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Özellikle bağıl hız hesaplamaları, artı-eksi işaretlerinin yönü ve ivme hesaplamaları detaylı olarak anlatılmaktadır."]},"endTime":2386,"title":"Fizik Dersi: Düzgün Dairesel Hareket ve Bağıl Hareket","beginTime":0}],"fullResult":[{"index":0,"title":"Fizik Genel Tekrarı ve Düzgün Dairesel Hareket","list":{"type":"unordered","items":["Fizik genel tekrarının birinci etabının son videosu, düzgün dairesel hareket ve bağıl hareket konularını içermektedir.","Fizikte \"düzgün\" kelimesi genellikle \"sabit\" anlamına gelir, örneğin düzgün dairesel hareket sabit hızlı dairesel hareket anlamına gelir.","Düzgün dairesel hareket, sabit bir hızla dairesel bir yolda hareket eden bir cismin yaptığı harekettir."]},"beginTime":0,"endTime":78,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=0&ask_summarization=1"},{"index":1,"title":"Dairesel Hareketin Mantığı","list":{"type":"unordered","items":["Dairesel harekette çizgisel hız (v) her yerde sabittir ve sürekli merkeze doğru dönerek hareket eder.","Hız vektörel bir nicelik olduğundan şiddet, yön ve doğrultuya sahiptir.","İvme, hızın sadece şiddetini değil, aynı zamanda yönünü de etkileyebilir."]},"beginTime":78,"endTime":264,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=78&ask_summarization=1"},{"index":2,"title":"Merkezcil İvme","list":{"type":"unordered","items":["Dairesel harekette hızın yönünü etkileyen ivme \"merkezcil ivme\" veya \"radyal ivme\" olarak adlandırılır.","Radyal ivme (r), çizgisel hızın karesinin dairesel yörüngenin yarıçapına oranı ile hesaplanır: r = v²/r.","Dairesel hareket, ivmenin sadece hızla değil, aynı zamanda yönü de değiştirebilen bir nicelik olduğunu kanıtlayan bir durumdur."]},"beginTime":264,"endTime":351,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=264&ask_summarization=1"},{"index":3,"title":"Dairesel Hareketin Özellikleri","list":{"type":"unordered","items":["Dairesel hareket, sürekli aynı yörüngede hareket eden bir yörüngesel harekettir.","Dairesel harekette periyot, frekans, açısal hız, açısal ivme ve açısal yer değiştirme gibi yeni terimler kullanılır.","Dairesel hareket, doğrusal hareket kavramlarıyla çözülemeyen, devirsel hareket içeren bir hareket türüdür."]},"beginTime":351,"endTime":415,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=351&ask_summarization=1"},{"index":4,"title":"Dairesel Hareketin Özellikleri","list":{"type":"unordered","items":["Dairesel hareket, merkezden bir dairesel yol alarak merkeze doğru radyal ivme sayesinde gerçekleşir.","Radyal ivme, çizgisel hızın karesinin yörüngenin yarıçapına bölünmesiyle bulunur.","Düzgün dairesel harekette çizgisel hız sabittir ve her yerde aynıdır."]},"beginTime":417,"endTime":479,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=417&ask_summarization=1"},{"index":5,"title":"Dairesel Harekette Zaman Kavramları","list":{"type":"unordered","items":["Dairesel harekette iki önemli zaman kavramı vardır: periyot ve frekans.","Periyot, bir turun tamamlanma süresidir ve birimi saniyedir.","Frekans, bir saniyedeki tur sayısıdır ve birimi s üzeri eksi bir (1/s) veya hertz'dir.","Periyot ve frekans arasındaki ilişki: T × f = 1'dir."]},"beginTime":479,"endTime":565,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=479&ask_summarization=1"},{"index":6,"title":"Dairesel Harekette Hız ve İvme İlişkisi","list":{"type":"unordered","items":["Dairesel harekette teğetsel ivme sıfır olduğundan, çizgisel hız sabittir ve sabit hızlı hareket olarak adlandırılır.","Sabit hızlı hareket için doğrusal hareket formülü Δx = v × t kullanılır.","Dairesel harekette bir tur, çemberin çevresi kadar yol almak demektir ve 2πr formülüyle hesaplanır.","Çizgisel hız formülü: v = 2πr / T veya v = 2πrf'dir."]