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Video boyunca trigonometrik dönüşümler, sekant ve tanjant fonksiyonları kullanılarak integral hesaplaması detaylı olarak anlatılmakta ve sonunda elektrik alanının y bileşeninin E = kλa/a sinθ olduğu sonucuna varılmaktadır."]},"endTime":384,"title":"Homojen Yük Dağılımına Sahip Çubuğun Elektrik Alanı Hesaplama","beginTime":0}],"fullResult":[{"index":0,"title":"Elektrik Alan Hesaplama Yöntemi","list":{"type":"unordered","items":["Q yüklü, L boyunda homojen yük dağılımına sahip bir çubuğun P noktasında oluşturduğu elektrik alanın Y bileşeni hesaplanacak.","Elektrik alan hesaplaması için çubuk küçük dx dilimlerine bölünür ve her dilimin oluşturduğu elektrik alanı hesaplanıp toplanır.","Her dx diliminin yükü dQ olup, P noktasına olan uzaklığı pisagor bağıntısı ile 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Derse canlı olarak katılmak...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/2003801/512c398980233abb127c4154cd3c9881/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/LXUFFAEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"2","reqid":"1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=videoid:14903192795486666450","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan fizik dersinin bir bölümüdür. Eğitmen, F2 dersinin tüm konularını sıfırdan başlayarak finallere kadar bitirmeyi amaçladığını belirtmektedir.","Video, elektrik yükü ve elektrostatik kuvvet konusunu ele almaktadır. İlk olarak temel bilgiler hatırlatılarak Coulomb Yasası formülü (F = k * q1 * q2 / r²) anlatılmakta, ardından çeşitli problem çözümleri adım adım gösterilmektedir. Problemler arasında elektrik kuvvetinin hesaplanması, mesafe bulma, vektörel analiz, üçgen geometrisi kullanılarak kuvvet bileşimi hesaplama ve dengede olma koşulları bulunmaktadır.","Videoda özellikle kuvvetlerin vektörel analizi, i ve j bileşenlerinin toplanması, açı hesaplamaları ve r² ile orantılı kuvvet hesaplamalarında dikkat edilmesi gereken noktalar vurgulanmaktadır. Eğitmen, öğrencilere hitap ederek konuyu adım adım açıklamakta ve öğrencilerle etkileşim halinde olmaktadır."]},"endTime":3141,"title":"F2 Dersi: Elektrik Yükü ve Elektrostatik Kuvvet Problemleri","beginTime":0}],"fullResult":[{"index":0,"title":"Elektrik Yükleri ve Kuvvetler","list":{"type":"unordered","items":["F2 dersinde elektrik yükleri konusuna sıfırdan başlanacak ve finallere kadar tüm konular bitirilecek.","Aynı işaretli elektrik yükleri birbirini iterken, zıt işaretli yükler birbirini çeker.","İki yük arasındaki elektrik kuvveti formülü F = k * (q1 * q2) / r² şeklinde gösterilir, burada k sabiti 9 x 10^9 Nm²/C²'dir."]},"beginTime":0,"endTime":101,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=0&ask_summarization=1"},{"index":1,"title":"Elektrik Kuvveti Hesaplama","list":{"type":"unordered","items":["Elektrik kuvveti, yükler büyüdükçe artarken, aradaki mesafe büyüdükçe ters orantılı olarak azalır.","Vektörel hesaplamada, kuvvetin yönü ve büyüklüğü ayrı ayrı hesaplanır.","Sorularda sadece büyüklük isteniyorsa, yönü hesaba katmadan sadece büyüklüğü hesaplamak yeterlidir."]},"beginTime":101,"endTime":190,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=101&ask_summarization=1"},{"index":2,"title":"Örnek Sorular","list":{"type":"unordered","items":["İlk örnek soruda, iki yük arasındaki mesafe hesaplanırken, tek bilinmeyenli denklem çözülerek r = 1,39 m bulunmuştur.","İkinci örnek soruda, iki yük arasındaki elektrik kuvvetinin büyüklüğü hesaplanırken, mesafe metreye çevrilerek F = 2,81 N bulunmuştur.","Üçüncü örnek soruda, üç yük arasındaki kuvvetlerin sıfır olduğu durumda, q1/q2 oranı hesaplanacak."]},"beginTime":190,"endTime":705,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=190&ask_summarization=1"},{"index":3,"title":"Elektrik Yükleri ve Kuvvetler","list":{"type":"unordered","items":["Elektrik yükleri arasındaki mesafelerin hesaplanmasında, belirli değerler yerine genel semboller kullanmak daha mantıklıdır çünkü sonradan sadeleşecektir.","Üçüncü yüke uygulanan kuvvetin sıfır olduğu belirtilmiş, bu durumda birinci ve ikinci yüklerin farklı işaretlere sahip olması gerekir (bir pozitif, bir negatif).","İki pozitif yükün üçüncü yüke uyguladığı kuvvetlerin sıfır olamayacağı, bu nedenle bir pozitif bir negatif veya bir negatif bir pozitif olmaları gerektiği açıklanmıştır."]