"},{"index":5,"title":"Redoks Tepkimelerinin Belirlenmesi","list":{"type":"unordered","items":["Kalsiyum karbonatın ısıtılarak kalsiyum oksit ve karbondioksit ayrışması tepkimesinde yükseltgenme basamakları değişmediği için redoks tepkimesi değildir.","Bileşik çiftlerinde altı çizili atomların yükseltgenme basamakları eşit olup olmadığı belirlenirken, her atomun değerini hesaplamak gerekir.","Potasyum dikromat ve chrome iki florür bileşiklerinde chrome atomlarının yükseltgenme basamakları eşit değildir."]},"beginTime":514,"endTime":688,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=514&ask_summarization=1"},{"index":6,"title":"Denkleştirilmemiş Tepkime Denklemleri","list":{"type":"unordered","items":["Alüminyum, sodyum hidroksit, sodyum alüminat ve hidrojen gazı arasındaki tepkimede, alüminyum sıfırdan artı üç'e yükselirken hidrojen artı bir'den sıfıra indirgenir.","Yarı tepkimeleri yazarak ve elektron sayılarını eşitleyerek denkleştirme yapılır.","Bir mol alüminyum üç mol elektron verir ve sodyum hidroksit yükseltgen bir bileşiktir çünkü hidrojen yükseltgenme basamaklarını değiştirir."]},"beginTime":688,"endTime":949,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=688&ask_summarization=1"},{"index":7,"title":"Tepkimelerde Yükseltgenme ve İndirgenme","list":{"type":"unordered","items":["Yanma tepkimelerinde oksijen genellikle indirgenir ve yanındaki madde yükseltir.","Tepkimelerde yükseltgenme ve indirgenme basamakları hesaplanarak tepkimelerin redoks tepkimesi olup olmadığı belirlenir.","Bileşiklerde yükseltgenme basamakları, bileşik içindeki atomların yükseltgenme basamaklarına göre belirlenir."]},"beginTime":949,"endTime":1139,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=949&ask_summarization=1"},{"index":8,"title":"Karbon Atomlarının Yükseltgenme Basamakları","list":{"type":"unordered","items":["Potasyum oksalat bileşiklerinde karbon atomunun yükseltgenme basamakları hesaplanır.","Karbon tetra florür bileşiklerinde karbon atomunun yükseltgenme basamakları hesaplanır.","Karbonik asit bileşiklerinde karbon atomunun yükseltgenme basamakları hesaplanır."]},"beginTime":1139,"endTime":1207,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1139&ask_summarization=1"},{"index":9,"title":"Redoks Tepkimi Analizi","list":{"type":"unordered","items":["Birinci tepkime incelendiğinde, karbon sıfırdan artı ikiye yükseltgenmiş, diğer karbon artı dörtten artı ikiye indirgenmiş olup, bu tepkimede karbon hem indirgenmiş hem yükseltgenmiş olmaktadır.","İkinci tepkime incelendiğinde, magnezyum, oksijen ve hidrojen değişmemiş, sadece karbon artı dörtten artı ikiye yükselgenmiş olup, bu tepkimede sadece bir madde yükselgenmiştir.","Üçüncü tepkime incelendiğinde, klor sıfırdan eksi bir'e indirgenmiş, bu tepkimede yükseltgenme ürünü perklorat, indirgenme ürünü klorürdür."]},"beginTime":1210,"endTime":1405,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1210&ask_summarization=1"},{"index":10,"title":"Redoks Tepkimesi ve Kimyasal Hesaplama","list":{"type":"unordered","items":["Soruda verilen tepkime denkleştirilerek hidrojen sülfür gazı harcandığında oluşan azot monoksit gazının kütlesi hesaplanmaktadır.","Tepkime denkleştirilirken azot artı beş indirgenmiş, kükürt eksi iki yükselgenmiş olup, elektron sayıları denkleştirilerek tepkime denklemi tamamlanmaktadır.","Denklemde hidrojen ve oksijenlerin katsayıları da hesaplanarak tamamlanmış olup, soru elektrokimya ile kimyasal hesaplama birleştirilerek çözülmektedir."]},"beginTime":1405,"endTime":1542,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1405&ask_summarization=1"},{"index":11,"title":"Gaz Hesaplaması ve Kimyasal Tepkime","list":{"type":"unordered","items":["6,72 litre gaz hacmi normal koşullarda 0,30 mol hidrojen sülfür'e karşılık gelmektedir.","3 mol hidrojen sülfür ile tepkime yaparak 2 mol azot monoksit oluşur, bu 60 gram azot monoksit'e denk gelmektedir.","0,30 mol hidrojen sülfür girdiğinde 6 gram azot monoksit oluşur."]