},"beginTime":565,"endTime":740,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=565&ask_summarization=1"},{"index":7,"title":"Dairesel Hareketin Temel Denklemleri","list":{"type":"unordered","items":["Dairesel harekette üç temel denklem vardır: radyal ivme, periyot ve frekans ilişkisi, çizgisel hız formülü.","Dairesel hareket konusu dinamik ile ilgili karışım soruları ve açısal momentum öncesinde daha ayrıntılı bir bölümle devam edecektir."]},"beginTime":740,"endTime":790,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=740&ask_summarization=1"},{"index":8,"title":"Örnek Soru Çözümü","list":{"type":"unordered","items":["Bir virgül yirmi metre çapa sahip bir tekerlek dakikada yüz yirmi devir atmaktadır.","Tekerleğin dişleri arasına gömülü bir taş parçasının çizgisel hızı ve radyal ivmesi bulunması istenmektedir.","Taş tekerleğin en dış kenarı üzerinde ve bir devirde tekerlek dairesi çevresine eşit olacak şekilde yol almaktadır."]},"beginTime":790,"endTime":860,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=790&ask_summarization=1"},{"index":9,"title":"Dairesel Hareket ve İvme Hesaplamaları","list":{"type":"unordered","items":["Radyal ivme, v²/r formülü ile hesaplanır ve bu formülde v çizgisel hız, r ise yarıçap değeridir.","Dairesel harekette hız, 2πr/T formülü ile bulunur, burada T periyot (bir turun geçtiği süre) değeridir.","Dakikada 120 devir atan bir tekerleğin frekansı 2 Hz, periyodu ise 0,5 saniye olarak hesaplanır."]},"beginTime":863,"endTime":1002,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=863&ask_summarization=1"},{"index":10,"title":"Hız ve İvme Hesaplamaları","list":{"type":"unordered","items":["Çizgisel hız, 2πr×f formülü ile hesaplanır ve bu örnekte 7,53 m/s olarak bulunur.","Radyal ivme, v²/r formülü ile hesaplanır ve bu örnekte 94,60 m/s² olarak bulunur.","Dairesel hareket hesaplamalarında adım adım işlemler yapıldığında sonuca rahatlıkla ulaşılabilir."]},"beginTime":1002,"endTime":1058,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1002&ask_summarization=1"},{"index":11,"title":"Bağıl Hareket Kavramı","list":{"type":"unordered","items":["Bağıl hareket, farklı referans sistemlerinde hareket eden hareketlerin birbirine göre hareketidir.","Bağıl harekette iki önemli durum vardır: gözlenen (hareket eden) ve gözlemci (hareketi gözlemleyen).","Aynı referans sisteminde olan gözlemci ve gözlenen için hareket aynı görünür, farklı referans sistemlerinde ise farklı görünür."]},"beginTime":1058,"endTime":1125,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1058&ask_summarization=1"},{"index":12,"title":"Bağıl Hareket Örnekleri","list":{"type":"unordered","items":["Kaykay üzerinde hareket eden bir kişi, elindeki topu yukarı aşağı fırlattığında sadece yukarı aşağı hareket ettiğini görür çünkü hepsi aynı referans sisteminde hareket eder.","Dışarıda duran bir gözlemci, kaykay üzerindeki hareketi ileriye doğru bir atış hareketi olarak görür çünkü farklı referans sistemlerinde hareket ederler.","Bağıl hız formülü, v_gözlenen - v_gözlemci şeklinde hesaplanır ve bu formül genellikle aynı düzlemde hareket eden sistemler için kullanılır."]