},"beginTime":709,"endTime":884,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=709&ask_summarization=1"},{"index":4,"title":"Kuvvet Denklemleri ve Hesaplamalar","list":{"type":"unordered","items":["Birinci yükün üçüncü yüke uyguladığı kuvvet (F13) ve ikinci yükün üçüncü yüke uyguladığı kuvvet (F23) büyüklük olarak birbirine eşit olmalıdır.","Kuvvet hesaplamasında, yüklerin çarpımı ile doğru orantılı olduğu ve mesafenin karesiyle ters orantılı olduğu belirtilmiştir.","Yüklerin işaretleri karşıt olduğu için, F1/F2 oranının negatif olacağı ve bu oranın -4'e eşit olacağı hesaplanmıştır."]},"beginTime":884,"endTime":1186,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=884&ask_summarization=1"},{"index":5,"title":"Vektörel Kuvvet Hesaplaması","list":{"type":"unordered","items":["Üçüncü yüke uygulanan net elektrostatik kuvvetin x ve y eksenlerindeki bileşenlerinin hesaplanması gerektiği belirtilmiştir.","Birinci yük, üçüncü yüke aşağı doğru itme kuvveti uygularken, ikinci yük kendine doğru çekme kuvveti uygulamaktadır.","Dördüncü yük de üçüncü yüke kendine doğru çekme kuvveti uygulamaktadır ve net kuvvet hesaplaması için vektörel toplama yapılacaktır."]},"beginTime":1186,"endTime":1380,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=1186&ask_summarization=1"},{"index":6,"title":"Elektrik Kuvveti Hesaplamaları","list":{"type":"unordered","items":["F23 kuvvetinin yönü artı i ve artı j olacak şekilde hesaplanıyor.","F23 kuvvetinin büyüklüğü 9×10^9×100×100/(5×10^-2)^2 hesaplamasıyla 5,5×10^2 N olarak bulunuyor.","F4 kuvvetinin büyüklüğü 9×10^9×200×200/(5×10^-2)^2 hesaplamasıyla 1,4×10^3 N olarak bulunuyor."]},"beginTime":1407,"endTime":1659,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=1407&ask_summarization=1"},{"index":7,"title":"Kuvvetlerin Toplanması","list":{"type":"unordered","items":["Kuvvetler i ve j bileşenlerine ayrılarak toplanıyor.","i bileşenleri toplandığında 0,6 + 0,14 + 0,14 = 0,88 N sonucu elde ediliyor."]},"beginTime":1659,"endTime":1687,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=1659&ask_summarization=1"},{"index":8,"title":"Vektör Kuvvetin Komponentleri","list":{"type":"unordered","items":["Bir vektör kuvvetin x ve y komponentleri hesaplanıyor: Fx = 0,18 N ve Fy = -0,07 N olarak bulunuyor.","Kuvvetin büyüklüğü, komponentlerin karelerinin toplamının karekökü olarak hesaplanabilir: √(0,17² + 0,07²) = 0,16 N."]},"beginTime":1716,"endTime":1800,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=1716&ask_summarization=1"},{"index":9,"title":"Elektrostatik Kuvvet Problemi","list":{"type":"unordered","items":["Soruda bir mikroklomb (1 μC) ve eksi üç mikroklomb (-3 μC) şarjları arasındaki mesafe 10 cm olarak verilmiş.","Üçüncü bir şarjın, birinci ve ikinci şarjın üzerindeki net elektrostatik kuvvetin sıfır olması isteniyor.","Üçüncü şarjın x ve y koordinatlarının ne olacağını bulmak gerekiyor."]},"beginTime":1800,"endTime":1850,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=1800&ask_summarization=1"},{"index":10,"title":"Şarjın Konumunu Belirleme","list":{"type":"unordered","items":["Üçüncü şarjın pozitif veya negatif olabileceği düşünülüyor, ancak ortada olamayacağı belirleniyor çünkü iki şarjın kuvvetleri aynı yönde olur.","Üçüncü şarjın sol tarafta olması gerektiği, yani x koordinatının negatif olması gerektiği anlaşılıyor.","Üçüncü şarjın y koordinatının sıfır olması gerektiği, yani y ekseninde bir yerde olamayacağı belirleniyor."]},"beginTime":1850,"endTime":2299,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=1850&ask_summarization=1"},{"index":11,"title":"Matematiksel Çözüm","list":{"type":"unordered","items":["Dengede olması için kuvvetlerin eşit olması şartıyla denklem kuruluyor: k * q1 * q3 / x² = k * q2 * q3 / (x + 0,1)².","Mikroklomb birimleri ve Coulomb sabiti k birbirini götürüyor, denklem sadeleştiriliyor.","Denklem çözülerek x = -0,136 m (veya -13,6 cm) bulunuyor, yani üçüncü şarjın konumu x = -13,6 cm, y = 0 olarak belirleniyor."]},"beginTime":2299,"endTime":2657,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=2299&ask_summarization=1"},{"index":12,"title":"Elektrik Kuvveti Hesaplama","list":{"type":"unordered","items":["İki yük (bir ve iki) 20 mikroklomb olup, aralarındaki mesafe 1,5 metre olarak verilmiş.","Birinci parçada ikinci parçadan uygulanan kuvvet yukarı doğru olacak çünkü ikisi de pozitif yük olduğu için birbirlerini iterler.","Kuvvet hesaplaması için F = k × (q₁ × q₂) / r² formülü kullanılarak, kuvvetin büyüklüğünün 1,60 Newton olduğu bulunmuştur."]},"beginTime":2661,"endTime":2782,"href":"/video/preview/14903192795486666450?parent-reqid=1769322770031856-2045826670020105064-balancer-l7leveler-kubr-yp-vla-88-BAL&text=Trek2Physics&t=2661&ask_summarization=1"},{"index":13,"title":"Eşkenar Üçgen Şeklindeki Yüklerin Kuvvetleri","list":{"type":"unordered","items":["Eşkenar üçgen şeklinde 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