},"beginTime":1545,"endTime":1622,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1545&ask_summarization=1"},{"index":12,"title":"Redoks Tepkimesi ve Hesaplama","list":{"type":"unordered","items":["Karbon ve azot atomlarının yükseltgenme basamakları hesaplanarak, karbonun 4 elektron verdiğini ve azotun 3 elektron aldığını tespit ederiz.","Tepkime denklemi denkleştirildikten sonra, 4 mol nitrik asit ile tepkime yaparak 3 mol karbondioksit oluşur.","0,40 mol nitrik asit girdiğinde 1,32 gram karbondioksit oluşur."]},"beginTime":1622,"endTime":1811,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1622&ask_summarization=1"},{"index":13,"title":"Karmaşık Redoks Tepkimesi","list":{"type":"unordered","items":["Potasyum permanganat tepkimede mangan atomu indirgelenirken (Mn+7 → Mn+2), klor atomu yükseltgenme geçirir.","Mangan atomunun indirgendiği tepkime kısmında 5 elektron alırken, klor atomunun yükseltgenme geçtiği kısmında 2 elektron verir.","Bu karmaşık tepkimede, klor atomlarının toplam katsayısı hesaplanarak denkleştirme yapılır."]},"beginTime":1811,"endTime":1976,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1811&ask_summarization=1"},{"index":14,"title":"İndirgenme-Yükseltgenme Tepkimesi Çözümü","list":{"type":"unordered","items":["Potasyum permanganat tepkimesinde klorun katsayısı 16 olarak belirleniyor ve su katsayısı hidrojen sayısından bulunuyor.","Potasyum permanganat yükseltgen midir sorusuna cevap olarak, klorun indirgenmesi (elektron alması) ve karşıdan yükseltgen olması belirtiliyor.","İki mol potasyum permanganat artansız tepkimeye girdiğinde 350 gram klor gazı oluşması hesaplanıyor."]},"beginTime":1978,"endTime":2100,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=1978&ask_summarization=1"},{"index":15,"title":"Hidroklorik Asit ve Potasyumun Rolü","list":{"type":"unordered","items":["HCl hem yükseltgen hem indirgen midir sorusuna cevap olarak, sadece klorun yükseltgendiğine ve hidrojenin değişmediğine göre sadece indirgendir yükseltgenmiş olarak belirtiliyor.","Potasyum elementi indirgenme yükseltgenme tepkimesine katılmamıştır çünkü artı bir şeklinde girdi ve çıktı."]},"beginTime":2100,"endTime":2138,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=2100&ask_summarization=1"},{"index":16,"title":"Tepkime Denkleştirme Sorusu","list":{"type":"unordered","items":["Bir tepkime denkleştirildiğinde ürünlerin katsayısı toplamı sorulduğunda, oksijen, karbon ve iyotların yükleri hesaplanıyor.","İyot artı beşe indirgenmiş, karbon artı dörte yükselmiş ve elektron denkleştirilmesi yapılarak tepkime denkleniyor.","Ürünlerin katsayıları toplamı 12 olarak bulunuyor."]},"beginTime":2138,"endTime":2257,"href":"/video/preview/2990323066083119708?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=2138&ask_summarization=1"},{"index":17,"title":"Video Kapanışı","list":{"type":"unordered","items":["İndirgenme ve yükseltgenme ile ilgili 12 soru çözüldüğü belirtiliyor ve bir sonraki videoda aktiflik konusuyla ilgili test sorularının çözüleceği söyleniyor.","İzleyicilerden abone olmaları, beğenileri ve yorumları ile destek olmaları isteniyor.","Soru sormak isteyenlerin Instagram sayfasına göndermeleri ve hızlıca cevap verileceği 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Öncelikle asidik ortam için yedi adımlı bir yöntem sunulmakta, ardından bazik ortam için bu yedi adımın yanı sıra üç ek adım anlatılmaktadır. Öğretmen, konuyu anlamak için örnek videoların izlenmesi gerektiğini vurgulamakta ve denklemlerin nasıl denkleştirileceğini adım adım açıklamaktadır."]},"endTime":204,"title":"Yarı Tepkime Yöntemi ile Errodoks Tepkime Denkleştirme","beginTime":0}],"fullResult":[{"index":0,"title":"Yarı Tepkime Yöntemi Tanıtımı","list":{"type":"unordered","items":["Errodoks tepkime denkleştirmek için yarı tepkime yöntemi ele alınacaktır.","Konuyu anlamak için örnek videoları izlemek ve soru çözümlerinden yola çıkarak pekiştirmek gerekmektedir.","Ortama göre denkleştirme biraz daha farklı olacaktır."]},"beginTime":0,"endTime":26,"href":"/video/preview/17919786983736001240?parent-reqid=1767355943560295-9276528936265581288-balancer-l7leveler-kubr-yp-vla-170-BAL&text=Redoks+Studio&t=0&ask_summarization=1"},{"index":1,"title":"Asidik Ortam İçin Kurallar","list":{"type":"unordered","items":["Tepkime iki yarı tepkimeye bölünür: yükselgenme tepkimesi ve indirgenme tepkimesi.","Hidrojen ve oksijen atomları 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