},"beginTime":1125,"endTime":1313,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1125&ask_summarization=1"},{"index":13,"title":"Bağıl Hareket Hızları","list":{"type":"unordered","items":["Bağıl hareket problemlerinde önemli nokta, gözlemci ve gözlenen sistemlerin hangi yönde hareket ettiği belirlemektir.","İki sistemin birbirine doğru hareket ettiği durumda, bağıl hız v₂ + v₁ formülüyle hesaplanır ve gözlemci, karşıdan gelen arabayı ikisinin hızının toplamı ile kendisine geliyormuş gibi görür.","Eğer sistemler farklı yönlerde hareket ediyorsa, aynı formül kullanılarak vektörel olarak toplama ve çıkarma yapılarak hız bulunabilir."]},"beginTime":1318,"endTime":1443,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1318&ask_summarization=1"},{"index":14,"title":"Farklı Referans Sistemlerinde Bağıl Hareket","list":{"type":"unordered","items":["Gözlemci ve gözlenen farklı referans sistemlerinde (örneğin, gözlemci dünya üzerinde, gözlenen araba içinde) bağıl hız hesaplaması için farklı bir denklem kullanılır.","Bu durumda, bağıl hız = referans sisteminin hızı + gözlenen sistemin hızı formülü kullanılır ve artı/eksi işaretleri yön bilgisini ifade eder.","Örneğin, gözlemci dünya üzerinde, gözlenen araba içinde ve araba v hızıyla doğu yönünde hareket ediyorsa, gözlemci gözlenen kişiyi arabanın hızıyla (v) aynı yönde hareket ediyormuş gibi görür."]},"beginTime":1443,"endTime":1698,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1443&ask_summarization=1"},{"index":15,"title":"İkinci Bağıl Hareket Senaryosu","list":{"type":"unordered","items":["İkinci senaryoda, gözlemci dünya üzerinde, gözlenen ise otobüs veya tren gibi bir araçta ve aynı yönde v₂ hızıyla hareket ediyorsa, bağıl hız hesaplaması için farklı bir formül kullanılır.","Bu durumda, bağıl hız = referans sisteminin hızı + gözlenen sistemin hızı formülü kullanılır ve artı/eksi işaretleri yön bilgisini ifade eder.","Örneğin, gözlemci dünya üzerinde, gözlenen vagon içinde ve vagon v₁ hızıyla hareket ediyorsa, gözlemci gözlenen kişiyi v₁ + v₂ hızıyla aynı yönde hareket ediyormuş gibi görür."]},"beginTime":1698,"endTime":1800,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1698&ask_summarization=1"},{"index":16,"title":"Bağıl Hareket Problemi Çözümü","list":{"type":"unordered","items":["Bir araba ve içindeki çocuk örneğinde, gözlemci arabadan ters yönde giderken, çocuğun dışarıdaki gözlemcinin gördüğü hızı hesaplamak için bağıl hız formülü kullanılır.","Formül: v = v_referans sistemi + v_gözlenen, burada pozitif yön x ekseninde kabul edilir.","Çocuğun dışarıdaki gözlemcinin gördüğü hızı hesapladığımızda, sonuç pozitif çıkarsa çocuk pozitif yönde (x yönünde) hareket etmektedir."]},"beginTime":1802,"endTime":1935,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1802&ask_summarization=1"},{"index":17,"title":"Nehir Problemi Çözümü","list":{"type":"unordered","items":["Bir nehir doğu yönünde 0,75 m/s sabit akış hızına sahipken, bir öğrenci nehrin belli bir noktasından akıntıya karşı 200 metrelik yolu yüzer ve başlangıç noktasına geri döner.","Öğrenci durgun suda 1,25 m/s hıza sahipse, nehir içerisindeki gidiş dönüş süresini bulmak için sabit hızlı denklem (Δx = v × t) kullanılır.","Bağıl hız hesaplanırken, gözlemci (nehir) pozitif yönde (0,75 m/s) hareket ederken, gözlenen (öğrenci) akıntıya karşı (negatif yönde) 1,25 m/s hızla yüzer, sonuç -0,50 m/s olarak bulunur.","Gidiş süresi 200 m = -0,50 × t denkleminden 400 saniye olarak hesaplanır."]},"beginTime":1935,"endTime":2234,"href":"/video/preview/8833368921389618131?parent-reqid=1773913942649149-17071915390401143967-balancer-l7leveler-kubr-yp-klg-219-BAL&text=physicsme&t=1935&ask_summarization=1"},{"index":18,"title":"Dönüş Hareketi Hesaplaması","list":{"type":"unordered","items":["İkinci senaryoda çocuk, bir noktadan diğerine doğru hareket edip sonra 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